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\(118^2-118.36+18^2\)
\(=118^2-2.118.18+18^2\)
\(=\left(118-18\right)^2\)
\(=100^2=10000\)
\(118^2-118.36+18^2\)
=\(118^2-2.118.18+18^2\)
=\(\left(118-18\right)^2\)
=\(100^2\)
a. 134^2 - 68.134 + 34^2 = ( 134 - 34 ) ^2 = 100^2 = 10000
b. 9^8.2^8 - ( 18^4 - 1 )(18^4 + 1 ) = 18^8 - 18^8 + 1 = 1
c. 100^2 - 99^2 + 98^2 - 97^2 + ... + 2^2 - 1
=( 100 - 99 )( 100 + 99 ) + ( 98 - 97 )( 98 + 97 ) + ... + ( 2 - 1 )( 2 + 1 )
= 100 + 99 + 98 + 97 + ... + 2 + 1
=( 100 + 1 ).100:2 = 5050
a) \(82^2-18^2=\left(82-18\right)\left(82+18\right)=64.100=6400\)
b) \(26^2+52.24+24^2=26^2+2.26.24+24^2=\left(26+24\right)^2=50^2=2500\)
c) \(\dfrac{93^3+78^3}{171}-93.78=\dfrac{\left(93+78\right)\left(93^2-93.78+73^2\right)}{171}-93.78\)
\(=\dfrac{171\left(93^2-93.78+73^2\right)}{171}-93.78\)
\(=93^2-93.78+73^2-93.78\)
\(=93^2-2.93.78+73^2=\left(93-73\right)^2=20^2=400\)
Ta có : 642 + 128.36 + 362
= 642 + 2.64.36 + 362
= (64 + 36)2
= 1002
= 10000
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Ta có : 642 + 128.36 + 362
= 642 + 2.64.36 + 362
= (64 + 36)2
= 1002
= 10000
a: \(=1995^2-\left(1995^2-1\right)=1995^2-1995^2+1=1\)
b: \(=18^8-18^8+1=1\)
c: \(=\left(163+37\right)^2=200^2=40000\)
\(205^2-95^2=\)
\(=\left(205-95\right)\left(205+95\right)\)
\(=200.300\)
\(=60000\)
\(36^2-14^2=\)
\(=\left(36-14\right)\left(36+14\right)\)
\(=22.50\)
\(=1100\)
\(205^2-95^2=\left(205-95\right)\left(205+95\right)=110.300=33000\)
\(36^2-14^2=\left(36-14\right)\left(36+14\right)=22.50=1100\)
\(97^2-3^2=\left(97-3\right)\left(97+3\right)=94.100=9400\)
\(=82^2-2.18.82+18^2=\left(82-18\right)^2=64^2=...\)
Để xem, \(64^2=2^{12}=4096\)