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\(2^{x+2}-2^x=96\)
\(\Rightarrow2^x\cdot2^2-2^x=96\)
\(\Rightarrow2^x\left(2^2-1\right)=96\)
\(\Rightarrow2^x\left(4-1\right)=96\)
\(\Rightarrow2^x\cdot3=96\)
\(\Rightarrow2^x=96:3\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)
\(\Rightarrow x=5\)
\(5^x+5^{x+1}=750\)
\(\Rightarrow5^x+5^x\cdot5=750\)
\(\Rightarrow5^x\left(1+5\right)=750\)
\(\Rightarrow5^x\cdot6=750\)
\(\Rightarrow5^x=750:6\)
\(\Rightarrow5^x=125\)
\(\Rightarrow5^x=5^3\)
\(\Rightarrow x=3\)
\(2^{x+3}+2^x=144\)
\(\Rightarrow2^x\cdot2^3+2^x=144\)
\(\Rightarrow2^x\left(2^3+1\right)=144\)
\(\Rightarrow2^x\cdot9=144\)
\(\Rightarrow2^x=144:9\)
\(\Rightarrow2^x=16\)
\(\Rightarrow2^x=2^4\)
\(\Rightarrow x=4\)
{x2-[36(64-63)3-35]-15}3=1
{x2-[36.13-35]-15}3=1
{x2-[36.1-35]-15}3=1
{x2-[36-35]-15}3=1
{x2-1-15}3=1
{x2-1-15}3=13
=>x2-1-15=1
x2=1+1+15
x2=17
x2=căn của 7
=>x=căn 7
Vậy x=căn 7
tk nha
\(3^{x-1}+5.3^{x-1}=486\)
\(\Rightarrow3^{x-1}.\left(5+1\right)=486\)
\(3^{x-1}.6=486\)
\(3^{x-1}=81\)
\(3^{x-1}=3^4\)
\(\Rightarrow x-1=4\)
\(\Rightarrow x=5\)
<=> 3x-1 +5.3x-1 =486
<=> 3x-1 . (1+5) = 486
<=> 3x-1 . 6 =486
<=> 3x-1 = 486 :6
<=> 3x-1 = 81
<=> 3x-1 = 34
<=> X-1=4
<=> X = 4+1
<=> X=5
\(=>2\cdot4^x+64\cdot4^x=1056\)
\(=>4^x\cdot\left(2+64\right)=1056\)
\(=>4^x=1056:66=16\)
\(=>4^x=4^2\)
\(=>x=2\)
ti ck nha
2.22x + 43.4x = 1056
=> 2.4x + 43.4x = 1056
=> (2 + 64).4x = 1056
=> 66.4x = 1056
=> 4x = 1056 : 66
=> 4x = 16
=> 4x = 42
=> x = 2
7.4x - 1 + 4x + 1 = 23
=> 7.4x.1/4 + 4x.4 = 23
=> (7/4 + 4).4x = 23
=> 23/4.4x = 23
=> 4x = 23 : 23/4
=> 4x = 4
=> x = 1
3x + 2 - 5.3x = 36
=> 3x.9 - 5.3x = 36
=> 3x.(9 - 5) = 36
=> 3x.4 = 36
=> 3x = 36 : 4
=> 3x = 9 = 32
=> 3x = 2
\(3^{x-1}=432:4^2=27=3^3\)
\(\Rightarrow x-1=3\Leftrightarrow x=4\)
3x + 5 . 3x+1 = 432
3x + 5 . 3x . 3 = 432
3x + 15 . 3x = 432
3x . ( 1 + 15 ) = 432
3x . 16 = 432
3x = 432 : 16
3x = 27
3x = 33
=> x = 3
Vậy x = 3
3x + 5.3.3x = 432 <=> 3x.( 1+ 5.3) = 432 <=> 3x = 432/16 = 27 = 33 <=> x=3