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6 - (5 - 5847) + 5 - 5847
= 6 - 5 + 5847 + 5 - 5847
= 6 + (-5 + 5) + (5847 - 5847)
= 6
\(a.35-17+1993-35-1993\\ =-17+\left(35-35\right)+\left(1993-1993\right)\\ =-17+0+0\\ =-17\\ b.-48725-\left(357-48725\right)+300\\ =-48725-357+48725+300\\ =\left(300-357\right)+\left(48725-48725\right)\\ =-57+0\\ =-57\\ c.3579-\left(49-5+3579\right)+49\\ =3579-49+5-3579+49\\ =5+\left(3579-3579\right)+\left(49-49\right)\\ =5+0+0\\ =5\)
a) \(35-17+1993-35-1993\)
\(=\left(35-35\right)+\left(1993-1993\right)-17\)
\(=-17\)
b) \(-48725-\left(357-48725\right)+300\)
\(=\left(-48725+48725\right)+\left(300-357\right)\)
\(=-57\)
c) \(3579-\left(49-5+3579\right)+49\)
\(=\left(3579-3579\right)+\left(49-49\right)+5\)
\(=5\)
35.13+35.17+65.75-65.45
=35.(13+17)+65.(75-45)
=35.30+65.30
=30.(35+65)
=30.100
=3000
\(\text{A= 1-2-3+4+5-6-7+8+9-...+1992+1993-1994}\)
\(A=\left(1-2-3+4\right)+...+\left(1989-1990-1992+1992\right)+1993-1994\)
\(A=0+0+...+0+1993-1994\)
\(A=-1\)
\(A=1-2-3+4+5-6-7+8+...+1992+1993-1994\)
\(A=\left(1-2-3+4\right)+...+\left(1989-1990-1991+1992\right)+1993-1994\)( 498 nhóm dư 2 )
\(A=0+0+...+0+1993-1994\)
\(A=1993-1994=-1\)
Vậy A = -1
\(6-\left(5-5847\right)+5-5847\)
= \(6-\left[\left(5-5\right)+\left(5847-5847\right)\right]\)
= \(6-\left[0+0\right]\)
= \(6-0\)
= \(6\)
\(35-17+1993-35-1993\)
= \(\left[\left(35-35\right)-\left(1993-1993\right)\right]-17\)
= \(0-0-17\)
= \(0-17\)
= \(\left(-17\right)\)