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a) x+10=-14
x=-14-10
x=-24
Vậy x=-24
b)5x-12=48
5x=48+12
5x=60
x=60:5
x=2
Vậy x=2
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\frac{1}{3}:\left(2x-1\right)=-5-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=-\frac{20}{4}-\frac{1}{4}\)
\(\frac{1}{3}:\left(2x-1\right)=-\frac{21}{4}\)
\(\left(2x-1\right)=\frac{1}{3}:-\frac{21}{4}\)
\(\left(2x-1\right)=\frac{1}{3}.-\frac{4}{21}\)
\(\left(2x-1\right)=-\frac{4}{63}\)
2x= -4/63 + 1
2x = 59/63
x = 59/63 : 2
x = 59/126
1/3:(2.x-1)=-5-1/4
1/3:(2.x-1)=-21/4
2.x-1=1/3:-21/4
2.x-1=-4/63
2.x=-4/63+1
2.x=\(3\frac{59}{63}\)
x=\(3\frac{59}{63}\):2
x=\(1\frac{61}{63}\)
(x-24).(x-2012)=0
=>
TH1: x-24=0 => x= 24
TH2: x-2012=0=> x=2012
chúc bn học giỏi.
a) | x - 3 | - ( -3 ) = 4
| x - 3 | = 4 + ( -3 )
| x - 3 | = 1
=> x - 3 = -1 => x = ( -1 ) + 3 = -2
hoặc x - 3 = 1 => x = 1 + 3 = 4
vậy x = 1 hoặc x = 4
\(\left|x+3\right|+\left|x-2\right|=5\left(1\right)\)
Xét \(x\le-3\), \(\left(1\right)\Leftrightarrow-x-3+2-x=5\)
\(\Leftrightarrow-2x=6\Leftrightarrow x=-3\) (thỏa mãn)
Xét \(-3< x\le2\), \(\left(1\right)\Leftrightarrow x+3+2-x=5\)
\(\Leftrightarrow5=5\Leftrightarrow x\in Z\)
Xét \(x>5\), \(\left(1\right)\Leftrightarrow x+3+x-2=5\)
\(\Leftrightarrow2x=4\Leftrightarrow x=2\) (loại)
đặt A=.....
=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{x-1}-\frac{1}{x}+\frac{1}{x}-\frac{1}{x+1}\)=\(\frac{2016}{2017}\)
=\(1-\frac{1}{x+1}=\frac{2016}{2017}\)
=\(\frac{x}{x+1}=\frac{2016}{2017}\)
=>x=2016
vậy..............
\(4x-39\div3=3\)
\(4x-13=3\)
\(4x=3+13\)
\(4x=16\)
\(x=16\div4\)
\(x=4\)
4.x-39:3=3
4.x-13=3
4.x=3+13
4.x=16
x=16:4
x=4