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Tìm x:
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 -1
x = 17
b, 12x - 33 = 32.33
12x - 33 =9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x=276:12
x=23
a, 96 - 3 . ( x + 1 ) = 42
3 . ( x + 1 ) = 96 - 42
3 . ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
b, 12x - 33 = 32 . 33
12x - 33 = 9 . 27
12x - 33 = 243
12x = 243 + 33
12x = 276
x = 276 : 12
x = 23
c)96-3(x+1)=42
3(x+1)=96-42
3(x-1)=54
(x+1)=54:3
(x+1)=18
x=18-1
x=17
a, 541 + [218 - x] = 735
[ 218 - x ] = 735 - 541
[ 218 - x ] = 194
218 - x = 194
= 218 - 194
=24
96 - 3( x + 1 ) = 42
3( x + 1 ) = 96 - 42
3( x + 1 ) = 54
x + 1 = 54 : 3 = 18
x = 18 - 1
x = 17
cau 1
96-3(x+1)=42
=> 3(x-1)=54
=> x-1=18
=> x=19
cau 2
12x-33=32.33
=> 12x-33=243
=> 12x=276
=> x=23
a ) 5(x + 35 ) = 515
x + 35 = 515 : 5
x + 35 = 103
x = 103 - 35
x = 68
a) x+35=515:5
x+35=103
x= 103-35=68
b) 96-3(x+1)=42
3(x+1)=96-42=54
x+1=54:3=18
x=18-1=17
c) 12x-33=32.33
12x - 33 = 9 . 27
12x - 33=243
12x = 243 +33
12x = 276
x= 276:12
x=23
\(96-3\times\left(x+1\right)=\)\(42\)
\(\Rightarrow3\times\left(x+1\right)=96-42=54\)
\(\Rightarrow x+1=54:3=18\)
\(\Rightarrow x=18-1=17\)
\(12x-33=3^2\times3^3\)
\(\Rightarrow12x-33=3^5=243\)
\(\Rightarrow12x=243+33=276\)
\(\Rightarrow x=276:12=23\)
a) 541 + ( 218 - x ) = 735
218 - x = 194
x = 24
b) 5 ( x + 35 ) = 515
x + 35 = 103
x = 68
c) 96 - 3 ( x + 1 ) = 42
3 ( x + 1 ) = 54
x + 1 = 18
x = 17
d ) 12x - 33 = 3 2 * 3 3
12x - 33 = 243
12x = 276
x = 23
a; 218-x=735-541
218-x=194
x=218-194
x=24
b; x+35=515/5
x+35=103
x=103-35
x=68
c;3*(x+1)=96-42
3*(x+1)=54
x+1=54/3
x+1=18
x=18-1
x=17
d;12x-33=243
12x=243+33
12x=276
x=276/12
x=23
a, 96 - 3(x + 1 ) = 42
3( x+ 1 ) = 54
x + 1 = 18
x = 17
b , 12x - 33 = 32 . 33
12x - 33 = 35
12x-33 = 243
12 x= 276
x = 23
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