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\(a,x-5⋮x+2\)
\(\Rightarrow x+2-7⋮x+2\)
\(\Rightarrow x+2\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x + 2 = 1=> x = -1
x + 2 = -1 => x = -3
.... tương tự nhé ~
\(2x+3⋮x-5\)
\(\Rightarrow2x-10+7⋮x-5\)
\(\Rightarrow2\left(x-5\right)+7⋮x-5\)
\(\Rightarrow x-5\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x - 5 = 1 => x = 6
....
5 x y - 7 = 8 + 2 x y
5 x y - 7 - 2 x y = 8
( 5 x y - 2 x y ) - 7 = 8
3 x y - 7 = 8
3 x y = 8 + 7
3 x y = 15
y = 15 : 3
y = 5
Vậy ...
\(5\times y-7=8+2\times y\)
\(5\times y-7-2\times y=8\)
\(\left(5\times y-2\times y\right)-7=8\)
\(3\times y-7=8\)
\(3\times y=8+7\)
\(3\times y=15\)
\(y=15\div3\)
\(y=5\)
c)\(\dfrac{3}{8}\times\dfrac{5}{8}+y=\dfrac{5}{4}\)
\(\dfrac{15}{64}+y=\dfrac{5}{4}\)
\(y=\dfrac{5}{4}-\dfrac{15}{64}\)
\(y=\dfrac{65}{64}\)
d, \(\dfrac{3}{8}+\dfrac{5}{8}\times y=\dfrac{5}{4}\)
\(\dfrac{5}{8}\times y=\dfrac{5}{4}-\dfrac{3}{8}\)
\(\dfrac{5}{8}\times y=\dfrac{7}{8}\)
\(y=\dfrac{7}{8}:\dfrac{5}{8}\)
\(y=\dfrac{7}{5}\)
a, 3/4 x y = 3/5 + 3/10
3/4 x y = 9/10
y = 9/10 : 3/4
y = 6/5
b, 3/5 : y = 3/4 - 2/5
3/5 : y = 7/20
y = 3/5 : 7/20
y = 12/7
Từ đầu bài ta có: y x 4 + y x 6 - y x 2 = 120
y x (4 + 6 - 2) = 120
y x 8 = 120
y = 120 : 8
Vậy y = 15
y : 8 × 32 + y : 3 × 18 - y : 5 × 10 = 120
y × 4 + y × 6 - y × 2 = 120
y × ( 4 + 6 - 2) = 120
y × 8 = 120
y = 120 : 8
y = 15
Vậy y = 15
\(\dfrac{2}{5}\) x y : \(\dfrac{7}{4}\) = \(\dfrac{7}{8}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{7}{8}\) x \(\dfrac{7}{4}\)
\(\dfrac{2}{5}\) x y = \(\dfrac{49}{32}\)
y = \(\dfrac{49}{32}\) : \(\dfrac{2}{5}\)
y = \(\dfrac{245}{64}\)
2\(\dfrac{2}{5}\): y x 1\(\dfrac{1}{4}\) = 2\(\dfrac{3}{5}\)
\(\dfrac{12}{5}\): y x \(\dfrac{5}{4}\) = \(\dfrac{13}{5}\)
\(\dfrac{12}{5}\): y = \(\dfrac{13}{5}\): \(\dfrac{5}{4}\)
\(\dfrac{12}{5}\): y = \(\dfrac{52}{25}\)
y = \(\dfrac{12}{5}\): \(\dfrac{52}{25}\)
y = \(\dfrac{15}{13}\)
y*2 + y*1/5 = 8/5
y * ( 1/5 + 2 ) = 8/5
y * 11/10 = 8/5
y= 8/5 : 11/10
y = 16/11.
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