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125(28+72)-25(3^2.4+64)
=125.100-25(9.4+64)
=125.100-25.(36+64)
=125.100-25.100
=12500-2500
=10000
a) 1252 . 82 - (24)2 + 59 : 1252
=(125 . 8)2 - 24.2 + 59 : (53)2
= 10002 - 28 + 59 : 56
= 1000000 - 256 + 53
= 999744 + 125
= 999869
b) Mình ko viết đầu bài đâu nhé
=(75 : 5)2 + (25 . 4)4 - 33 . 52
= 152 + 1004 - 27 . 25
= 15. 15 + 100 . 100 . 100 . 100 - 675
= 225 + 100000000 - 675
= 100000000 - (675 - 225)
= 100000000 - 450
= 99999550
=
a) \(9\cdot2^3-72:2^2\)
\(=72-18=54\)
b) \(125\cdot26+5^3\cdot32+25\cdot42\cdot5\)
\(=125\cdot26+125\cdot32+125\cdot42\)
\(=125\cdot\left(26+32+42\right)=125\cdot100=12500\)
c) \(5871:\left[928-\left(247-82\right)\cdot5\right]+2012^0\)
\(=5871:\left[928-\left(247-82\right)\cdot5\right]+1\)
\(=5871:\left(928-165\cdot5\right)+1\)
\(=5871:103+1\)
\(=58\)
d) \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=-100\)
a, \(9.2^3-\frac{72}{2^2}=9.8-\frac{72}{4}=72-18=54\)
b, \(125.26+5^3.32+25.42.5\)
\(=125.26+125.32+125.42\)
\(=125.\left(26+32+42\right)\)
\(=125.100\)
\(=12500\)
c, \(\frac{5871}{\left[928-\left(247-82\right).5\right]}+2012^0\)
\(=\frac{5871}{103}+1\)
\(=57+1\)
\(=58\)
d, \(2012+78+\left(-178\right)+\left(-2012\right)\)
\(=\left[2012+\left(-2012\right)\right]+\left[78+\left(-178\right)\right]\)
\(=0+100\)
\(=100\)
a) \(\left(2^3.9^4+9^3.45\right):\left(9^2.10-9^2\right)\)
=\(\left(2^3.9^4+9^3.9.5\right):9^2\left(10-1\right)\)
= \(\left(8-9^4+9^4.5\right):9^2.9\)
=\(9^4\left(8-5\right):9^3\)
=\(9^4.3:9^3\)
=\(9^4:9^3.3\)
=\(9.3\)
=\(27\)
18 mu 3 chia 9 mu 3 bang 18 mu 3 phan ra bang (9.2) mu 3 bang 9 mu 3 nhan 2 mu 3 9 mu 3 chia cho nhau bang 1 nhan 2 mu 3 =8
b 125 mu 3 = 25 mu 9 chia 25 mu 4 = 25 mu 5
c
a) $125^3:25^4=(5^3)^3:(5^2)^4=5^9:5^8=5^1$
$16^4:4^2=(4^2)^4:4^2=4^8:4^2=4^6$
$27^8:9^4=(3^3)^8:(3^2)^4=3^{24}:3^8=3^{16}$
$125^5:25^3=(5^3)^5:(5^2)^3=5^{15}:5^6=5^9$
$4^{14}:5^{28}=(2^2)^{14}:5^{28}=2^{28}:5^{28}=(\dfrac{2}{5})^{28}$
b) $12^n:2^{2n}=12^n:(2^2)^n=12^n:4^n=3^n$
$64^4.16^5.4^{20}=(4^3)^4.(4^2)^5.4^{20}=4^{12}.4^{10}.4^{20}=4^{42}$
\(B=\frac{125^2\cdot72^3:9^3}{4^3\cdot25^5\cdot5^5}=\frac{\left(5^3\right)^2\cdot\left(2^3\cdot3^2\right):\left(3^2\right)^3}{\left(2^2\right)^3\cdot\left(5^2\right)^5\cdot5^5}=\frac{5^6\cdot2^3\cdot3^2:3^6}{2^6\cdot5^{10}\cdot5^5}\)
tỰ TÍNH