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a) \(25^2-15^2=\left(25-15\right)\left(25+15\right)\)
= 400
b) \(87^2+73^2-27^2-13^2\)
\(\Leftrightarrow\left(87^2-13^2\right)\)+\(\left(73^2-27^2\right)\)
\(\Leftrightarrow\left(87+13\right)\left(87-13\right)+\left(73+27\right)\left(73-27\right)\)
\(\Leftrightarrow7400+4600=12000\)
a) 3x3-2x2+2 chia x+1= 3x2-5x+5 dư -3 b) -3 chia hết x+1 vậy chon x =2
1)
a) \(-7x\left(3x-2\right)\)
\(=-21x^2+14x\)
b) \(87^2+26.87+13^2\)
\(=87^2+2.87.13+13^2\)
\(=\left(87+13\right)^2\)
\(=100^2\)
\(=10000\)
2)
a) \(x^2-25\)
\(=x^2-5^2\)
\(=\left(x-5\right)\left(x+5\right)\)
b) \(3x\left(x+5\right)-2x-10=0\)
\(\Leftrightarrow3x\left(x+5\right)-\left(2x-10\right)=0\)
\(\Leftrightarrow3x\left(x+5\right)-2\left(x-5\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(3x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+5=0\\3x-2=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\3x=2\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=\dfrac{2}{3}\end{matrix}\right.\)
Vậy..........
3)
a) \(A:B=\left(3x^3-2x^2+2\right):\left(x+1\right)\)
Vậy \(\left(3x^3-2x^2+2\right):\left(x+1\right)=\left(3x^2-5x-5\right)+7\)
b)
Để \(A⋮B\Rightarrow7⋮\left(x+1\right)\)
\(\Rightarrow\left(x+1\right)\in U\left(7\right)=\left\{-1;1-7;7\right\}\)
Vì x là số nguyên nên x=0 ; x=6 thì \(A⋮B\)
Giải:
1). \(25^2-15^2\)
\(=\left(25-15\right)\left(25+15\right)\)
\(=10.40\)
\(=400\)
2). \(87^2+73^2-27^2-13^2\)
\(=\left(87^2-13^2\right)+\left(73^2-27^2\right)\)
\(=\left(87-13\right)\left(87+13\right)+\left(73-27\right)\left(73+27\right)\)
\(=74.100+46.100\)
\(=100\left(74+46\right)\)
\(=100.120\)
\(=12000\)
Chúc bạn học tốt!!!
a, \(5\left(m+3x\right)\left(x+1\right)-4\left(1+2x\right)=80\)
Phương trình nhận \(x=2\)làm nghiệm nên :
\(5\left(m+3.2\right)\left(2+1\right)-4\left(1+2.2\right)=80\)
\(\Leftrightarrow15m+90-20=80\)
\(\Leftrightarrow15m=80+20-90\)
\(\Leftrightarrow15m=10\Leftrightarrow m=1,5\)
....
b, \(3\left(2x+m\right)\left(3x+2\right)-2\left(3x+1\right)^2=43\)
Phương trình nhận \(x=1\)làm nghiệm nên :
\(3\left(2.1+m\right)\left(3.1+2\right)-2\left(3.1+1\right)^2=43\)
\(\Leftrightarrow30+15m-32=43\)
\(\Leftrightarrow15m=43+32-30\)
\(\Leftrightarrow15m=45\Leftrightarrow m=3\)
....
\(\frac{315-x}{101}+\frac{313-x}{103}+\frac{311-x}{105}+\frac{309-x}{107}+4=0\)
\(\Leftrightarrow\frac{315-x}{101}+1+\frac{313-x}{103}+1+\frac{311-x}{105}+1+\frac{309-x}{107}+1=0\)
\(\Leftrightarrow\frac{416-x}{101}+\frac{416-x}{103}+\frac{416-x}{105}+\frac{416-x}{107}=0\)
\(\Leftrightarrow\left(416-x\right)\left(\frac{1}{101}+\frac{1}{103}+\frac{1}{105}+\frac{1}{107}\right)=0\)
\(\Leftrightarrow416-x=0\)
\(\Leftrightarrow x=416\)
a) 5(m + 3x)(x + 1) - 4(1 + 2x) = 80
Phương trình có nghiệm x = 2:
5(m + 3.2)(2 + 1) - 4(1 + 2.2) = 80
<=> 5(m + 6).3 - 4.5 = 80
<=> 15(m + 6) - 4.5 = 80
<=> 15(m + 6) - 20 = 80
<=> 15(m + 6) = 80 + 20
<=> 15(m + 6) = 100
<=> m + 6 = 100 : 15
<=> m + 6 = 20/3
<=> m = 20/3 - 6
<=> m = 2/3
b) 3(2x + m)(3x + 2) - 2(3x + 1)2 = 43
Phương trình có nghiệm x = 1:
3(2.1 + m)(3.1 + 2) - 2(3.1 + 1)2 = 43
<=> 3(2 + m).5 - 2.16 = 43
<=> 15(2 + m) - 32 = 43
<=> 15(2 + m) = 43 + 32
<=> 15(2 + m) = 75
<=> 2 + m = 75 : 15
<=> 2 + m = 5
<=> m = 5 - 2
<=> m = 3
a) 262 + 52.24 + 242
= 262 + 2.26.24 + 242
= ( 26 + 24 )2
= 502 = 2500
b) 30032 - 32
= ( 3003 + 3 ) ( 3003 - 3 )
= 3006 . 3000 = 9018000
c) 872 + 732 - 272 -132
= ( 872 - 132 ) + ( 732 - 272 )
= [ ( 87 + 13 )( 87- 13 )] + [ ( 73 - 27 )( 73 + 27 ) ]
= ( 100 . 74 ) + ( 46 . 100 )
= 7400 + 4600 = 12000
d)792 - 79.58 + 292
= 792 - 2.79.29 + 292
= ( 79 - 29 )2
= 502 = 2500
a) 262 + 52 . 24 + 242 = 262 + 2 . 26 . 24 + 242
= ( 26 + 24 )2
= 502
= 2500
b) 30032 - 32 = ( 3003 - 3 ) . ( 3003 + 3 )
= 3000. 3006
= 9018000
c) 872 + 732 - 272 - 132 = ( 872 - 272 ) + ( 732 - 132 )
= ( 87 - 27 ) . ( 87 + 27 ) + ( 73 - 13 ) . ( 73+13)
= 60 . 114 + 60 . 86
= 60 . ( 114 + 86 )
= 60 . 200
= 12000
d) 792 - 79 . 58 + 292 = 792 - 2 . 79 . 29 + 292
= ( 79 - 29 )2
= 502
= 2500
bài 1
a(x+y)2-(x-y)2
=[(x+y)-(x-y)][(x+y)+(x-y)]
=(x+y-x+y)(x+y+x-y)
=2y.2x
b,(3x+1)2-(x+1)2
=[(3x+1)-(x+1)][(3x+1)+(x+1)]
=(3x+1-x-1)(3x+1+x+1)
=2x.(4x+2)
4x.(x+10
bài 2
x3-0,25x=0
=>x(x2-0,25)=0
=>x=0 hoặc x2-0,25=0
=> x=0 hoặc x=\(\pm0,5\)
a, \(27^2+13^2+2.37.13=\left(27+13\right)^2\)
b, \(87^2+57^2-174.67=\left(87-57\right)^2\)
c, \(x^2-2xy+2y^2+2y+1\)
\(=\left(x^2-2xy+y^2\right)+\left(y^2+2y+1\right)\)
\(=\left(x-y\right)^2+\left(y+1\right)^2\)
d, \(4x^2-12x-y^2+2y+1\)
\(=4\left(x^2-3x\right)-\left(y^2-2y+1\right)+2\)
\(=4\left(x^2-\dfrac{3}{2}.x.2+\dfrac{9}{4}-\dfrac{9}{4}\right)-\left(y-1\right)^2+2\)
\(=\left(x-\dfrac{3}{2}\right)^2-\left(y-1\right)^2-7\)
\(a,x^2-y^2=\left(x+y\right)\left(x-y\right)=\left(87+13\right)\left(87-13\right)=100.74=7400\)\(b,x^3-3x^2+3x-1=\left(x-1\right)^3=\left(101-1\right)^3=100^3=1000000\)c,\(x^3+9x^2+27x+27=\left(x+3\right)^3=\left(97+3\right)^3=1000000\)
a) x2 - y2 = (x+y)(x-y)
Thay x=87; y=13 có:
(87+13)(87-13) = 100.74 = 7400
b)x3-3x2+3x-1 = x3 - 3x2.1+ 3x .12 -13 = (x-1)3
Thay x=101 có:
(101-1)3 =1003 =1000000
c)x3+9x2+27x+27= x3 +3x2.1+3x.12+33= (x+3)3
Thay x=97 có:
(97+3)3= 1003=1000000
d. \(\left(x-3y\right)\left(3x^2+y^2+5xy\right)\)
\(=3x^3+xy^2+5x^2y-9x^2y-3y^3-15xy^2\)
\(=3x^3-14xy^2-4x^2y-3y^3\)
Bài 2:
a. \(x^2-y^2-5x+5y\)
\(=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)
\(=\left(x+y-5\right)\left(x-y\right)\)
b. \(x^3-x^2-4x^2+8x-4\)
\(=x^2\left(x-1\right)-4\left(x^2-2x+1\right)\)
\(=x^2\left(x-1\right)-4\left(x-1\right)^2\)
\(=\left(x-1\right)\left[x^2-4\left(x-1\right)\right]\)
\(=\left(x-1\right)\left(x^2-4x+4\right)\)
\(=\left(x-1\right)\left(x-2\right)^2\)
Bài 3:
\(87^2+26.87+13^2\)
\(=\left(87+ 13\right)^2\)
\(=100^2\)
\(=10000\)
Bài 1:
a. \(3x^2\left(5x^2-4x+3\right)\)
\(=15x^4-12x^3+9x^2\)
b. \(-5xy\left(3x^2y-5xy-y^2\right)\)
\(=-15x^3y^2+25x^2y^2+5xy^3\)
c. \(\left(5x^2-4x\right)\left(x-3\right)\)
\(=5x^3-19x^2-4x^2+12x\)
Giải:
a) \(313^2+2.87.313+87^2\)
\(=\left(313+87\right)^2\)
\(=400^2\)
\(=160000\)
Vậy ...
b) \(313^2-2.313.13+13^2\)
\(=\left(313-13\right)^2\)
\(=300^2\)
\(=90000\)
Vậy ...
a, 3132+2.87.313+872
Áp dụng hằng đẳng thức đáng nhớ!!!( hằng đẳng thức số 1)
=(313+87)2=4002=160 000
KL:.....
b, Cũng áp dụng hằng đẳng thức đáng nhớ( hằng đẳng thức số 2)
3132-2.313.13+132=(313-13)2=3002=90 000
KL:........
Chúc bạn học zui