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\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(P=\dfrac{250}{\left(14,0625-7,5625\right):0,52}\)
\(P=\dfrac{250}{6,5:0,52}=\dfrac{250}{12,5}=20\)
\(P=\dfrac{\left(17.005-4.505\right)^2+125\cdot\dfrac{3}{4}}{\left(3.75^2-2.75^2\right):0.52}\)
\(=\dfrac{\left(12.5\right)^2+12.5\cdot\dfrac{15}{2}}{\left(3.75+2.75\right):0.52}\)
\(=\dfrac{12.5\left(12.5+7.5\right)}{6.5:0.52}=\dfrac{12.5\cdot20}{12.5}=20\)
\(P=\dfrac{\left(17.005-4.505\right)^2+93.75}{\left[\left(0.22+3.53\right)^2-\left(2.75\right)^2\right]:0,52}\)
\(=\dfrac{156.25+93.75}{6.5:0.52}=\dfrac{250}{12.5}=20\)
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:052}\)
\(=\dfrac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{250}{\left(14,0625-75625\right):0,52}\)
\(=\dfrac{250}{6,5:0,52}\)
\(=\dfrac{250}{12,5}=20\)
Vây P = 20
P/s: Lấy máy tính tính lại xem đúng k chứ nhiều số rắc rối quá
\(P=\dfrac{\left(17,005-4,505\right)^2+93,75}{\left\{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]\right\}:0,52}\)
\(=\dfrac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{156,25+93.75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\dfrac{250}{\left(14,0625-7,5625\right):0,52}\)
\(=\dfrac{250}{6,5:0,52}=\dfrac{250}{12,5}=20\)
Giải:
\(P=\frac{\left(17,005-4,505\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
\(=\frac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
\(=\frac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
\(=\frac{250}{\left(14,0625-7,5625\right):0,52}\)
\(=\frac{250}{6,5:0,52}\)
\(=\frac{250}{12,5}\)
\(=20\)
Ta có:A=\(\left[\frac{1}{2}+\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^3+\left(\frac{1}{2}\right)^4+....+\left(\frac{1}{2}\right)^{99}\right]\)
\(\frac{1}{2}A\)=\(\frac{1}{2}\)\(\left[\frac{1}{2}+\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^3+\left(\frac{1}{4}\right)^4+....+\left(\frac{1}{2}\right)^{99}\right]\)
\(\frac{1}{2}A\)=\(\left[\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^3+\left(\frac{1}{2}\right)^4+\left(\frac{1}{2}\right)^5+...+\left(\frac{1}{2}\right)^{100}\right]\)
\(\frac{1}{2}A-A\)=\(\left[\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^3+\left(\frac{1}{2}\right)^4+\left(\frac{1}{2}\right)^5+...+\left(\frac{1}{2}\right)^{100}\right]\)-\(\left[\frac{1}{2}+\left(\frac{1}{2}\right)^2+\left(\frac{1}{2}\right)^3+\left(\frac{1}{2}\right)^4+....+\left(\frac{1}{2}\right)^{99}\right]\)
\(-\frac{1}{2}A\)=\(\left(\frac{1}{2}^{100}\right)-\frac{1}{2}\)
\(-\frac{1}{2}A\)=\(-\frac{1}{2}\)
A=\(-\frac{1}{2}:\left(-\frac{1}{2}\right)\)
A=1
Chúc bạn học tốt!
\(A=\frac{\left(81,624:4,8-4,505\right)^2+125.0,75}{\left\{\left[\left(0,44\right)^2:0,88+3,53\right]^2-\left(2,75\right)^2\right\}:0,52}\)
= \(\frac{\left(17,005-4,005\right)^2+93,75}{\left[\left(0,1936:0,88+3,53\right)^2-7,5625\right]:0,52}\)
= \(\frac{\left(12,5\right)^2+93,75}{\left[\left(0,22+3,53\right)^2-7,5625\right]:0,52}\)
= \(\frac{156,25+93,75}{\left[\left(3,75\right)^2-7,5625\right]:0,52}\)
= \(\frac{250}{\left(14,0625-7,5625\right):0,52}\)
= \(\frac{250}{12,5}=20\)
Kết quả gọn ha.Mình tính sao sao í mà được số thập phân