K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

\(\frac{2016}{2017}\)\(\frac{2017}{2018}\)\(\frac{2019}{2020}\)=\(\frac{504}{505}\)

đ/s:\(\frac{504}{505}\)

31 tháng 8 2017

\(\frac{2016}{2017}\cdot\frac{2017}{2018}\cdot\frac{2018}{2019}\cdot\frac{2019}{2020}=\frac{504}{505}\)

24 tháng 8 2019

Ta có: \(\frac{x-2019}{2018}+\frac{x-2018}{2017}=\frac{x-2017}{2016}+\frac{x-2016}{2015}\)

\(\Leftrightarrow\left(\frac{x-2019}{2018}+1\right)+\left(\frac{x-2018}{2017}+1\right)=\left(\frac{x-2017}{2016}+1\right)+\left(\frac{x-2016}{2015}+1\right)\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}=\frac{x-1}{2016}+\frac{x-1}{2015}\)

\(\Leftrightarrow\frac{x-1}{2018}+\frac{x-1}{2017}-\frac{x-1}{2016}-\frac{x-1}{2015}=0\)

\(\Leftrightarrow\left(x-1\right)\left(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\right)=0\)

\(\Leftrightarrow x-1=0\)( vì \(\frac{1}{2018}+\frac{1}{2017}-\frac{1}{2016}-\frac{1}{2015}\ne0\))

\(\Leftrightarrow x=1\)

Vạy x=1

4 tháng 6 2018

\(\frac{2016\cdot2017+2015}{2018\cdot2017-2019}\)

\(\frac{2016\cdot2017+2015}{\left(2016+2\right)\cdot2017-2019}\)

\(\frac{2016\cdot2017+2015}{2016\cdot2017+2\cdot2017-2019}\)

\(\frac{2016\cdot2017+2015}{2016\cdot2017+4034-2019}\)

\(\frac{2016\cdot2017+2015}{2016\cdot2017-2015}\)

\(1\)

30 tháng 7 2018

\(\frac{2016\times2017+2015}{2018\times2017-2019}\)

\(=\frac{2016\times2017+2015}{\left(2016+2\right)\times2017-2019}\)

\(=\frac{2016\times2017+2015}{2016\times2017+2\times2017-2019}\)

\(=\frac{2016\times2017+2015}{2016\times2017+4034-2019}\)

\(=\frac{2016\times2017+2015}{2016\times2017+2015}\)

\(=1\)

16 tháng 7 2018

32 x 27 + 148 x 34 + 16 x 94

= ( 32 x 27 + 16 x 94 ) + 74 * 2 * 34

= 32 ( 27 + 47 ) + 74 x 68

= 32 x 74 + 74 x 68

= ( 32 + 68 ) x 74

= 100 * 74

= 7400

\(\frac{2017\cdot2013-2017}{4034\cdot1006+2007}\)

\(=\frac{2017\cdot\left(2013-1\right)}{2017\cdot\left(2012+1\right)}\)

\(=\frac{2012}{2013}\)

16 tháng 7 2018

a, 32×27+148×34+16×94

=32×27+74×2×34+16×2×47

=32×27+74×68+32×47

=32×(27+47)+74×68

=32×74+74×68

=74×(32+68)

=72×100

=7200

b, 2017×2013-2017 / 4034×1006+2017

=2017×(2013-1) / 2017×2×1006+2017

=2017×2012 / 2017×2012+2017

=1/2017

8 tháng 6 2019

#)Giải :

\(Q=2+\frac{2016}{2017+2018+2019}+\frac{2017}{2017+2018+2019}+\frac{2018}{2017+2018+2019}\)

Ta thấy : \(2>\frac{2016}{2017};2>\frac{2017}{2018};2>\frac{2018}{2019}\left(1\right)\)

\(\frac{2016}{2017+2018+2019}< \frac{2016}{2017}\left(2\right)\)

\(\frac{2017}{2017+2018+2019}< \frac{2017}{2018}\left(3\right)\)

\(\frac{2018}{2017+2018+2019}< \frac{2018}{2019}\left(4\right)\)

Từ (1) (2) (3) (4) \(\Rightarrow P>Q\)

5 tháng 8 2021

2019 + 2017 + 2015 + .... + 1003 + 1001 - 2018 - 2016 - 2014 -.... - 1002 - 1000

=(2019-2018)+(2017-2016)+....+(1001-1000)

=1+1+...+1

= 510

21 tháng 5 2023

Bài làm:

(2019-2018+2017-.....-2) x (100 -25x2x2)

=(2019-2018+2017-.....-2) x (100 -25x4)

=(2019-2018+2017-.....-2) x 0

=0

*like phát

21 tháng 5 2023

=(2019 – 2018 + 2017 – 2016 + 2015 + ....... – 4 + 3 – 2) x(100-25x4)

=(2019 – 2018 + 2017 – 2016 + 2015 + ....... – 4 + 3 – 2) x(100-100)

=(2019 – 2018 + 2017 – 2016 + 2015 + ....... – 4 + 3 – 2) x0

=0

15 tháng 7 2017

\(\frac{2018\cdot2016+2021}{2017\cdot2018+3}\)

\(=\frac{2018\cdot2016+2021}{2016\cdot2018+2018\cdot1+3}\)

\(=\frac{2018\cdot2016+2021}{2016\cdot2018+2021}\)

\(=1\)