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Tìm x
a,\(\frac{5}{4}x=\frac{2}{3}-1,5=\frac{2}{3}-\frac{3}{2}=\frac{4}{6}-\frac{9}{6}=\frac{-5}{6}\)
\(x=\frac{-5}{6}:\frac{5}{4}=\frac{-5}{6}.\frac{4}{5}=\frac{5.\left(-1\right).2.2}{2.3.5}=\frac{-2}{3}\)
b, \(\frac{2}{7}x-\frac{3}{2}x=\frac{-21}{4}.\frac{2}{7}=\frac{-3}{2}\)
\(x.\left(\frac{2}{7}-\frac{3}{2}\right)=\frac{-3}{2}\)
\(x.\frac{-17}{14}=\frac{-3}{2}\)
\(x=\frac{-3}{2}:\frac{-17}{14}=\frac{-3}{2}.\frac{14}{-17}=\frac{21}{17}\)
Bài 1 d)
\(1-2+3-4+5-6+...+2013\)
\(=1+\left(-2+3\right)+\left(-4+5\right)+...+\left(-2012+2013\right)\)
\(=1+1+1+...+1\left(1006s\right)\)
\(=1006.1=1006\)
a) \(\left(\left(\frac{-12}{16}\right)+\frac{7}{14}\right)-\left(\frac{1}{13}-\frac{3}{13}\right)\) \(=\left(\left(\frac{-3}{4}\right)+\frac{1}{2}\right)-\left(\frac{-2}{13}\right)\) \(=\left(\frac{-2}{8}\right)-\left(\frac{-2}{13}\right)\) \(=\left(\frac{-10}{104}\right)\) \(=\left(\frac{-5}{72}\right)\) | b) \(\frac{10}{11}+\frac{4}{11}:4-\frac{1}{8}\) \(=\frac{10}{11}+\frac{4}{11}:\frac{4}{1}-\frac{1}{8}\) \(=\frac{10}{11}+\frac{4}{11}\cdot\frac{1}{4}-\frac{1}{8}\) \(=\frac{10}{11}+\frac{1}{11}-\frac{1}{8}\) \(=\frac{11}{11}-\frac{1}{8}\) \(=1-\frac{1}{8}\) \(=\frac{7}{8}\) |
HT
\(12-(23-17)+\left|-15\right|=13-x-(23-8+\left|-9\right|)\)
\(\Rightarrow12-6+15=13-x-(23-8+9)\)
\(\Rightarrow12-6+15=13-x-24\)
\(\Rightarrow21=13-x-24\)
\(\Rightarrow x=13-24-21\)
\(\Rightarrow x=-32\)
\(\text{Vậy : }x=-32\)
12-( 23 - 17 )+ 15 = 13 -x - (23 - 8 + 9 )
12-23+17+15=13-x-23+8-9
12+17+15-23=13+8-9-x
29+15-23= 21-9 -x
44-23=12-x
21=12-x
12-x=21
x=12-21
x= -9
a)\(=\left(\frac{-3}{13}-\frac{10}{13}\right)+\left(\frac{7}{12}+\frac{5}{12}\right)\)
\(=-1+1=0\)
b)=
1) (-37) + 14 + 26 + 37
= [(-37) + 37] + 14 + 26
= 0 + 40
= 40
2) (-24) + 6 + 10 + 24
= [(-24) + 24] + 6 + 10
= 0 + 16
= 16
3) 15 + 23 + (-25) + (-23)
= 15 + (-25) + [(-23) + 23]
= -10 + 0
= -10
4) 60 + 33 + (-50) + (-33)
= 60 + (-50) + [(-33) + 33]
= 10 + 0
= 10
1:
a: \(=\dfrac{-4}{7}+\dfrac{4}{7}+\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=\dfrac{3}{7}-\dfrac{23}{34}-\dfrac{4}{5}=-\dfrac{1247}{1190}\)
b:
Sửa đề: \(\dfrac{-5}{13}+\dfrac{4}{19}+\dfrac{-8}{13}+\dfrac{15}{19}+\dfrac{45}{6}\)
\(=\dfrac{-5}{13}-\dfrac{8}{13}+\dfrac{4}{19}+\dfrac{15}{19}+\dfrac{45}{6}=\dfrac{9}{2}\)
mn giúp mik vơi mn:((
\(=\left(\frac{12}{19}.\frac{19}{12}\right).\left(-\frac{13}{17}.\frac{17}{13}\right).\frac{7}{15}\)
\(=1.-1.\frac{7}{15}\)
\(=-1.\frac{7}{15}\)
\(=-\frac{7}{15}\)