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a: \(\Leftrightarrow-\dfrac{2}{3}\cdot\dfrac{4-6-9}{12}\ge x\ge-\dfrac{13}{3}\cdot\dfrac{3-1}{6}\)

\(\Leftrightarrow-\dfrac{2}{3}\cdot\dfrac{-11}{12}\ge x\ge\dfrac{-13}{3}\cdot\dfrac{1}{3}\)

\(\Leftrightarrow\dfrac{22}{36}\ge x\ge\dfrac{-13}{9}\)

mà x là số nguyên

nên \(x\in\left\{0;-1\right\}\)

b: \(\Leftrightarrow\dfrac{21}{100}+\dfrac{75}{100}-\dfrac{220}{100}>=2x-1>=-3-\dfrac{1}{2}+3+\dfrac{1}{5}\)

\(\Leftrightarrow\dfrac{-124}{100}\ge2x-1\ge\dfrac{-3}{10}\)

\(\Leftrightarrow-\dfrac{124}{100}+1\ge2x>=\dfrac{-3}{10}+1\)

\(\Leftrightarrow\dfrac{-3}{25}\ge2x\ge\dfrac{7}{10}\)(vô lý)

=>x không có giá trị

c: \(\Leftrightarrow43+\dfrac{1}{2}-39-\dfrac{1}{5}\le-3x+4\le9+\dfrac{1}{5}+50+\dfrac{1}{7}\)

\(\Leftrightarrow3+\dfrac{3}{10}\le-3x+4\le59+\dfrac{12}{35}\)

\(\Leftrightarrow\dfrac{33}{10}-4\le-3x\le59+\dfrac{12}{35}-4\)

\(\Leftrightarrow\dfrac{-7}{10}\le-3x\le\dfrac{1937}{35}\)

\(\Leftrightarrow\dfrac{7}{30}\ge x\ge-\dfrac{1937}{105}\)

mà x là số nguyên

nên \(x\in\left\{0;-1;-2;...;-18\right\}\)

 

9 tháng 9 2017

Thêm đề: Tìm \(x\in Z\)

\(-\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\ge x\ge-4\dfrac{1}{3}.\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\)

\(\Rightarrow-\dfrac{2}{3}.\left(-\dfrac{11}{12}\right)\ge x\ge-\dfrac{13}{3}.\dfrac{1}{3}\)

\(\Rightarrow\dfrac{11}{18}\ge x\ge-\dfrac{13}{9}\)

\(x\in Z\) nên \(x\in\left\{-1;0\right\}\)

Vậy...............

Chúc bạn học tốt!!!

a: \(\left(2x+3\right)\left(3x-5\right)\ge0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x-5\ge0\\2x+3\le0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x>=\dfrac{5}{3}\\x< =-\dfrac{3}{2}\end{matrix}\right.\)

b: \(\dfrac{x}{3-x}>-1\)

\(\Leftrightarrow\dfrac{x}{3-x}+1>0\)

\(\Leftrightarrow\dfrac{x+3-x}{3-x}>0\)

=>3-x>0

hay x<3

c: \(\dfrac{x-1}{x+5}\ge\dfrac{3}{2}\)

\(\Leftrightarrow\dfrac{x-1}{x+5}-\dfrac{3}{2}\ge0\)

\(\Leftrightarrow\dfrac{2x-2-3x-15}{2\left(x+5\right)}>=0\)

\(\Leftrightarrow\dfrac{x+17}{2\left(x+5\right)}< =0\)

=>-17<=x<-5

d: \(\dfrac{7}{4x^2-1}\ge0\)

=>4x2-1>0

=>(2x-1)(2x+1)>0

=>x>1/2 hoặc x<-1/2

 

30 tháng 8 2019

1) -2/3

1: \(\Leftrightarrow3x+4=2\)

=>3x=-2

=>x=-2/3

2: \(\Leftrightarrow7x-7=6x-30\)

=>x=-23

3: =>\(5x-5=3x+9\)

=>2x=14

=>x=7

4: =>9x+15=14x+7

=>-5x=-8

=>x=8/5

a: \(\Leftrightarrow\dfrac{23}{5}\cdot\dfrac{50}{23}< =x< =\dfrac{-13}{5}:\dfrac{7}{5}\)

=>10<=x<=-13/7

hay \(x\in\varnothing\)

b: \(\Leftrightarrow-\dfrac{13}{3}\cdot\dfrac{1}{3}< =x< =\dfrac{-2}{3}\cdot\dfrac{-11}{12}\)

=>-13/9<=x<=22/36

hay \(x\in\left\{-1;0\right\}\)

18 tháng 6 2018

Giải:

a) \(\dfrac{1}{3}x+\dfrac{1}{5}-\dfrac{1}{2}x=1\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{1}{5}-\dfrac{1}{6}x=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{1}{6}x=\dfrac{-21}{20}\)

\(\Leftrightarrow x=\dfrac{-63}{10}\)

Vậy ...

b) \(\dfrac{3}{2}\left(x+\dfrac{1}{2}\right)-\dfrac{1}{8}x=\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{3}{2}x+\dfrac{3}{4}-\dfrac{1}{8}x=\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{11}{8}x=\dfrac{-1}{2}\)

\(\Leftrightarrow x=\dfrac{-4}{11}\)

Vậy ...

Các câu sau làm tương tự câu b)

5 tháng 10 2017

\(a)3\dfrac{1}{2}.\dfrac{4}{49}-\left[2,\left(4\right):2\dfrac{5}{11}\right]:\left(\dfrac{-42}{5}\right)\)

\(=\dfrac{7}{2}.\dfrac{4}{49}-\dfrac{88}{27}:\left(\dfrac{-42}{7}\right)\)

\(=\dfrac{2}{7}-\dfrac{-220}{567}\)

\(=\dfrac{382}{567}\)

các phần con lại dễ nên bn tự lm đi nhé mk bn lắm

Chúc bạn học tốt!

25 tháng 12 2017

Tính 1 câu thoy nhé !

\(\dfrac{3}{7}.19\dfrac{1}{3}-\dfrac{3}{7}.33\dfrac{1}{3}\)

= \(\dfrac{3}{7}.\left(19\dfrac{1}{3}-33\dfrac{1}{3}\right)\)

=\(\dfrac{3}{7}.-14=-6\)

2 tháng 10 2017

câu E

\(\left\{{}\begin{matrix}x\ne\dfrac{5}{2}\\\left(2x-5\right)\left(5-2x\right)=-\left(\dfrac{3}{2}\right)^4\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}x\ne\dfrac{5}{2}\\\left|2x-5\right|=\left(\dfrac{3}{2}\right)^2\end{matrix}\right.\)

\(\left[{}\begin{matrix}\left\{{}\begin{matrix}x< \dfrac{5}{2}\\2x-5=-\left(\dfrac{3}{2}\right)^2\Rightarrow x=\dfrac{11}{8}< \dfrac{5}{2}\left(n\right)\end{matrix}\right.\\\left\{{}\begin{matrix}x>\dfrac{5}{2}\\2x-5=\left(\dfrac{3}{2}\right)^2\Rightarrow x=\dfrac{29}{8}>\dfrac{5}{2}\left(n\right)\end{matrix}\right.\end{matrix}\right.\)

câu F (bạn cho vào lớp 7.2=lớp 14 nhé. )