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A) 2/3 - x - 1/5 = 2/5 - 1/7
2/3 - x - 1/5 = 9/35
2/3 - x = 9/35 + 1/5
2/3 - x = 16/35
x = 2/3 - 16/35 = 22/105
B) 1/2 x X : 2/3 = 1 2/5
1/2 x X : 2/3 = 7/5
1/2 x X = 7/5 x 2/3
1/2 x X = 14/15
X =14/15 : 1/2
X = 28/15
C) 2/5 x X + X x 1/5 = 2/7
X x ( 2/5 + 1/5 ) = 2/7
X x 3/5 = 2/7
X = 2/7 : 3/5 = 10/21
\(a,x-5⋮x+2\)
\(\Rightarrow x+2-7⋮x+2\)
\(\Rightarrow x+2\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x + 2 = 1=> x = -1
x + 2 = -1 => x = -3
.... tương tự nhé ~
\(2x+3⋮x-5\)
\(\Rightarrow2x-10+7⋮x-5\)
\(\Rightarrow2\left(x-5\right)+7⋮x-5\)
\(\Rightarrow x-5\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
x - 5 = 1 => x = 6
....
3/5 X + 2X + 40 = 53
13/5 X = 53 - 40
13/5 X = 13
X = 13 : 13/5
X = 5
\(\frac{2}{5}\cdot\frac{1}{2}-\frac{2}{5}\cdot\frac{1}{3}-\frac{2}{5}\cdot\frac{1}{6}\)
\(=\frac{2}{5}\cdot\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)
\(=\frac{2}{5}\cdot\frac{0}{6}=\frac{2}{5}\cdot0=0\)
tìm x
a) \(0,5+\left(x-\frac{15}{2}\right):\frac{1}{2}=\frac{9}{2}\)
\(\Rightarrow x=\frac{19}{2}=8,5\)
b) \(2012\cdot x-2010\cdot x=2014\)
\(\Leftrightarrow\left(2012-1010\right)\cdot x=2014\)
\(\Leftrightarrow2x=2014\)
\(\Rightarrow x=\frac{2014}{2}=1007\)
hok tốt .
Tính nhanh:
2/5 x 1/2 - 2/5 x 1/3 - 2/5 x 1/6
= 2/5 x ( 1/2 - 1/3 - 1/6 )
= 2/5 x ( 3/6 - 2/6 - 1/6 )
= 2/5 x 0/6
=0
\(x:2\frac{1}{2}\times x+2\frac{1}{5}=5\frac{1}{2}\)
\(x:\frac{5}{2}\times x+\frac{11}{5}=\frac{11}{2}\)
\(x\times\frac{2}{5}\times x+\frac{11}{5}=\frac{11}{2}\)
\(x\times x\times\frac{2}{5}=\frac{11}{2}-\frac{11}{5}\)
\(x\times x\times\frac{2}{5}=\frac{33}{10}\)
\(x\times x=\frac{33}{10}:\frac{2}{5}\)
\(x\times x=\frac{33}{4}\)
\(\Rightarrow x=\sqrt{\frac{33}{4}}\)
\(x=2,8722...\)
CHÚC BN HỌC TỐT!!!!!
\(\frac{x}{5}+\frac{x}{2}=42,35\)
\(\Rightarrow\frac{2x}{10}+\frac{5x}{10}=42,35\)
\(\Rightarrow\frac{7x}{10}=42,35\)
\(\Rightarrow7x=42,35\times10=423,5\)
\(\Rightarrow x=423.5:7=60,5\)
\(\frac{x}{5}+\frac{x}{2}=42,35 \)
\(x\cdot\frac{1}{5}+x\cdot\frac{1}{2}=42,35\)
\(x\cdot0,2+x\cdot0,5=42,35\)
\(x\cdot\left(0,2+0,5\right)=42,35\)
\(x\cdot0,7=42,35\)
\(x=42,35:0,7\)
\(x=60,5.\)
Vậy \(x=60,5.\)