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Thôi ai làm thì làm cho tôi nhờ mà tôi cũng ko cần nữa nên làm hay ko cũng được.
a) \(4^{10}.2^{30}=\left(2^2\right)^{10}.2^{30}=2^{2.10}.2^{30}=2^{20}.2^{30}=2^{20+30}=2^{50}\)
b) \(9^{25}.27^4.81^3=\left(3^2\right)^{25}.\left(3^3\right)^4.\left(3^4\right)^3=3^{3.25}.3^{3.4}.3^{4.3}=3^{75}.3^{12}.3^{12}=3^{75+12+12}=3^{99}\)
c) \(25^{50}.125^5=\left(5^2\right)^{50}.\left(5^3\right)^5=5^{2.50}.5^{3.5}=5^{100}.5^{15}=5^{100+15}=5^{115}\)
d) \(64^3.4^8.16^4=\left(4^3\right)^3.4^8.\left(4^2\right)^4=4^{3.3}.4^8.4^{2.4}=4^9.4^8.4^8=4^{9+8+8}=4^{25}\)
e) \(3^8:3^6=3^{8-6}=3^2\)
f) \(2^{10}:8^3=2^{10}:\left(2^3\right)^3=2^{10}:2^{3.3}=2^{10}:2^9=2^{10-9}=2\)
g) \(12^7:6^7=\left(12:6\right)^7=2^7\)
h_ \(21^5:81^3\)kết quả là số dư nên không tính ( đề sai )
a, \(3^4\div3^2-\left[120-\left(2^6.2+5^2.2\right)\right]\)
\(=3^2-\left\{120-\text{[}2.\left(2^6+5^2\right)\text{]}\right\}\)
\(=3^2-\left(120-2\cdot89\right)\)
\(=9--58=9+58=67\)
1. \(a,3^4:3^2-\left[120-(2^6\cdot2+5^2\cdot2)\right]\)
\(=3^2-\left[120-\left\{(2^6+5^2)\cdot2\right\}\right]\)
\(=3^2-\left[120-\left\{(64+25)\cdot2\right\}\right]\)
\(=9-\left[120-89\cdot2\right]\)
\(=9-\left[120-178\right]=9-(-58)=67\)
b, Tương tự như bài a
2.a,\(4^x\cdot5+4^2\cdot2=2^3\cdot7+56\)
\(\Leftrightarrow4^x\cdot5+16\cdot2=8\cdot7+56\)
\(\Leftrightarrow4^x\cdot5+32=56+56\)
\(\Leftrightarrow4^x\cdot5+32=112\)
\(\Leftrightarrow4^x\cdot5=80\)
\(\Leftrightarrow4^x=16\Leftrightarrow4^x=4^2\Leftrightarrow x=2\)
\(b,24:(2x-1)^3-2=1\)
\(\Leftrightarrow24:(2x-1)^3=3\)
\(\Leftrightarrow(2x-1)^3=8\)
\(\Leftrightarrow(2x-1)^3=2^3\)
\(\Leftrightarrow2x-1=2\)
Làm nốt là xong thôi
\(a,213=200+10+3\)\(=\left(2x10^2\right)\)\(+10^1\)\(+\left(3x10^0\right)\)
\(b,421=400+20+1\)\(=\left(4x10^2\right)\)\(+\left(2x10^1\right)\)\(+10^0\)
\(c,1256=1000+200+50+6\)\(=10^3\)\(+\left(2x10^2\right)\)\(+\left(5x10^1\right)\)\(+\left(6x10^0\right)\)
\(d,2006=2000+6\)\(=\left(2x10^3\right)\)\(+\left(6x10^0\right)\)
\(e,abc=100a+10b+c=10^2\)\(a+10^1\)\(b+\left(cx10^0\right)\)
\(g,abcde=10000a+1000b+100c+10d+e\)\(=10^4\)\(a+10^3\)\(b+10^2\)\(c+10^1\)\(d+e\)
Bài 9: Viết các số sau dưới dạng tổn các lũy thừa của 10
a) 213 = 2 . 100 + 1 . 10 + 3 . 1 = 2 . 102 + 2 . 101 + 3 . 100
b) 421 = 4 . 100 + 2 . 10 + 1 . 1 = 4 . 102 + 2 . 101 + 1 . 100
c) 1256 = 1 . 1000 + 2 . 100 + 5 . 10 + 6 . 1 = 1 . 103 + 2 . 102 + 5 . 101 + 6 . 100
d) 2006 = 2 . 1000 + 6 . 1 = 2 . 103 + 1 . 100
e) abc = a . 100 + b . 10 + c . 1 = a . 102 + b . 101 + c . 100
g) abcde = a . 10000 + b . 1000 + c . 100 + d . 10 + e . 1 = a . 104 + b . 103 + c .102 + d . 101 + e . 100
Bài 10: Viết mỗi thương sau dưới dạng 1 lũy thừa
a) 38 : 36 = 32
75 : 72 = 73
197 : 193 = 194
210 : 83 = 210 : ( 23 )3 = 210 : 29 = 21 = 2
127 : 67 = ( 12 : 6 )7 = 27
275 : 813 = ( 33 )5 : ( 34 )3 = 315 : 312 = 33
b) 106 : 10 = 105
58 : 252 = 58 : ( 52 )2 = 58 : 54 = 54
49 : 642 = 49 : ( 43 )2 = 49 : 46 = 43
225 : 324 = 225 : ( 25 )4 = 225 : 220 = 5
183 : 93 = ( 18 : 9 )3 = 23
1253 : 254 = ( 53 )3 : ( 52 )4 = 59 : 58 = 5
Bài 1 :
a/ \(a^3.a^9=a^{3+9}=a^{12}\)
b/\(\left(a^5\right)^7=a^{5.7}=a^{35}\)
c/ \(\left(a^6\right).4.a^{12}=a^{24}.a^{12}.4=a^{24+12}.4=a^{36}.4\)
d/ \(\left(2^3\right)^5.\left(2^3\right)^3=2^{15}.2^9=2^{15+9}=2^{24}\)
e/ \(5^6:5^3+3^3.3^2\)
\(=5^3+3^5=125+243=368\)
i/ \(4.5^2-2.3^2\)
\(=2^2.5^2-2.3^2\)
\(=2^2.25-2^2.14\)
\(=2^2.\left(25-14\right)\)
\(=2^2.11\)
\(=4.11=44\)
a) \(125^3:25^4=\left(5^3\right)^3:\left(5^2\right)^4=5^9:5^8=5\)
b) \(\left(10^3+10^4+125^2\right):5^3\)
\(=\left[\left(5.2\right)^3+\left(5.2\right)^4+\left(5^3\right)^2\right]:5^3\)
\(=\left(5^3.2^3+5^4.2^4+5^6\right):5^3\)
\(=\frac{5^3.2^3}{5^3}+\frac{5^4.2^4}{5^3}+\frac{5^6}{5^3}\)
\(=2^3+5.2^4+5^3=213\)
c) \(24^4:3^4-32^{12}:16^{12}\)
\(=\left(3.8\right)^4:3^4-\left(16.2\right)^{12}:16^{12}\)
\(=3^4.8^4:3^4-2^{12}.16^{12}:16^{12}\)
\(=8^4-2^{12}=\left(2^3\right)^4-2^{12}=2^{12}-2^{12}=0\)
Ta có 24 mũ 3 : 12 mũ 3 = (24:12) mũ 3 = 2 mũ
25 mũ 6 : 25 mũ 4 = 25 mũ (4-2) = 25 mũ 2
81 mũ 2 : 9 mũ 2 = (81:9) mũ 2 = 9 mũ 2
32 mũ 4 : 2 mũ 6 = 16834