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62 . 58 = (60 + 2)(60 - 2) = 60\(^2\) - 2\(^2\) = 3600 - 4 = 3596
199\(^2\) = (200 -1)\(^2\) = 200\(^2\) - 2.200.1 + 1\(^2\) = 40 000 - 400 + 1 = 39601
499\(^2\) = (500 - 1)\(^2\) = 500\(^2\) - 2.500.1 + 1\(^2\) = 250 000 - 1000 + 1 = 249 001
299 . 301 = (300 - 1)(300 + 1) = 300\(^2\) - 1\(^2\) = 90 000 - 1 = 89 999
Học tốt
Đúng thì k cho mk nhé
Trả lời:
+, \(62.58=\left(60+2\right)\left(60-2\right)=60^2-2^2=3600-4=3596\)
+, \(199^2=\left(200-1\right)^2=200^2-2.200.1+1^2=40000-400+1=39601\)
+, \(499^2=\left(500-1\right)^2=500^2-2.500.1+1^2=250000-1000+1=249001\)
+, \(299.301=\left(300-1\right)\left(300+1\right)=300^2-1=90000-1=89999\)
a) = 1003 2 - 2.3.1003 + 32
= (1003 - 3)2 = 10002 = 1000000
b) = 9982 + 4. (998 + 1)
= 9982 + 2.2.998 + 22
= (998 + 2)2 = 10002 = 1000000
\(\left(1+3x\right)\left(3x-1\right).2\)
\(=\left[\left(3x\right)^2-1^2\right].2\)
\(=\left(9x^2-1\right).2\)
\(=18x^2-2\)
\(36x^2+36x+9=\left(6x\right)^2+36x+3^2=\left(6x+3\right)^2\)
B=(2+1)(22+1)(24+1)(28+1)(216+1)−232
=1.(2+1)(22+1)(24+1)(28+1)(216+1)−232
=(2-1)(2+1)(22+1)(24+1)(28+1)(216+1)−232
=(22-1)(22+1)(24+1)(28+1)(216+1)−232
=(24-1)(24+1)(28+1)(216+1)−232
=(28-1)(28+1)(216+1)−232
=(216-1)(216+1)−232
=232-1-232
=-1
A = ( 2 +1 )( 2^2 + 1 )...(2^16+1) - 2^32
A = ( 2 - 1) ( 2 + 1 )(2^2 + 1) .... (2^16 + 1) - 2^32
A = (2^2 - 1) (2^2 + 1) ...(2^16 + 1) - 2^32
A =( 2^ 4 - 1)( 2^4 + 1 )( 2^8 + 1) (2^16+1) -2^32
A = ( 2^8 - 1)( 2^ 8 + 1) ( 2^ 16 + 1)- 2^32
A = ( 2^16 - 1 )( 2^16 + 1) - 2^32
A = 2^32 - 1 - 2^32
A = - 1
\(-\left(3+x\right)^2=-\left(3^2+2\cdot3\cdot x+x^2\right)\)
\(=-\left(9+6x+x^2\right)\)
\(=-x^2-6x-9\)
a)1002001
b)899,99
Nếu thấy đúng cho mình 1 k nha !
Học giỏi