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Gọi \(A=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{22.25}\)
\(\Leftrightarrow\)\(3A=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{22.25}\)
\(\Leftrightarrow\)\(3A=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)
\(\Leftrightarrow\)\(3A=1-\frac{1}{25}\)
\(\Leftrightarrow\)\(3A=\frac{24}{25}\)
\(\Leftrightarrow\)\(A=\frac{24}{25}:3\)
\(\Leftrightarrow\)\(A=\frac{24}{25}.\frac{1}{3}\)
\(\Leftrightarrow\)\(A=\frac{8}{25}\)
Vậy \(A=\frac{8}{25}\)
Đặt \(C=\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}\)
\(\Rightarrow3C=\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+....+\frac{3}{22.25}\)
\(\Rightarrow3C=1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{22}-\frac{1}{25}\)
\(\Rightarrow3C=1-\frac{1}{25}=\frac{24}{25}\)
\(\Rightarrow C=\frac{24}{25}:3=\frac{8}{25}\)
Vậy \(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{22.25}=\frac{8}{24}\)
\(A=\frac{1}{5.9}+\frac{1}{9.13}+\frac{1}{13.17}+........+\frac{1}{100.104}\)
\(=\frac{1}{4}.\left(\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+.......+\frac{4}{100.104}\right)\)
\(=\frac{1}{4}.\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+.......+\frac{1}{100}-\frac{1}{104}\right)\)
\(=\frac{1}{4}.\left(\frac{1}{5}-\frac{1}{104}\right)\)
\(=\frac{1}{4}.\frac{99}{520}=\frac{99}{2080}\)
\(\frac{2011x2011x20102010-2010x2010x20112011}{2011x2010x20092009}\)
\(=\frac{2011x2011x2010x10001-2010x2010x2011x10001}{2011x2010x2009x10001}\)
\(=\frac{2011x2010x10001\left(2011-2010\right)}{2011x2010x2009x10001}\)
\(=\frac{2011x2010x10001}{2011x2010x2009x10001}\)
= 1/2009
\(\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{19.20}\)
\(=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{20}\)
\(=\frac{1}{5}-\frac{1}{20}\)
\(=\frac{4}{20}-\frac{1}{20}=\frac{3}{20}\)
NHƯ NÀY NÈ:
\(\frac{36}{6}\cdot\frac{36}{7}=\frac{36\cdot36}{6\cdot7}=\frac{36\cdot6\cdot6}{6\cdot7}=\frac{36\cdot6}{7}=\frac{216}{7}=30\frac{6}{7}\)
MK KHÔNG BIẾT CÓ ĐÚNG KO.
K MK NHA. (NẾU ĐÚNG ^_^)
gạch tất cả số 5, 9, 13
là bằng 4.x/1 + 4.x/17
rồi gợi ý thế thôi nhé
\(\frac{4.x}{1.5}+\frac{4.x}{5.9}+\frac{4.x}{9.13}+\frac{4.x}{13.17}=16\)
\(x.\left(\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}\right)=16\)
\(x.\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}\right)=16\)
\(x.\left(1-\frac{1}{17}\right)=16\)
\(x.\frac{16}{17}=16\Rightarrow x=16:\frac{16}{17}=16.\frac{17}{16}\)
\(\Rightarrow x=17\)
\(\frac{135,79.399+79,8.420,86+1995.355,0076}{3+5+7+...+39}\)
Ta tách phân số trên thành 2 phần thì ta được :
- Phần mẫu số :
3 + 5 + 7 + .... + 39
= ( 39 + 3 ) x [ ( 39 - 3 ) : 2 + 1 ] : 2
= 42 x 19 : 2
= ( 42 : 2 ) x 19
= 21 x 19
= 19 x 20 + 19
= 380 + 19
= 399
- Phần tử số :
135,79 . 399 + 79,8 . 420,86 + 1995 . 355,0076
= 54180,21 + 33584,628 + 708240,162
= 54180,21 + 741824,79
= 796005
\(\Rightarrow\frac{135,79.399+79,8.420,86+1995.355,0076}{3+5+7+.....+39}=\frac{796005}{399}=1995\)
\(\frac{68\cdot35-27}{34\cdot68+41}\)
\(=\frac{68\left(34+1\right)-27}{34\cdot68+41}\)
\(=\frac{68\cdot34+68-27}{34\cdot68+41}\)
\(=\frac{1+41}{1+41}\)
\(=1\)
\(\frac{2006\times125+100}{125\times200-880}=\frac{250850}{24120}\)
2006 x 125 + 100/125 x 200 - 880