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a, \(\frac{42}{54}\)= \(\frac{7}{x}\)=> 42x=7.54 => x=\(\frac{7.54}{42}\)= 9. Vậy x=9 b, \(\frac{x}{15}\)= \(\frac{-2}{3}\)=> 3x= (-2).15 => x= \(\frac{\left(-2\right).15}{3}\)= -10. Vậy x=-10 c, \(\frac{x}{27}\)= \(\frac{-5}{9}\)=> 9x=(-5).27 => x\(\frac{\left(-5\right).27}{9}\)= -15 Thay x = -15 vào biểu thức ta có: \(\frac{-15}{27}\)= \(\frac{-45}{y}\)=> -15y= (-45).27 => y= \(\frac{\left(-45\right).27}{-15}\)=81 Vậy x=-15, y = -81 .KÍCH NKA PẠN
theo tớ câu 1 thì một trong hai số phải là 0 nên tớ nghĩ là Câu 1 C:x,y khác dấu
Dễ lắm ;x =3 đó bạn
a.17-(43-/x+11/)=45
(43-/x+11/)=17-45
(43-/x+11/)=-28
/x+11/=43-(-28)
/x+11/=71
TH1:x+11=71;x=71-11=60
TH2:x+11=-71;x=-71-11=-82
b.32.x= -27
9.x=-27
x=-27:9
x=-3
c.x+15= -2
x=-2-15
x=-17
a.17-(43-/x+11/)=45
(43-/x+11/)=17-45
(43-/x+11/)=-28
/x+11/=43-(-28)
/x+11/=71
TH1:x+11=71;x=71-11=60
TH2:x+11=-71;x=-71-11=-82
b.32.x= -27
9.x=-27
x=-27:9
x=-3
c.x+15= -2
x=-2-15
x=-17
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a,\(\dfrac{42}{54}\)=\(\dfrac{7}{x}\)
\(\dfrac{7}{9}\)=\(\dfrac{7}{x}\)
⇒x=9
b,\(\dfrac{x}{15}\)=\(\dfrac{-2}{3}\)
\(\dfrac{x}{15}\)=\(\dfrac{-10}{15}\)
⇒x=-10