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a) \(\text{2(x-51)=2.2^2+20}\)
\(2\left(x-51\right)=2.4+20\)
\(2\left(x-51\right)=28\)
\(x-51=28\div2\)
\(x-51=14\)
\(x=14+51\)
\(\text{b)3.(x+1)-26=541}\)
\(3.\left(x+1\right)=541+26\)
\(3\cdot\left(x+1\right)=567\)
\(x+1=567\div3\)
\(x+1=189\)
\(x=189-1\)
\(x=188\)
\(x=65\)
\(\text{c)4(x-3)=7^2-1^10}\)
\(4\left(x-3\right)=49-1\)
\(4\left(x-3\right)=48\)
\(x-3=48\div4\)
\(x-3=12\)
\(x=12+3\)
\(x=15\)
\(\text{e)2x-138=2^3.3^2}\)
\(2x-138=8\cdot9\)
\(2x-138=72\)
\(2x=72+138\)
\(2x=210\)
\(x=210\div2\)
\(x=105\)
\(\text{f)(x-1)^4=16}\)
\(\left(x-1\right)^4=2^4\)
\(x-1=2\)
\(x=2+1\)
\(x=3\)
1a)1+2+3+...+x=0
\(\frac{x.\left(x+1\right)}{2}\)=0
x.(x+1) =0:2
x.(x+1) =0
x.(x+1) =0.1
vây x=0
tich dung cho minh nha
a, Vì \(x>0\Rightarrow\)x là số nguyên dương, Vì \(8⋮x\Rightarrow x=Ư\left(8\right)=\left\{1;2:4;8\right\}\)
Vậy \(x=\left\{1;2;4;8\right\}\)
b, Vì \(x>0\Rightarrow\)x là số nguyên dương, Vì \(12⋮x\Rightarrow x=Ư\left(12\right)=\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\right\}\)
Vậy \(x=\left\{\dots\right\}\)
c, Vì \(x⋮-8,x⋮12\Rightarrow x=UC\left(-8,12\right)=\left\{\pm1;\pm2;\pm4\right\}\)
Vậy \(x=\left\{\dots\right\}\)
a, (x+5)+(x-9)=x+2
\(\Leftrightarrow\)(x+5)+(x-9)-x-2=0
\(\Leftrightarrow\)x+5+x-9-x-2=0
\(\Leftrightarrow\)x-6=0
\(\Leftrightarrow\)x=6
Vậy...
b, \(\left|x+3\right|\)+\(\left|x+2\right|\)=x
\(\Leftrightarrow\)x+3+x+2=x
\(\Leftrightarrow\)x+3+x+2-x=0
\(\Leftrightarrow\)x+5=0
\(\Leftrightarrow\)x=-5
Vậy...
c, 2.\(\left|x-20\right|\)=10
\(\Leftrightarrow\)\(\left|x-20\right|\)=5
\(\Leftrightarrow\)\(\left[\begin{matrix}x-20=5\\x-20=-5\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=25\\x=15\end{matrix}\right.\)
Vậy...
d, 2.\(\left|x-5\right|\)=2\(^5\)
\(\Leftrightarrow\)2.\(\left|x-5\right|\)=32
\(\Leftrightarrow\)\(\left|x-5\right|\)=16
\(\Leftrightarrow\)\(\left[\begin{matrix}x-5=16\\x-5=-16\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=21\\x=-11\end{matrix}\right.\)
Vậy...
e, -5x+(7-15)=-6x+5
\(\Leftrightarrow\)-5x-8=-6x+5
\(\Leftrightarrow\)-5x-8+6x-5=0
\(\Leftrightarrow\)x-13=0
\(\Leftrightarrow\)x=13
Vậy...
f, 23-3.\(\left|2x+6\right|\)=-7
\(\Leftrightarrow\)3.\(\left|2x+6\right|\)=30
\(\Leftrightarrow\)\(\left|2x+6\right|\)=10
\(\Leftrightarrow\)\(\left[\begin{matrix}2x+6=10\\2x+6=-10\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=2\\x=-8\end{matrix}\right.\)
Vậy...
Chúc bạn học tốt!!!^^^