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Bài làm
\(D=\frac{6}{3,5}+\frac{6}{5.7}+...+\frac{6}{21.23}\)
\(D=3.\left(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{21.23}\right)\)
\(D=3.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{21}-\frac{1}{23}\right)\)
\(D=3.\left(\frac{1}{3}-\frac{1}{23}\right)\)
\(D=3.\frac{20}{69}\)
\(D=\frac{20}{23}\)
Học tốt
Bài làm
\(D=\frac{6}{3.5}+\frac{6}{5.7}+...+\frac{6}{21.23}\)
\(D=3.\left(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{21.23}\right)\)
\(D=3.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{21}-\frac{1}{23}\right)\)
\(D=3.\left(\frac{1}{3}-\frac{1}{23}\right)\)
\(D=3.\frac{20}{69}\)
\(D=\frac{20}{23}\)
\(E=\frac{20}{11.13}+\frac{20}{13.15}+\frac{20}{15.17}+...+\frac{20}{53.55}\)
\(E=10.\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{53.55}\right)\)
\(E=10.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)\)
\(E=10.\left(\frac{1}{11}-\frac{1}{55}\right)\)
\(E=10.\frac{4}{55}\)
\(E=\frac{8}{11}\)
\(G=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{9900}\)
\(G=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+...+\frac{1}{99.100}\)
\(G=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\)
\(G=\frac{1}{1}-\frac{1}{100}\)
\(G=\frac{99}{100}\)
Nhớ k cho m nha
a)\(\frac{-1}{3}< \frac{x}{24}< \frac{-1}{4}\)
=>\(\frac{-8}{24}< \frac{x}{24}< \frac{-6}{24}\)
=>x=-7
Vậy x=-7
b)Bn làm tương tự nha
Chúc bn học tốt
=> 11/12 + 1/12 - 1/23 + 1/23 - 1/34 + ..... + 1/89 - 1/100 + x = 5/3
=> 11/12 + 1/12 - 1/100 + x = 5/3
=> 99/100 + x = 5/3
=> x = 5/3 - 99/100 = 203/300
Tk mk nha
lm theo bài này :1/x + 1/y = 1/4
<=> 4/x + 4/y = 1
<=> 4x + 4y = xy
<=> xy - 4x - 4y + 16 = 16
<=> (x-4).(y-4) = 16
1/x + y/2 = 5/8
1/x + 4y/8 = 5/8
1/x = 5/8 - 4y/8
1/x = 5 - 4y/8
Vì y là số nguyên dương nên 4y là số nguyên dương. B( 4y ) < 5.
Vậy B( 4y ) = { 4 }
4y = 4
y = 4 : 4
y = 1
Ta có :
1/x = 5-4/8
1/x = 1/8
Vậy x = 8
Đ/S : y = 1
x = 8
\(A=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{29}+\frac{1}{30}\)
\(A=\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{20}\right)+\left(\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+...+\frac{1}{30}\right)\)
\(A>\left(\frac{1}{20}+\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}\right)+\left(\frac{1}{30}+\frac{1}{30}+\frac{1}{30}+...+\frac{1}{30}\right)\)
\(A>10.\frac{1}{20}+10.\frac{1}{30}\)
\(A>\frac{1}{2}+\frac{1}{3}\)
\(A>\frac{5}{6}\)
Vậy \(A>\frac{5}{6}\)
Chúc bạn học tốt ~
\(A=\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{29}+\frac{1}{30}\)
\(A=\left(\frac{1}{11}+\frac{1}{12}+\frac{1}{13}+...+\frac{1}{20}\right)+\left(\frac{1}{21}+\frac{1}{22}+\frac{1}{23}+...+\frac{1}{30}\right)\)
\(A>\left(\frac{1}{20}+\frac{1}{20}+\frac{1}{20}+...+\frac{1}{20}\right)+\left(\frac{1}{30}+\frac{1}{30}+\frac{1}{30}+...+\frac{1}{30}\right)\)
\(A>\frac{1}{20}\times10+\frac{1}{30}\times10\)
\(A>\frac{1}{2}+\frac{1}{3}\)
\(A>\frac{5}{6}\)
Vậy \(A>\frac{5}{6}\)
D = $\frac{2}{3}.\frac{5}{6}.\frac{9}{10}. ... .\frac{799}{780}$
= $\frac{2.2}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}. ... .\frac{38.41}{39.40}$
= $\frac{2.2}{2.3}.\frac{2.3. ... .38}{3.4. ... 39}.\frac{5.6. ... .41}{4.5. ... .40}$
= $\frac{2}{3}.\frac{2}{39}.\frac{41}{4}$
= $\frac{41}{3.39}$
D = \(\frac{2}{3}.\frac{5}{6}.\frac{9}{10}.\frac{14}{15}.....\frac{779}{780}\)
= \(\frac{2.2}{2.3}.\frac{2.5}{3.4}.\frac{3.6}{4.5}.\frac{4.7}{5.6}.....\frac{38.41}{39.40}\)
= \(\frac{2}{3}.\frac{2.3.4....38}{3.4.5....39}.\frac{5.6.7.....41}{4.5.6.....40}\)
= \(\frac{2}{3}.\frac{2}{39}.\frac{41}{4}\)
= \(\frac{41}{117}\)
1/4+2/5+6/8+2/15+6/7
=(1/4+6/8)+(2/5+2/15)+6/7
=(2/8+6/8)+(6/15+2/15)+6/7
=1+8/15+6/7
=1+56/105+90/105
=1+146/105
=1+105/105+41/105
=1+1+41/105
=2+41/105
=2 và 41/105
2 và 41/105 là hỗn số nha
1/4+2/5+6/8+2/15+6/7
Ta có:
1/4=1-3/4
6/8=3/4
2/15=2/3*5=1/3-1/5
==> 1-3/4+2/5+3/4+1/3-1/5+6/7
=1+1/3+1/5+6/7
=(105+35+21+90)/105
=251/105.
lấy 1 - 1/9900= 9899/9900 chi có thế thôi
9899/9900 thui