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a) x+13,5=34
x=34-13,5
x=20,5
b) 6/5 - x = 1/2
x=6/5-1/2
x=7/10
x + 13.5=34
x + 65 =34
x =34 - 65
x = -31
\(\frac{6}{5}\) - x = \(\frac{1}{2}\)
x = \(\frac{6}{5}\) - \(\frac{1}{2}\)
x = \(\frac{7}{10}\)
x + 13,5 = 34
x =34-13,5
x =20,5
6/5 - x = 1/2
x =6/5- 1/2
x =12/10 - 5/10
x =7/10
\(\left(a\right)\frac{34-x}{30}=\frac{5}{6}\)
\(\frac{34-x}{30}=\frac{25}{30}\)
34 - x = 25
x = 34 - 25 = 9
\(\left(b\right)\frac{x+13}{34}=\frac{12}{17}\)
\(\frac{x+13}{34}=\frac{24}{34}\)
x + 13 = 24
x = 24 - 13 = 11
\(\left(c\right)\left(x+\frac{1}{3}\right)+\left(x+\frac{1}{9}\right)+\left(x+\frac{1}{27}\right)+\left(x+\frac{1}{81}\right)=\frac{56}{81}\)
\(4x+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)
Đặt \(A=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
Ta có : \(3A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)
\(3A-A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}-\frac{1}{3}-\frac{1}{9}-\frac{1}{27}-\frac{1}{81}\)
\(2A=1-\frac{1}{81}=\frac{80}{81}\)
\(A=\frac{80}{81}\div2=\frac{40}{81}\)
\(\Rightarrow4x+\frac{40}{81}=\frac{56}{81}\)
\(4x=\frac{56}{81}-\frac{40}{81}\)
\(4x=\frac{16}{81}\)
\(x=\frac{16}{81}\div4=\frac{4}{81}\)
A , 34 - \(\dfrac{x}{30}\) = \(\dfrac{5}{6}\)
\(\dfrac{x}{30}\) = 34 - \(\dfrac{5}{6}\)
\(\dfrac{x}{30}=\) \(\dfrac{199}{6}\)
\(\dfrac{x}{30}=\) \(\dfrac{995}{30}\)
x = 995
B x +\(\dfrac{13}{34}\) = \(\dfrac{12}{17}\)
x = \(\dfrac{12}{17}-\dfrac{13}{34}\)
x = \(\dfrac{11}{34}\)
\(\dfrac{7}{9}=\dfrac{21}{27};\dfrac{7}{10}=\dfrac{21}{30}\)
hai số nằm giữa \(\dfrac{7}{9}\) và \(\dfrac{7}{10}\)
\(\dfrac{21}{27}>\dfrac{21}{28}>\dfrac{21}{29}>\dfrac{21}{30}\)
\(a,\left(x-12\right)\times1000=0\)
\(x-12=0\)
\(x=0+12\)
\(x=12\)
\(b,\left(23-x\right)\times34=34\)
\(23-x=34:34\)
\(23-x=1\)
\(x=23-1\)
\(x=22\)
\(c,\left(x-5\right)\times6=24\)
\(x-5=24:6\)
\(x-5=4\)
\(x=4+5\)
\(x=9\)
\(d,2x+3=15\)
\(2x=15-3\)
\(2x=12\)
\(x=12:2\)
\(x=6\)
\(e,6\left(7x+1\right)=48\)
\(7x+1=48:6\)
\(7x+1=8\)
\(7x=7\)
\(x=1\)
\(g,\left(x-6\right)\left(x-34\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\x-34=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=6\\x=34\end{cases}}\)
\(h,\left(x-4\right)\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x+2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}\)
Bài làm
a) \(\left(x-12\right).1000=0\)
Vì 1000 > 0 \(\Rightarrow x-12=0\Rightarrow x=12\)
b) \(\left(23-x\right).34=34\)
\(\Rightarrow23-x=1\Rightarrow x=22\)
c) \(\left(x-5\right).6=24\Rightarrow x-5=4\Rightarrow x=9\)
d) \(2x+3=15\Rightarrow2x=12\Rightarrow x=6\)
e) \(6\left(7x+1\right)=48\Rightarrow7x+1=8\)
\(\Rightarrow7x=7\Rightarrow x=1\)
g) \(\left(x-6\right).\left(x-34\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-6=0\\x-34=0\end{cases}\Rightarrow\orbr{\begin{cases}x=6\\x=34\end{cases}}}\)
Vậy x= 6 hoặc x= 34
h)\(\left(x-4\right).\left(x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}}\)
Vậy x=4 hoặc x= -2
i) \(x\left(x+1\right).\left(x+2\right)=3\)
..........
Cậu có thể tam khảo bài làm trên đây ạ, học tốt nha ^^
a)
X + \(\frac{1}{5}=\frac{9}{13}\)
\(X=\frac{9}{13}-\frac{1}{5}\)
\(X=\frac{32}{65}\)
b) 20:6=3,33 dư 0,02
30:4=7,5
51:26=1,96 dư 0,04
a) Tìm \(x\)
\(x+\frac{1}{5}=\frac{9}{13}\)
\(x=\frac{9}{13}-\frac{1}{5}\)
\(x=\frac{32}{65}\)
b) 20 : 6 = 3,33 (dư 2)
30 : 4 = 7,50 ( dư 0)
51 : 26 = 1,96 (dư 4)
Ai k mk mk k lại!
35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34 =
= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45
= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )
= 35 . 110 + 65 . 110
= 110 . ( 35 + 65 )
= 110 . 100
= 11000
Hok tốt!!!!!!!!!!!!!
a) Tính bằng cách hợp lí nhất :
35 . 34 + 35 . 38 + 65 . 75 + 65 . 45 + 35 . 34
= 35 . 34 + 35 . 38 + 35 . 34 + 65 . 75 + 65 . 45
= 35 . ( 34 + 38 + 34 ) + 65 . ( 75 + 45 )
= 35 . 106 + 65 . 120
= 3710 + 7800
= 11510
3 . 25 . 8 + 4 . 37 . 6 + 2 . 38 . 12
= 3 . 8 . 25 + 4 . 6 . 37 + 2 . 12 . 38
= 24 . 25 + 24 . 37 + 24 . 38
= 24 . ( 25 + 37 + 38 )
= 24 . 100
= 2400
b) Tìm số tự nhiên x, biết :
( x - 5 ) ( x + 7 ) = 0
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+7=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-7\end{cases}}}.\)
Vậy .......
\(\dfrac{34-x}{30}\)=\(\dfrac{5}{6}\)
=> \(\dfrac{34-x}{30}\)=\(\dfrac{25}{30}\)
=>34-x=25
=>x=9