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bài 1b)
\(8\frac{1}{14}-6\frac37\)
C1:\(\frac{113}{14}-\frac{45}{7}\) =\(\frac{113}{14}-\frac{90}{14}=\frac{23}{14}\)
C2:\(8\frac{1}{14}-6\frac37=\left(8-6\right)+\left(\frac{1}{14}-\frac37\right)=2+\left(\frac{1}{14}-\frac{6}{14}\right)\)
\(=2+\frac{-5}{14}=\frac{28}{14}-\frac{5}{14}=\frac{23}{14}\)
bài 1 c)\(7-3\frac67\)
C1:\(\) \(7-3\frac67=7-\frac{27}{7}=\frac{49}{7}-\frac{27}{7}=\frac{22}{7}\)
C2:\(7-3\frac67=\left(7-3\right)-\frac67=4-\frac67=\frac{28}{7}-\frac67=\frac{22}{7}\)
a )
\(\frac{-4}{9}.\frac{1}{3}-\frac{4}{9}.\frac{5}{6}+\frac{3}{7}.\frac{4}{9}\)
\(=\frac{4}{9}.\left(-\frac{1}{3}-\frac{5}{6}+\frac{3}{7}\right)\)
\(=\frac{4}{9}.\left(-\frac{14}{42}-\frac{35}{42}+\frac{18}{42}\right)\)
\(=\frac{4}{9}.\frac{-31}{42}\)
\(=-\frac{62}{189}\)
b )
\(\frac{2}{3}:\frac{3}{7}-\frac{2}{3}:\frac{4}{3}+\frac{2}{3}:\frac{1}{21}\)
\(=\frac{2}{3}.\frac{7}{3}-\frac{2}{3}.\frac{3}{4}+\frac{2}{3}.21\)
\(=\frac{14}{9}-\frac{1}{2}+14\)
\(=\frac{28}{18}-\frac{9}{18}+14\)
\(=\frac{19}{18}+14\)
\(=1+14+\frac{1}{18}\)
\(=15\frac{1}{18}\)
c )
\(\left(5\frac{1}{3}+3\frac{2}{3}\right)-4\frac{1}{3}\)
\(=\left(5+3-4\right)+\left(\frac{1}{3}+\frac{2}{3}-\frac{1}{3}\right)\)
\(=4\frac{2}{3}\)
\(=\frac{14}{3}\)
a) \(-\frac{4}{9}\cdot\frac{1}{3}-\frac{4}{9}\cdot\frac{5}{6}+\frac{3}{7}\cdot\frac{4}{9}\)
\(=\left(-\frac{4}{9}\right)\cdot\frac{1}{3}+\left(-\frac{4}{9}\right)\cdot\frac{5}{6}-\left(-\frac{4}{9}\right)\cdot\frac{3}{7}\)
\(=\left(-\frac{4}{9}\right)\left(\frac{1}{3}+\frac{5}{6}-\frac{3}{7}\right)\)
\(=\left(-\frac{4}{9}\right)\cdot\frac{31}{42}=-\frac{62}{189}\)
\(=\frac{3}{200}:\frac{3}{5}+\frac{3}{2}\left(\frac{4}{25}-\frac{2}{5}\right)-\frac{1}{25}.\left(\frac{7}{4}:\frac{7}{5}-\frac{5}{2}\right)\)
\(=\frac{3.5}{200.3}+\frac{3}{2}\left(\frac{4}{25}-\frac{2.5}{25}\right)-\frac{1}{25}\left(\frac{7.5}{4.7}-\frac{5}{2}\right)\)
\(=\frac{1}{40}+\frac{3}{2}\left(\frac{-6}{25}\right)-\frac{1}{25}\left(\frac{5}{4}-\frac{10}{4}\right)\)
\(=\frac{1}{40}-\frac{9}{25}+\frac{1}{20}\)
\(=\frac{1.5}{40.5}-\frac{9.8}{25.8}+\frac{1.10}{20.10}\)
\(=\frac{5-72+10}{200}=\frac{-57}{200}\)
a) \(\left(-0,75+\frac{1}{2}\right):\frac{4}{3}\)
\(=\frac{-1}{4}:\frac{4}{3}\)
\(=\frac{-3}{16}\)
b) \(\frac{5}{9}.\frac{2}{7}+\frac{5}{9}.\frac{5}{7}-\frac{8}{3}\)
\(=\frac{5}{9}.\left(\frac{2}{7}+\frac{5}{7}\right)-\frac{8}{3}\)
\(=\frac{5}{9}.1-\frac{8}{3}\)
\(=\frac{-19}{9}\)
c) \(7,5.1\frac{3}{4}-6\frac{2}{5}\)
\(=\frac{15}{2}.\frac{7}{4}-\frac{32}{5}\)
\(=\frac{269}{40}\)
\(\frac{3}{4}+\frac{5}{6}-\left(\frac{3}{4}+\frac{1}{2}\right)=\frac{3}{4}+\frac{5}{6}-\frac{3}{4}-\frac{1}{2}\)
\(=\frac{5}{6}-\frac{3}{6}\)
=\(\frac{2}{6}\)
=\(\frac{1}{3}\)
Chúc bạn học tốt+-*/
\(\frac{3}{4}+\frac{5}{6}-\frac{3}{4}-\frac{1}{2}=\left(\frac{3}{4}-\frac{3}{4}\right)-\left(\frac{5}{6}+\frac{1}{2}\right)=0-\frac{4}{3}=-\frac{4}{3}\)
Thực hiện phép tính
a ) \(\frac{2}{5}+\frac{-1}{6}-\frac{3}{4}-\frac{-2}{3}\)
= \(\frac{2}{5}+\frac{-1}{6}+\frac{-3}{4}+\frac{2}{3}\)
= \(\left(\frac{2}{5}+\frac{-3}{4}\right)+\left(\frac{-1}{6}+\frac{2}{3}\right)\)
= \(\left(\frac{8}{20}+\frac{-15}{20}\right)+\left(\frac{-1}{6}+\frac{4}{6}\right)\)
= \(\left(\frac{8+\left(-15\right)}{20}\right)+\left(\frac{\left(-1\right)+4}{6}\right)\)
= \(\frac{-7}{20}+\frac{1}{2}\)
= \(\frac{-7}{20}+\frac{10}{20}=\frac{\left(7\right)+10}{20}=\frac{3}{20}\)
tk mk nha
đang âm rất nhiều rồi , giúp nha !!!!!
\(2,5-\frac{2}{3}.\frac{3}{4}+3\frac{1}{6}\)
\(=\frac{5}{2}-\frac{2}{3}.\frac{3}{4}+\frac{19}{6}\)
\(=\frac{3}{4}.\frac{10}{3}-\frac{2}{3}.\frac{3}{4}-\frac{3}{4}.\frac{38}{9}\)
\(=\frac{3}{4}.\left(\frac{10}{3}-\frac{2}{3}-\frac{38}{9}\right)\)
\(=\frac{3}{4}.\left(\frac{30}{9}-\frac{6}{9}-\frac{38}{9}\right)\)
\(=\frac{3}{4}.\frac{-14}{9}\)
\(=-\frac{7}{6}\)
\(2,5-\frac{2}{3}\times\frac{3}{4}+3\frac{1}{6}\)
\(=\frac{5}{2}-\frac{1}{2}+3+\frac{1}{6}\)
\(=2+3+\frac{1}{6}\)
\(=5\frac{1}{6}\)
Chúc bn học tốt !!!