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Cách 1 ở tất cả các câu: Tính bình thường như đề cho
a) Cách 2: \(\frac{5}{7}\times\frac{3}{4}+\frac{5}{7}\times\frac{1}{2}\)
b) Cách 2: \(\frac{13}{21}\times\left(\frac{5}{7}+\frac{2}{7}\right)\)
c) Cách 2: \(\frac{2}{5}\times\frac{1}{2}+\frac{2}{5}\times\frac{1}{3}\)
d) Cách 2: \(\frac{17}{21}\times\left(5+\frac{2}{5}\right)\)
Chọn đáp án đúng:
A 3\5-1\5=2\10 B 15\7-6\7=8\7 C 18\21-5\7=1\7 D 17\18-1\6=7\9
3/22 x 33/11 x 22= 3/22 x22 x 3=3 x 3=9
3/5 x 17/21 + 17/21 + 2/5= 17/21(3/5 + 2/5)= 17/21x 1=17/21
(1/2+1/3)2/5=1/2x2/5+1/3x2/5 =1/5+2/15=1/3
Bài 1:
a) 19/27+9/7+6/27+5/7+2/7
= (19/27+6/27) + (9/7+5/7+2/7)
=1 + 16/7
=23/7
b) 2/7 + 27/48 + 7/16 +45/63
= (2/7 + 45/63) + (27/48 +7/16)
= (2/7 + 5/7) + ( 9/16 + 7/16)
= 1 + 1
=2
c) Tính bằng cách bình thường
Bài 2:
6/11 + x = 1
x = 1-6/11
x = 5/11
Bài làm
a) \(\frac{19}{27}+\frac{9}{7}+\frac{6}{27}+\frac{5}{7}+\frac{2}{7}\)
\(=\frac{27}{27}+\frac{16}{7}\)
\(=1+\frac{16}{7}\)
\(=\frac{7}{7}+\frac{16}{7}\)
\(=\frac{23}{7}\)
b) \(\frac{2}{7}+\frac{27}{48}+\frac{7}{16}+\frac{45}{63}\)
\(=\left(\frac{18}{63}+\frac{45}{63}\right)+\left(\frac{27}{48}+\frac{21}{48}\right)\)
\(=\frac{63}{63}+\frac{48}{48}\)
\(=1+1\)
\(=2\)
c) \(\frac{17}{23}+\left(\frac{4}{7}-\frac{6}{13}\right)\)
\(=\frac{17}{23}+\left(\frac{52}{91}-\frac{42}{91}\right)\)
\(=\frac{17}{23}+\frac{10}{91}\)
\(=\frac{1547}{2093}+\frac{230}{2093}\)
\(=\frac{1770}{2093}\)
Bài 2
\(\frac{6}{11}+x=1\)
\(x=1-\frac{6}{11}\)
\(x=\frac{11}{11}-\frac{6}{11}=\frac{5}{11}\)
Vậy \(x=\frac{5}{11}\)
a c1 (1/2+1/3)x2/5
=5/6x2/5
=1/3
c2 1/2 x2/5+1/3x2/5
=1/5+2/15
=1/3
a) Cách 1 :
\(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}\)
= \(\left(\frac{3}{6}+\frac{2}{6}\right)\times\frac{2}{5}\)
= \(\frac{5}{6}\times\frac{2}{5}\)
= \(\frac{10}{30}=\frac{1}{3}\)
Cách 2 :
\(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}\)
= \(\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)
= \(\frac{2}{10}+\frac{2}{15}\)
= \(\frac{10}{30}=\frac{1}{3}\)
b) Cách 1 :
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
= \(\frac{51}{105}+\frac{34}{105}\)
= \(\frac{85}{105}=\frac{17}{21}\)
Cách 2 :
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
= \(\left(\frac{3}{5}+\frac{2}{5}\right)\times\frac{17}{21}\)
= \(1\times\frac{17}{21}\)
= \(\frac{17}{21}\)
Nếu đúng thì mọi người t i c k em nhé:3
CÁCH 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{35}+\frac{34}{105}=\frac{17}{21}\)
CÁCH 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{21}\times(\frac{3}{5}+\frac{2}{5})=\frac{17}{21}\times1=\frac{17}{21}\)
Cách 1:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{3\times17}{5\times21}+\frac{17\times2}{21\times5}\)
\(=\frac{17}{5\times7}+\frac{34}{105}\)
\(=\frac{17}{35}+\frac{34}{105}\)
\(=\frac{17\times3}{35\times3}+\frac{34}{105}\)
\(=\frac{51+34}{105}\)
\(=\frac{85}{105}\)
\(=\frac{17}{21}\)
Cách 2:
\(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}\)
\(=\frac{17}{21}\times\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=\frac{17}{21}\times1\)
\(=\frac{17}{21}\)
C1 : 3/5 + 17/21 + 17/21 x 2/5
= 3/5 + 17/21 x ( 1 + 2/5 )
= 3/5 + 17/21 x ( 5/5 + 2/5 )
= 3/5 + 17/21 x 7/5
= 3/5 + 17/15
= 9/15 + 17/15
= 26/15
a) C1 : \(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}=\left(\frac{3}{6}+\frac{2}{6}\right)\times\frac{2}{5}\)
\(=\frac{5}{6}\times\frac{2}{5}\)
\(=\frac{10}{30}=\frac{1}{3}\)
C2 : \(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}=\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)
\(=\frac{1}{5}+\frac{2}{15}\)
\(=\frac{3}{15}+\frac{2}{15}\)
\(=\frac{5}{15}=\frac{1}{3}\)
b) C1 : \(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{35}+\frac{34}{105}\)
\(=\frac{51}{105}+\frac{34}{105}\)
\(=\frac{85}{105}=\frac{17}{21}\)
C2 : \(\frac{3}{5}\times\frac{17}{21}+\frac{17}{21}\times\frac{2}{5}=\frac{17}{21}\times\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=\frac{17}{21}\times1=\frac{17}{21}\)
Cảm ơn Vũ Huyền nhé