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a)\(\frac{864.48-432.96}{864.48+432}\)
=\(\frac{864.48-432.2.48}{864.48+432}\)
=\(\frac{864.48-864.48}{864.48+432}\)
=\(\frac{0}{864.48+432}\)
=0
864x48-432x96/864x48+432=2x432x48-432x48x2/864x48+432=0/864x48+432=0.
**** mình nha
\(\frac{864.48-432.96}{864.48.432}=\frac{864.48-432.2.48}{864.48.432}=\frac{864.48-864.48}{864.48.432}\)
\(=\frac{0}{864.48.432}=0\)
ta có tử số= 864.48-432.96=432.2.48-432.96=432.96-432.96=0
vậy phân thức đã cho có giá trị bằng 0
y=\(\frac{2006x2005-1}{2004x2006+2005}=\frac{2006x2005-1}{\left(2005-1\right)x2006+2005}=\frac{2006x2005-1}{2005x2006-2006+2005}=\frac{2006x2005-1}{2005x2006-1}=1\)
\(\frac{2005x2004-1}{2003x2005+2004}\)=\(\frac{4018019}{4018019}\)= 1
\(\frac{2005\cdot2004-1}{2003\cdot2005+2004}\)
\(=\frac{2005\cdot\left(2003+1\right)-1}{2003\cdot2005+2004}\)
\(=\frac{2005\cdot2003+2005-1}{2003\cdot2005+2004}\)
\(=\frac{2005\cdot2003+2004}{2003\cdot2005+2004}\)
\(=1\)
2005 x 2004 - 1 / 2003 × 2005 + 2004
= 2005 × (2003 + 1) - 1 / 2003 × 2005 + 2004
= 2005 × 2003 + (2005 - 1) / 2003 × 2005 + 2004
= 2005 × 2003 + 2004 / 2003 × 2005 + 2004
= 1
2006 * ( 2005 + 2 ) - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 2006 * 2 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 4012 - 2593 / 2005 * 2006 + 1419
2006 * 2005 + 1419 / 2005 * 2006 + 1419 = 1
k cho tui nha