\(\sqrt{8,1}\times\sqrt{250}\)

\(\sqrt{2,5}\times\...">

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\(\sqrt{8,1}.\sqrt{250}\)

\(=\sqrt{81}.\sqrt{25}\)

\(=9.5\)

\(=45\)

\(\sqrt{2,5}.\sqrt{360}\)

\(=\sqrt{25}.\sqrt{36}\)

\(=5.6\)

\(=30\)

\(\sqrt{\frac{-49}{-121}}=\sqrt{\frac{49}{121}}\)

\(=\frac{\sqrt{49}}{\sqrt{121}}\)

\(=\frac{7}{11}\)

\(\sqrt{\frac{-36}{-169}}=\sqrt{\frac{36}{169}}\)

\(=\frac{\sqrt{36}}{\sqrt{169}}=\frac{6}{13}\)

26 tháng 7 2018

\(\sqrt{2,5}.\sqrt{360}\)

\(=\sqrt{25}.\sqrt{36}\)

\(=5.6\)

\(=30\)

\(\sqrt{\frac{-49}{-121}}\)

\(=\sqrt{\frac{49}{121}}\)

\(=\frac{\sqrt{49}}{\sqrt{121}}=\frac{7}{11}\)

a) Ta có: \(\sqrt{45}:\sqrt{80}\)

\(=\sqrt{\frac{45}{80}}=\sqrt{\frac{9}{20}}\)

\(=\frac{3}{2\sqrt{5}}\)

b) Ta có: \(\sqrt{\frac{3}{15}}:\sqrt{\frac{36}{45}}\)

\(=\sqrt{\frac{1}{5}:\frac{4}{5}}\)

\(=\sqrt{\frac{1}{5}\cdot\frac{5}{4}}\)

\(=\sqrt{\frac{1}{4}}=\frac{1}{2}\)

c) Ta có: \(\sqrt{\frac{72}{9}}:\sqrt{8}\)

\(=\frac{\sqrt{8}}{\sqrt{8}}=1\)

d) Ta có: \(\sqrt{\frac{288}{169}}:\sqrt{\frac{8}{225}}\)

\(=\sqrt{\frac{288}{169}:\frac{8}{225}}\)

\(=\sqrt{\frac{288}{169}\cdot\frac{225}{8}}\)

\(=\sqrt{\frac{8100}{169}}=\frac{90}{13}\)

13 tháng 6 2018

\(a)\) \(A=\sqrt{49}-2\sqrt{36}+3\sqrt{4}\)

\(A=7-2.6+3.2\)

\(A=7-12+6\)

\(A=1\)

\(b)\) \(B=\frac{1}{2}\sqrt{\frac{144}{225}}-7\sqrt{100}+4\sqrt{\frac{361}{400}}\)

\(B=\frac{1}{2}.\frac{4}{5}-7.10+4.\frac{19}{20}\)

\(B=\frac{2}{5}-70+\frac{19}{5}\)

\(B=\frac{-329}{5}\)

Chúc bạn học tốt ~ 

21 tháng 8 2017

Đề có sai ko bn?Phương Phan Thùy

31 tháng 3 2017

a) \(\sqrt{16}\cdot\sqrt{25}+\sqrt{196}:\sqrt{49}\)

\(=\sqrt{16\cdot25}+\sqrt{196:49}\)

\(=20+2=22\)

b) \(36:\sqrt{2\cdot3^2\cdot18}-\sqrt{169}\)

\(=36:\sqrt{324}-\sqrt{169}\)

\(=36:18-13=2-13=-11\)

c) \(\sqrt{\sqrt{81}}\)

\(=\sqrt{9}=3\)

d) \(\sqrt{3^2+4^2}\)

\(=\sqrt{9+16}=\sqrt{25}=5\)

7 tháng 6 2017

a) \(\sqrt{16}.\sqrt{25}+\sqrt{196}\div\sqrt{49}\)

\(=4.5+14:7\)

\(=20+2=22\)

b) \(36:\sqrt{2.3^2.18}-\sqrt{169}\)

\(=36:18-13=-11\)

c) \(\sqrt{\sqrt{81}}=\sqrt{9}=3\)

d) \(\sqrt{3^2+4^2}=\sqrt{25}=5\)

25 tháng 8 2017

tu lam di cau nao kho thi hoi hoi vay ko ai tra loi cho dau

cau e)

\(A=\sqrt{2+\sqrt{3}}.\sqrt{2-\sqrt{3}}\)(suy ra A>=0)

\(A^2=\left(2+\sqrt{3}\right)\left(2-\sqrt{3}\right)\)

\(A^2=1\)

A=1

(bai toan co nhieu cach)

cau m)

\(=\frac{\sqrt{\left(\sqrt{3}+\sqrt{2}\right)^2}+\sqrt{\left(\sqrt{5}-\sqrt{3}\right)^2}}{\sqrt{\left(\sqrt{5}+\sqrt{2}\right)^2}}\)

\(=\frac{\sqrt{3}+\sqrt{2}+\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{2}}\)

\(=1\)

cau G)

\(=\frac{5\sqrt{7}}{\sqrt{35}}-\frac{7\sqrt{5}}{\sqrt{35}}+\frac{2\sqrt{70}}{\sqrt{35}}\)

\(=\frac{5}{\sqrt{5}}-\frac{7}{\sqrt{7}}+2\sqrt{2}\)

\(=\sqrt{5}-\sqrt{7}+2\sqrt{2}\)

26 tháng 11 2016

 căn bậc 3 x căn bận 12=6

cân bậc 12 chia căn bâc 3 =2