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\(\frac{4}{5}x-\frac{4}{3}\left(x-\frac{1}{4}\right)=0,3+\left(-\frac{1}{3}\right)^2\)
\(\Rightarrow\frac{4}{5}x-\frac{4}{3}x+\frac{1}{3}=0,3+\frac{1}{9}\)
\(\Rightarrow\frac{-8}{15}x+\frac{1}{3}=\frac{37}{90}\)
\(\Rightarrow-\frac{8}{15}x=\frac{7}{90}\)
\(\Rightarrow x=-\frac{7}{48}\)
\(25\%+\frac{2}{5}\le x\%\le1-0,3\)
\(\Rightarrow\frac{13}{20}\le\frac{x}{100}\le\frac{7}{10}\)
\(\Rightarrow\frac{13}{20}.100\le x\le\frac{7}{10}.100\)
\(\Rightarrow65\le x\le70\)
\(\Rightarrow x\in\left\{65;66;67;68;69;70\right\}\)
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
a, \(-5x-1-\dfrac{x}{2}+\dfrac{1}{3}=\dfrac{3}{2}x-5\Leftrightarrow-7x=-\dfrac{13}{3}\Leftrightarrow x=\dfrac{13}{21}\)
b, \(3x-\dfrac{3}{2}-5x-3=-x+\dfrac{1}{5}\Leftrightarrow-x=\dfrac{47}{10}\Leftrightarrow x=-\dfrac{47}{10}\)
a) 5^x-1 = 5^2 + 100
=> 5x-1 = 125 = 53
=> x - 1 = 3
=> x = 4.
b) x10 = x
=> x = {-1;0;1}
2.52.32 + {[2.53 - (5x + 4).5 : (23.3.5)]} = 455
=> 450 + {250 - (5x + 4).5 : 120} = 455
=> 250 - (5x + 4).5 : 120 = 5
=> (5x + 4).5 : 120 = 245
=> (5x + 4).5 = 245.120 = 29400
=> 5x + 4 = 29400 : 5 = 5880
=> 5x = 5876
=> x = 1175,2
\(\frac{3}{2}-x=-0,3:\frac{3}{5}\)
\(\frac{3}{2}-x=-\frac{1}{2}\)
\(x=\frac{3}{2}-\left(-\frac{1}{2}\right)\)
\(x=\frac{3}{2}+\frac{1}{2}=\frac{4}{2}=2\)
3/5.(3/2 - x) = -0.3
=>3/2 - x = -0.3 : 3/5
=>3/2 - x = -0.5
=> x = 3/2 + 0.5
=> x = 2
~Study well~