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Bài 1:
Theo đề, ta có: \(x_1\cdot y_1=x_2\cdot y_2\)
\(\Leftrightarrow\dfrac{y_1}{5}=\dfrac{y_2}{2}\)
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{y_1}{5}=\dfrac{y_2}{2}=\dfrac{3y_1+4y_2}{3\cdot5+4\cdot2}=\dfrac{46}{23}=2\)
Do đó: \(y_1=10\)
\(k=xy=10\cdot2=20\)
=>y=20/x
a)(-2,5 x 0,38 x 0,4) - [0,125 x 3,15 x (-8)]
=[(-2,5 x 0,4) x 0,38] - [(-8 x 0,125) x 3,15]
=(-1 x 0,38) - (-1 x 3,15)
=(-0,38) - (-3,15)
=2,77
a) ( - 6,37 x 0,4 ) x 2,5
=-6,37 x (0,4 x 2,5)
=-6,37 x 1
=-6,37
b) ( -0,125 ) x ( -5,3 ) x 8
=(-0,125 x 8) x (-5,3)
=-1 x (-5,3)
=5,3
c) ( -2,5 ) x ( -4 ) x ( -7,9 )
=[(-2,5) x (-4)] x (-7,9)
=10 x (-7,9)
=-79
a)(-6,37x0,4)x2,5=-6,37x(0,4x2,5)=-6,37x1=-6,37
b)(-0,125)x(-5,3)x8=(-0,125x8)x(-5,3)=-1x(-5,3)=5,3
c)(-2,5)x(-4)x(-7,9)=[(-2,5)x(-4)]x(-7,9)=10x(-7,9)=-79
a: \(=\left(1.25\right)^{16}\cdot8^{16}\cdot8=8\cdot10^{16}\)
b: \(=\left(\dfrac{5}{2}\right)^{13}\cdot4^{13}\cdot4^2=10^{13}\cdot4^2\)
c: \(=\left(0.25\right)^4\cdot8^4\cdot8^2=2^4\cdot8^2=64\cdot16=1024\)
d: \(=\left(\dfrac{1}{2}\right)^{15}\cdot2^{18}=2^3=8\)
e: \(=\left(\dfrac{1}{3}\cdot6\right)^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=2^7\cdot\left(\dfrac{1}{2}\right)^7\cdot\dfrac{1}{2}=\dfrac{1}{2}\)
a)
\(\left(-6,37.0,4\right)2,5=\left(-6,37\right).\left(\frac{2}{5}.\frac{5}{2}\right)=1.\left(-6,37\right)=-6,37\)
b)
\(\left(-0,125\right)\left(-5,3\right).8=\left[\left(-\frac{1}{8}\right).8\right]\left(-5,3\right)=\left(-1\right)\left(-5,3\right)=5,3\)
c)
\(\left(-2,5\right).\left(-4\right).\left(-7,9\right)=\left[\left(-\frac{5}{2}\right).\left(-4\right)\right]\left(-7,9\right)=10.\left(-7,9\right)=-79\)
d)
\(\left(-0,375\right).4\frac{1}{3}.\left(-2\right)^3=\left(-\frac{3}{8}\right).\frac{12}{3}.\left(-8\right)=12\)
Bài 1:
\(\left(-0,125\right)\times7,9\times80\)
\(=\left(-0,9875\right)\times80\)
\(=79.\)
\(\left(0,125\right)\times1\times0,25\times8\times\left(-4\right)\)
\(=0,125\times0,25\times8\times\left(-4\right)\)
\(=0,03125\times8\times\left(-4\right)\)
\(=0,25\times\left(-4\right)\)
\(=\left(-1\right).\)
Bài 2:
\(x+\frac{8}{3}^2=\frac{1}{9}\)
\(x+16=\frac{1}{9}\)
\(x=\frac{1}{9}-16.MSC=9\)
\(x=\frac{1}{9}-\frac{144}{9}\)
\(x=\frac{-143}{9}.\)
a) \(=\left(\frac{-337}{100}:\frac{40}{100}\right).\frac{250}{100}=\frac{-337}{40}.\frac{40}{16}=-\frac{337}{16}\)
b) \(=\frac{-1}{8}.\left(-5,3\right).8=\frac{-1}{8}.8.\left(-5,3\right)=-1.\left(-5,3\right)=5,3\)
c) \(=10.\left(-7,9\right)=-79\)
d) \(=-\frac{3}{8}.\frac{13}{3}.\left(-8\right)=\left[-\frac{3}{8}.\left(-8\right)\right].\frac{13}{3}=3.\frac{13}{3}=13\)
a)(-3,37:0,4).2,5
=(-8,425).2,5
=-21,0625
b) (-0,125) . (-5,3) . 8
=(-0,125).8.(-5,3)
=(-1).(-5,3)
=5,3
c)(-2,5).(-4).(-7,9)
=10.(-7,9)
=-79
d)(-0,375).\(4\frac{1}{3}\).(-2)3
=(-0,375).(-2)3.\(4\frac{1}{3}\)
=3.\(\frac{13}{3}\)
=13
a, 30,24 + 30,24 + 30,24 + 30,24 x 7 - 30,24 : 0,1
= 30,24 x 3 + 30,24 x 7 - 30,24 : 0,1
= 30,24 x 10 - 30,24 : 0,1
= 30,24 x 10 - 30,24 x 10
= 0
b, 2 giờ 30 phút x 8 + 2,5 giờ x 3 - 150 phút
= 2,5 giờ x 8 + 2,5 giờ x 3 - 150 phút
= 2,5 giờ x 8 + 2,5 giờ x 3 - 2,5 giờ
= 2,5 giờ x 10
= 25 giờ
c, 1/2 : 0,5 - 1/4 : 0,25 + 1/8 : 0,125 - 1/10 : 0,1
= 1/2 x 2 + 1/4 x 4 + 1/8 x 8 - 1/10 x 10
= 1 + 1 + 1 - 1
= 2