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1.
a) \(\frac{16}{24}-\frac{1}{3}=\frac{16}{24}-\frac{8}{24}=\)\(\frac{8}{24}=\frac{1}{3}\)
b) \(\frac{4}{5}-\frac{12}{60}=\frac{48}{60}-\frac{12}{60}=\frac{36}{60}=\frac{9}{15}\)
3.
a)\(\frac{17}{6}-\frac{2}{6}=\frac{17-2}{6}=\frac{15}{6}\)
b) \(\frac{16}{15}-\frac{11}{15}=\frac{16-11}{15}=\frac{5}{15}=\frac{1}{3}\)
c) \(\frac{19}{12}-\frac{13}{12}=\frac{19-13}{12}=\frac{6}{12}=\frac{1}{2}\)
a) \(\frac{2}{5}+\frac{9}{15}=\frac{2}{5}+\frac{3}{5}=\frac{5}{5}=1\)
b) \(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{7}{6}\)
c) \(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{12}{8}=\frac{3}{2}\)
d) \(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{19}{42}\)
a) \(\frac{2}{5}+\frac{9}{15}\)=\(\frac{2}{5}+\frac{3}{5}=\frac{2+3}{5}=1\)
b)\(\frac{15}{45}+\frac{25}{30}=\frac{1}{3}+\frac{5}{6}=\frac{2}{6}+\frac{5}{6}=\frac{2+5}{6}=\frac{7}{6}\)
c)\(\frac{28}{32}+\frac{45}{72}=\frac{7}{8}+\frac{5}{8}=\frac{7+5}{8}=\frac{12}{8}=\frac{3}{2}\)
d)\(\frac{8}{28}+\frac{5}{30}=\frac{2}{7}+\frac{1}{6}=\frac{12}{42}+\frac{7}{42}=\frac{12+7}{42}=\frac{19}{42}\)
\(a,\frac{8}{15}+\frac{2}{3}=\frac{8+10}{15}=\frac{18}{15}=\frac{6}{5}\)
\(b,\frac{3}{7}+\frac{4}{8}=\frac{24+28}{56}=\frac{62}{56}=\frac{31}{28}\)
a) \(\frac{8}{15}+\frac{2}{3}=\frac{8}{15}+\frac{10}{15}=\frac{8+10}{15}=\frac{18}{15}=\frac{6}{5}\)
b) \(\frac{3}{7}+\frac{4}{8}=\frac{24}{56}+\frac{28}{56}=\frac{24+28}{56}=\frac{52}{56}=\frac{13}{14}\)
Làm câu a)
2/3+4/3x3/6=2/3+2/3=4/3
Làm câu b)
9/24=3/8
Làm câu c)
355/985+355/985=710/985
Vậy.................
\(a,\frac{2}{5}+\frac{1}{6}+\frac{3}{5}\)
\(=\left(\frac{2}{5}+\frac{3}{5}\right)+\frac{1}{6}\)
\(=1+\frac{1}{6}\)
\(=\frac{7}{6}\)
Hok tốt!~
\(\frac{2}{3}+\frac{3}{9}+\frac{7}{5}\)
\(=\frac{2}{3}+\frac{1}{3}+\frac{7}{5}\)
\(=\frac{10}{15}+\frac{5}{15}+\frac{21}{15}\)
\(=\frac{36}{15}\)
\(=\frac{12}{5}\)
\(\frac{2}{3}+\frac{3}{9}+\frac{7}{5}\)
=\(\frac{2}{3}+\frac{1}{3}+\frac{7}{5}\)
=\(\frac{7}{5}+\frac{2}{3}+\frac{1}{3}\)
=\(\frac{3}{3}+\frac{7}{5}\)
\(=1+\frac{7}{5}\)
=\(\frac{12}{5}\)