Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
ta có : \(\frac{4^{17}+64}{4^{16}+16}=\frac{2^{34}+2^6}{2^{32}+2^4}=\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}=2^2=4\)
Ta có: \(\frac{4^{17}+64}{4^{16}+16}\) = \(\frac{2^{34}+2^6}{2^{32}+2^4}\) = \(\frac{2^6\left(2^{28}+1\right)}{2^4\left(2^{28}+1\right)}\) = \(\frac{2^6}{2^4}\) = \(\frac{64}{16}\) = 4
a) (417+64):(416+16)
= (417+43):(416+42)
=420:418
=42=16
b)83:24+513:511.30
=(23)3:24+52.1
=26:24+25
=22+25
=4+25=29
c)33.48+34.42+81.42
=33.48+33.3.42+33.3.42
=33.48+33.126+33.126
=33.(48+126+126)
=27.300
=8100
\(\left(5^{1995}-5^{1993}\right):\left(5.5^{1992}\right)=\left(5^{1995}-5^{1993}\right):5^{1993}=\left(5^{1995}-5^{1993}\right)\times\frac{1}{5^{1993}}\)
\(=\left(5^{1995}\times\frac{1}{5^{1993}}\right)-\left(5^{1993}\times\frac{1}{5^{1993}}\right)=\frac{5^{1995}}{5^{1993}}-\frac{5^{1993}}{5^{1993}}=5^2-1=25-1=24\)
\(\Leftrightarrow\frac{5^{46}+5^{45}+5^{44}}{5^{39}\cdot5^5}=\frac{5^{44}\left[5^2+5+1\right]}{5^{44}}=5^2+5+1=31\)
= 3 0