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N
3
TN
1
5 tháng 10 2019
1-\(\left(3\frac{3}{8}+x-2\frac{5}{24}\right)\)\(.\frac{12}{17}=0\)
\(\Rightarrow\left(3\frac{3}{8}+x-2\frac{5}{24}\right)\)\(.\frac{12}{17}\)\(=1\)
\(\frac{27}{8}+x-\frac{53}{24}\) \(=1:\frac{12}{17}\)
\(\frac{27}{8}+x=\frac{17}{12}+\frac{53}{24}\)
\(\frac{27}{8}+x=\frac{34+53}{24}\)
\(\frac{27}{8}+x=\frac{87}{24}\)
\(x=\frac{87}{24}-\frac{27}{8}\)
\(x=\frac{87-81}{24}\)
\(x=\frac{6}{24}=\frac{1}{4}\)
10 tháng 9 2017
a) \(\frac{24}{x}\div\frac{8}{3}=\frac{3}{5}\)
\(\frac{24}{x}\cdot\frac{3}{8}=\frac{3}{5}\)
\(\frac{24}{x}=\frac{3}{5}\div\frac{3}{8}\)
\(\frac{24}{x}=\frac{24}{15}\)
Vậy x = 15
b) Tương tự
13 tháng 9 2017
\(x+\frac{15}{7}=\frac{9}{2}\)
\(x=\frac{9}{2}-\frac{15}{7}=\frac{33}{14}\)
\(x-\frac{3}{4}=\frac{7}{2}\)
\(x=\frac{7}{2}+\frac{3}{4}=\frac{17}{4}\)
\(x.\frac{7}{8}=\frac{12}{5}\)
\(x=\frac{12}{5}:\frac{7}{8}=\frac{96}{35}\)
\(\frac{5}{6}:x=\frac{4}{3}\)
\(x=\frac{5}{6}:\frac{4}{3}=\frac{5}{8}\)
13 tháng 9 2017
- a) x=9/2-15/7=33/14
- b) x=7/2+3/4=17/4
- c) x=12/5:7/8=61/35
- d) x=5/6:4/3=5/8
- k nha
TV
18 tháng 9 2017
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
KC
18 tháng 9 2017
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
N
0
TH
12 tháng 7 2017
3 - ( 5\(\frac{3}{8}\)+ x - 7\(\frac{5}{24}\)) : 16\(\frac{2}{3}\)= 2
3 - ( \(\frac{43}{8}\)+ x - \(\frac{173}{24}\)) : \(\frac{50}{3}\)= 2
3 - ( \(\frac{43}{8}\)+ x - \(\frac{173}{24}\)) = 2 x \(\frac{50}{3}\)
3 - ( \(\frac{43}{8}\)+ x - \(\frac{173}{24}\)) = \(\frac{100}{3}\)
\(\frac{43}{8}\)+ x - \(\frac{173}{24}\)= 3 - \(\frac{100}{3}\)
\(\frac{43}{8}\)+ x - \(\frac{173}{24}\)= \(-\frac{97}{3}\)
\(\frac{43}{8}\)+ x = \(-\frac{97}{3}+\frac{173}{24}\)
\(\frac{43}{8}\)+ x = \(-\frac{201}{8}\)
x = \(-\frac{201}{8}-\frac{43}{8}\)
x = \(=-\frac{61}{2}\)
25 tháng 9 2020
\(\frac{8}{9}+\frac{1}{3}=\frac{8}{9}+\frac{3}{9}=\frac{11}{9}\)
25 tháng 9 2020
\(\frac{8}{9}+\frac{1}{3}=\frac{8}{9}+\frac{3}{9}=\frac{11}{9}\)
\(\frac{24}{15}-\frac{20}{25}=\frac{24}{15}-\frac{4}{5}=\frac{24}{15}-\frac{12}{15}=\frac{12}{15}\)
\(3\frac{1}{6}\times2\frac{3}{5}=\frac{19}{6}\times\frac{13}{5}=\frac{247}{30}\)
\(2\frac{1}{10}\div2\frac{2}{5}=\frac{21}{10}\div\frac{12}{5}=\frac{21}{10}\times\frac{5}{12}=\frac{7}{8}\)
HD
2
24 tháng 3 2019
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(\Rightarrow1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(\Rightarrow\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=1\)
\(\Rightarrow\frac{43}{8}+x-\frac{173}{24}=\frac{53}{3}\)
\(\Rightarrow\frac{43}{8}+x=\frac{53}{3}+\frac{173}{24}\)
\(\Rightarrow\frac{43}{8}+x=\frac{199}{8}\)
\(\Rightarrow x=\frac{199}{8}-\frac{43}{8}\)
\(\Rightarrow x=\frac{156}{8}=\frac{39}{2}\)
KM
24 tháng 3 2019
\(1-\left(5\frac{3}{8}+x-7\frac{5}{24}\right):16\frac{2}{3}=0\)
\(< =>1-\left(\frac{43}{8}+x-\frac{173}{24}\right):\frac{50}{3}=0\)
\(< =>1\left(\frac{43}{8}+x-\frac{173}{24}\right)=0\)
\(< =>\frac{43}{8}+x-\frac{173}{24}=0\)
\(< =>\frac{43}{8}+x=\frac{173}{24}\)
\(< =>x=\frac{173}{24}-\frac{43}{8}\)
\(< =>x=\frac{11}{6}\)
24/9:8/3=5/3
\(\frac{24}{x}\div\frac{8}{3}=\frac{5}{3}\)
\(\frac{24}{x}=\frac{5}{3}\times\frac{8}{3}\)
\(\frac{24}{x}=?\)