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a) \(\left(2\frac{5}{6}+1\frac{4}{9}\right):\left(10\frac{1}{12}-9\frac{1}{2}\right)\)
\(=\left(\frac{17}{6}+\frac{13}{9}\right):\left(\frac{121}{12}-\frac{19}{2}\right)\)
\(=\frac{77}{18}:\frac{7}{12}\)
\(=\frac{22}{3}\)
b) \(1\frac{5}{18}-\frac{5}{18}.\left(\frac{1}{15}+1\frac{1}{12}\right)\)
\(=\frac{23}{18}-\frac{5}{18}.\left(\frac{1}{15}+\frac{13}{12}\right)\)
\(=\frac{23}{18}-\frac{5}{18}.\frac{23}{20}\)
\(=\frac{23}{18}-\frac{23}{72}\)
\(=\frac{23}{24}\)
c) \(-1\frac{1}{7}.\left(9\frac{1}{2}-8,75\right):\frac{2}{7}+0,625:1\frac{2}{3}\)
\(=\frac{-8}{7}.\left(\frac{19}{2}-\frac{35}{4}\right):\frac{2}{7}+\frac{5}{8}:\frac{5}{3}\)
\(=\frac{-8}{7}.\frac{3}{4}:\frac{2}{7}+\frac{3}{8}\)
\(=\frac{-8}{7}.\frac{3}{4}.\frac{7}{2}+\frac{3}{8}\)
\(=-3+\frac{3}{8}\)
\(=\frac{-21}{8}\)
Chúc bn học tốt !!
B= (2/3-1/4+5/11):(5/12+1-7/11)
B=(8/12-3/12+5/11):(5/12+1-7/11)
B=(5/12+5/11):(5/12+1-7/11)
B=115/132:(17/12-7/11)
B=115/132:103/132
B=115/103
Mik làm mẫu cho 1 con nè. các câu sau cxn tương tự từ trái wa phải.Nều bạn tính toán kém thì cứ làm như câu mẫu trên. Mik mà làm bài này thì mik làm theo cách nhanh hơn cơ. Chúc bạn học tốt và có 1 ngày tốt lành nghen. Có j cần giúp đỡ thì cứ bảo mik
a) 2/7+-3/8+11/7+1/3+1/7+5/-8
=(2/7+11/7+1/7)+(3/8+-5/8)+1/3
=2+2+1/3
=4+1/3
=13/3
b) -3/8+12/25+5/-8+2/-5+13/25
=(-3/8+-5/8)+(12/25+13/25)+-2/5
=-1+1+-2/5
=0+-2/5
=-2/5
c)7/8+1/8*3/8+1/8*5/8
=7/8+1/8*(3/8+5/8)
=7/8+1/8*1
=7/8+1/8
=1
a) 2/7+-3/8+11/7+1/3+1/7+5/-8
=(2/7+11/7+1/7)+(3/8+-5/8)+1/3
=2+2+1/3
=4+1/3
=13/3
b) -3/8+12/25+5/-8+2/-5+13/25
=(-3/8+-5/8)+(12/25+13/25)+-2/5
=-1+1+-2/5
=0+-2/5
=-2/5
c)7/8+1/8*3/8+1/8*5/8
=7/8+1/8*(3/8+5/8)
=7/8+1/8*1
=7/8+1/8
=1
a, \(\left(\frac{17}{6}+\frac{13}{9}\right):\left(\frac{121}{12}+\frac{19}{2}\right)\)
\(=\frac{77}{18}:\frac{235}{12}=\frac{77}{18}.\frac{12}{235}=\frac{154}{705}\)
b, \(\left(\frac{19}{2}-\frac{35}{4}\right).\frac{7}{2}+\frac{5}{8}:\frac{5}{3}\)
\(\frac{3}{4}.\frac{7}{2}+\frac{5}{8}.\frac{3}{5}=\frac{21}{8}+\frac{3}{8}=\frac{24}{8}=3\)
c, \(140.\left(\frac{25}{28}+\frac{25}{36}+\frac{5}{9}\right)=140.\frac{10}{7}=200\)
d, \(\left(\frac{7}{5}-\frac{7}{25}+\frac{7}{125}-\frac{7}{625}\right):\left(1-\frac{1}{5}+\frac{1}{25}-\frac{1}{125}\right)\)
\(=\frac{728}{625}:\frac{104}{125}=\frac{728}{625}.\frac{125}{104}=\frac{7}{5}\)
c)=140[(50.10101)/(56.10101)+(50.10101)/(72.10101)+(50.10101)/(90.10101)]
=140(50/56+50/72+50/90)
=140.50(1/56+1/72+1/90)
=7000(1/7.8+1/8.9+1/9.10)
=7000(1/7-1/8+1/8-1/9+1/9-1/10)
=7000(1/7-1/10)
=7000.3/70
=300
B1
a) \(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(1-\left(x-\frac{11}{6}\right).\frac{3}{50}=0\)
\(\left(x-\frac{11}{6}\right).\frac{3}{50}=1-0\)
\(\left(x-\frac{11}{6}\right).\frac{3}{50}=1\)
\(x-\frac{11}{6}=1:\frac{3}{50}\)
\(x-\frac{11}{6}=\frac{50}{3}\)
\(x=\frac{50}{3}+\frac{11}{6}\)
\(x=\frac{37}{2}\)
b) \(\frac{3}{5}+\frac{5}{7}:x=\frac{1}{3}\)
\(\frac{5}{7}:x=\frac{1}{3}-\frac{3}{5}\)
\(\frac{5}{7}:x=-\frac{4}{15}\)
\(x=\frac{5}{7}:\left(-\frac{4}{15}\right)\)
\(x=-\frac{75}{28}\)
c) \(\left(4\frac{1}{2}-\frac{2}{5}.x\right):\frac{7}{4}=\frac{11}{9}\)
\(\left(\frac{9}{2}-\frac{2}{5}.x\right):\frac{7}{4}=\frac{11}{9}\)
\(\frac{9}{2}-\frac{2}{5}.x=\frac{11}{9}.\frac{7}{4}\)
\(\frac{9}{2}-\frac{2}{5}.x=\frac{11}{2}\)
\(\frac{2}{5}.x=\frac{9}{2}-\frac{11}{2}\)
\(\frac{2}{5}.x=-1\)
\(x=-1:\frac{2}{5}\)
\(x=-\frac{5}{2}\)
B2
a) \(\left(\frac{1}{2}+\frac{1}{3}+\frac{2}{6}\right).24:5-\frac{9}{22}:\frac{15}{121}\)
\(=\left(\frac{3}{6}+\frac{2}{6}+\frac{2}{6}\right).24:5-\frac{9}{22}.\frac{121}{15}\)
\(=\frac{7}{6}.24:5-\frac{33}{10}\)
\(=28:5-\frac{33}{10}\)
\(=\frac{28}{5}-\frac{33}{10}\)
\(=\frac{56}{10}-\frac{33}{10}\)
\(=\frac{23}{10}\)
b) \(\frac{5}{14}+\frac{18}{35}+\left(1\frac{1}{4}-\frac{5}{4}\right):\left(\frac{5}{12}\right)^2\)
\(=\frac{25}{70}+\frac{36}{70}+\left(\frac{5}{4}-\frac{5}{4}\right):\frac{25}{144}\)
\(=\frac{61}{70}+0:\frac{25}{144}\)
\(=\frac{61}{70}+0\)
\(=\frac{61}{70}\)
a)\(\frac{-5}{13}+\left(\frac{3}{5}+\frac{3}{13}-\frac{4}{10}\right)=\frac{-5}{13}-\frac{3}{5}-\frac{3}{13}+\frac{4}{10}=\left(\frac{-5}{13}-\frac{3}{13}\right)+\frac{4}{10}-\frac{3}{5}=\frac{-5-3}{13}+\left(\frac{4}{10}-\frac{6}{10}\right)=\frac{-8}{13}+\frac{-2}{10}=\frac{-80}{130}+\frac{-26}{130}=\frac{-106}{130}=\frac{-53}{65}\)