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135 - 3 ( x + 1 ) = 30
3 ( x + 1 ) = 105
x + 1 = 35
x = 34
\(1005^2\cdot1005^x=1005^7\)
\(1005^{2+x}=1005^7\)
=> x + 2 = 7
=> x = 5
Vậy,........
10052 . 1005x = 10057
=> 1005x = 10057 : 10052
1005x = 10055
=> x = 5
ok mk nha!! 365656675678435365647697894563564564556756787687745645756768
a) 135 - 3 . ( x + 1 ) = 30
3 . ( x + 1 ) = 135 - 30
3 . ( x + 1 ) = 105
x + 1 = 105 : 3
x + 1 = 35
x = 35 - 1
x = 34
b) 12 + 2x = 22 . 52
12 + 2x = 100
2x = 100 - 12
2x = 88
x = 88 : 2
x = 44
c) 10052 . 1005x = 10057
1005x = 10057 : 10052
1005x = 10055
= > x = 5
hok tốt
33 - 2x = 71005 . 71013 . 72017
33 - 2x = 74035
2x = 33 - 74035
x = ( 33 - 74035 ) : 2
\(\left(2x-15\right)^5=\left(2x-15\right)^3\)
\(\Rightarrow\orbr{\begin{cases}2x-15=1\\2x-15=-1\end{cases}}\)Hoặc 2x - 15 = 0
<=> x = 8 hoặc x = 7 hoặc x = 15/2
Ơ chị k5 mà ạ ?
a) \(\left(-5\right)\left(x-2\right)^2+360=\left(-150\right)\cdot3+43\cdot5\)
\(-5\cdot\left(x-2\right)^2+360=-235\)
\(-5\cdot\left(x-2\right)^2=-595\)
\(\left(x-2\right)^2=119\)
\(\left(x-2\right)^2=\left(\pm\sqrt{199}\right)^2\)
\(\Rightarrow\orbr{\begin{cases}x-2=\sqrt{119}\\x-2=-\sqrt{119}\end{cases}\Rightarrow\orbr{\begin{cases}x=\sqrt{119}+2\\x=2-\sqrt{119}\end{cases}}}\)
b) \(\left(x+5\right)-\left(3x+9\right)=-16\)
\(x+5-3x-9=-16\)
\(-2x-4=-16\)
\(-2x=-12\)
\(x=6\)
c) \(3\left(x+2\right)-\left(15-x\right)\cdot6=160+\left(-1\right)^{1005}\)
\(3x+6-90+6x=160-1\)
\(9x-84=159\)
\(9x=243\)
\(x=27\)
d) \(x\left(x-1\right)\left(x^2-4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x\left(x-1\right)=0\\x^2-4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\left\{0;1\right\}\\x=\left\{2;-2\right\}\end{cases}}}\)
a) S = \(6^{362}.12^{508}.35^{100}+1324^{500}\)
\(\left(.....6\right).\left(....6\right).\left(....5\right)+\left(1324.1324\right)^{499}\)
\(\left(...6\right).\left(...6\right)\left(...5\right)+\left(...6\right)^{499}\)
\(\left(...6\right).\left(...6\right).\left(...5\right)+\left(...6\right)\)
= (...0) + 6
= ....6
Vậy có chữ số tận cùng là 6
F = \(9^{81}.6^{72}.25^{501}+325^{1005}\)
= (9 . 9)80 . 672 . 25501 +325 1005
= (...1)80 . (...6) .(...5) + (...5)
= (....1) . (...6) . (...5) + (...5)
= (...0) + (...5)
= (...5)
Vậy chữ số tận cùng là 5
x = 4
x= 5
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(=>x-1=3\)
\(=>x=4\)
vậy \(x=4\)
\(1005^2.1005^x=1005^7\)
\(=>2x=7\)
\(=>x=3,5\)
vậy \(x=3,5\)