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a, 2.4.5.15.19
=(2.5).(4.15).19
=10.60.19
=60.19
=1140
b, 28.87+13.28
=28.(87+13)
=28.100
=2800
đúng ý ta
a) = 23.52,3.(20-1) = 11.400
b) = 28(87+13) = 28.100 = 2800
\(\left(\frac{2}{9}+\frac{7}{9}\right)+\left(\frac{1}{5}+\frac{4}{5}\right)=1+1=2\)\(2\)
\(\frac{19}{37}+1-\frac{19}{37}=\left(\frac{19}{37}-\frac{19}{37}\right)+1=1\)
B = 15 - 37 + 59 - 211 + 713 - 916 - 713 + 212 - 59 + 37 - 15 - 15
B = (15 - 15) + (37 - 37) + (59 - 59) + (212 - 211) + (713 - 713) - 916 - 15
B = 0 + 0 + 0 + 1 + 0 + 0 - 916 - 15
B = 1 - 916 - 15
B = -915 - 15
B = -930
a) 4.52-3.23 = 22.52-3.23 = 22.(52-3.2) =22.(25-6) = 4.19 = 76
b) 28.76 + 13.28 + 9.2
= 28. (76 + 13) + 18
= 28. 89 + 18
= 2492 + 18
= 2510
c) 1024: ( 17 .25+15.25)
= 210 : [25.(17+15)]
= 210: [25. 32]
= 210: [25.25)
= 210:210
= 1
a) 4.52-3.23
=22.52-3.23
=22.(25-6)
=4.11
=44
b) 28.76+13.28+9.2
=28.(76+13)+9.2
=28.89+9.2
=2.(1246+9)
=2.1255
=2510
c) 1024:(17.25+15.25)
=1024:25.(17+15)
=1024:32.32
=1
\(\frac{37}{45}-\left(\frac{7}{45}-\frac{36}{108}-\frac{5}{13}\right)=\frac{37}{45}-\frac{7}{45}+\frac{36}{108}+\frac{5}{13}.\)
\(=\left(\frac{37}{45}-\frac{7}{45}\right)+\left(\frac{36}{108}+\frac{5}{13}\right)\)
\(=\frac{2}{3}+\frac{28}{39}\)
\(=\frac{18}{13}\)
\((\frac{37}{45}-\frac{7}{45})+(\frac{36}{108}-\frac{5}{13})\)
=\(\frac{2}{3}+-\frac{2}{39}\)=\(\frac{8}{13}\)
13.28+72.13+37 + 37.99 = 13.(28+72) + 37.(1+99) = 13.100 + 37.100 =1300 +3700 = 5000