Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(3^{x-1}=\frac{1}{243}\)
\(3^{x-1}=\left(\frac{1}{3}\right)^5\)
\(\Rightarrow3^{x-1}=3^{-5}\)
\(\Rightarrow x-1=-5\)
\(x=-4\)
b) \(2^x+2^{x+3}=114\)
\(2^x.\left(1+2^3\right)=114\)
\(2^x.9=114\)
\(2^x=\frac{38}{3}\)si đề
- a.(3x)2=1/243x33=1/9
3x=1/3 hoặc 3x=-1/3 ( vế 2 ko có x thỏa mãn)
suy ra x=3-1
b.(5x+1)=\(\sqrt{\frac{36}{49}}\)\(\Rightarrow\)5x+1=\(\frac{4}{7}\)hoặc 5x+1=\(\frac{-4}{7}\) | |
\(\Rightarrow\)x=\(\frac{-3}{35}\)hoặc x=\(\frac{-11}{35}\) | |
c.\(\frac{6}{4}\)-10x = \(\frac{4}{5}\)-3x chuyển vế :\(\frac{6}{4}\)-\(\frac{4}{5}\)= -3x + 10x \(\frac{7}{10}\)=7x \(\Rightarrow\)x =\(\frac{7}{10}\):7 \(\Rightarrow\)x= \(\frac{1}{10}\) |
a/ \(3^{x+1}=9^x=3^{2x}\Rightarrow x+1=2x\Leftrightarrow x=1\)
b/ \(2^{3x+2}=4^{x+5}=2^{2x+10}\Rightarrow3x+2=2x+10\Leftrightarrow x=8\)
c/ \(3^{2x-1}=243=3^5\Rightarrow2x-1=5\Leftrightarrow x=3\)
\(\frac{4^x}{2^{x+y}}=8\)
\(\frac{2^{2x}}{2^x.2^y}=8\)
\(\frac{2^x}{2^y}=8\)
\(2^x=2^3.2^y\)
\(2^x=2^{3+y}\)
\(\Rightarrow x=3+y\)
\(\frac{9^{x+y}}{3^{5y}}=243\)
\(\frac{3^{2x+2y}}{3^{5y}}=3^5\)
\(\frac{3^{2x}.3^{2y}}{3^{5y}}=3^5\)
\(\frac{3^{2x}}{3^{3y}}=3^5\)
\(3^{2x}=3^5.3^{3y}\)
\(3^{2x}=3^{5+3y}\)
\(\Rightarrow2x=3y+5\)
\(\hept{\begin{cases}2x-3y=5\\x=3+y\end{cases}}\Leftrightarrow\hept{\begin{cases}2\left(3+y\right)-3y=5\\x=3+y\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}6+2y-3y=5\\x=3+y\end{cases}}\Leftrightarrow\hept{\begin{cases}-y=-1\\x=3+y\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}y=1\\x=4\end{cases}}\)
vậy...
\(\frac{4^x}{2^{x+y}}=8\Leftrightarrow2^{2x}=2^{x+y+3}\Leftrightarrow x=y+3\)
\(9^{x+y}=243.3^{5y}\Leftrightarrow3^{2x+2y}=3^{5y+5}\Leftrightarrow2x=3y+5\)
\(\left(x,y\right)=\left(-1;2\right)\)
a) \(2^{3x+2}=4^{x+5}\)
\(2^{3x+2}=2^{2x+10}\)
\(\Rightarrow3x+2=2x+10\)
\(3x-2x=10-2\)
\(x=8\)
Vậy x = 8
b) \(3^{2x-1}=243\)
\(3^{2x-1}=3^5\)
\(\Rightarrow2x-1=5\)
\(2x=5+1\)
\(2x=6\)
\(x=6\div2\)
\(x=3\)
Vậy x = 3
=))
\(5^{x+2}+5^{x+3}=750\)
\(5^x.5^2+5^x.5^3=750\)
\(5^x.25+5^x\cdot125=750\)
\(5^x.\left(25+125\right)=750\)
\(5^x.150=750\)
\(5^x=750:150\)
\(5^x=5\)
\(5^x=5^1\)
\(\Rightarrow x=1\)
Bài giải
\(3^x\cdot3^{x+2}=243\)
\(3^{x+x+2}=243\)
\(3^{2x+1}=243\)
\(3^{2x+1}=3^5\)
\(\Rightarrow\text{ }2x+1=5\)
\(2x=5-1\)
\(2x=4\)
\(x=4\text{ : }2\)
\(x=2\)
3^x.3^x+2=243
Suy ra3^x.3^x.3^2=243
3^x.(3^2.1)=243
3^x.9=243
3^x=243:9
3^x=27
Suy ra x=3