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Bài 1: 1/3+1/9+1/27+1/81+1/243+1/729
Đặt:
A = 1 + 1/3 + 1/9 + 1/27 + 1/81 + 1/243 + 1/729
Nhân A với 3 ta có:
\(Ax3=3+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\)
\(\Rightarrow Ax3-S=3-\frac{1}{243}\)
\(\Rightarrow2A=\frac{2186}{729}\)
\(\Rightarrow A=\frac{2186}{729}:2\)
\(\Rightarrow A=\frac{1093}{729}\)
a) = \(\frac{127}{96}\)
b) = \(\frac{255}{256}\)
c) Mik bỏ nha
d) = \(\frac{1023}{512}\)
e) = \(\frac{2343}{625}\)
a)8 3/5..<....8,8
b)29 1/10....>..29,02
c)18 3/20..=....18,15
d)5 1/25..>...5,2
a) 12/17 + 21/25 = 657/425
b) 4 - 205/811 = 3039/811
c) 12 . 21/25 = 252/25
d) 4 : 205/811 = 205/3244
a) 12/17 + 21/25 = 657/425
b) 4 - 205/811 = 3039/811
c) 12 . 21/25 = 252/25
d) 4 : 205/811 = 205/3244
2) \(\frac{3}{1\times3}+\frac{3}{3\times5}+\frac{3}{5\times7}+...+\frac{3}{99\times101}+\frac{3}{101\times103}\)
\(=\frac{3}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+\frac{2}{5\times7}+...+\frac{2}{101\times103}\right)\)
\(=\frac{3}{2}\times\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{101}-\frac{1}{103}\right)\)
\(=\frac{3}{2}\times\left(1-\frac{1}{103}\right)\)
\(=\frac{3}{2}\times\frac{101}{103}\)
\(=\frac{303}{206}\)
(1/2+2/3+3/4+4/5+...+122/123+123/124).(125-5.25)
=(1/2+2/3+3/4+4/5+...+122/123+123/124).(125-125)
=(1/2+2/3+3/4+4/5+...+122/123+123/124).0=0
a) \(\frac{7}{8}\) - \(\frac{1}{3}\) = \(\frac{21}{24}\) - \(\frac{8}{24}\) = \(\frac{13}{24}\)
\(\frac{8}{9}\) + \(\frac{2}{5}\) = \(\frac{40}{45}\) + \(\frac{18}{45}\) = \(\frac{58}{45}\)
\(\frac{3}{10}\) x \(\frac{1}{6}\) = \(\frac{3\times1}{10\times6}\) = \(\frac{3}{60}\) = \(\frac{1}{20}\)
\(\frac{8}{9}\) : \(\frac{3}{7}\) = \(\frac{8}{9}\) x \(\frac{7}{3}\) = \(\frac{56}{27}\)
b) Đổi hỗn số ra phân số rồi làm tương tự câu a)