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a: =>x+5+x-9=x+2
=>2x-4=x+2
=>x=6
c: =>|x-20|=5
=>x-20=5 hoặc x-20=-5
=>x=25 hoặc x=15
d: =>|x-5|=25/2
=>x-5=25/2 hoặc x-5=-25/2
=>x=35/5 hoặc x=-15/2
a)-6x=6
x=-1
b)8x=35->x=35/8
c)8|x|=35->|x|=35/2->x=35/2;x=-35/2
mấy ý kia tương tự bạn ạ!
a, (19-51)-(x-23)=-6
19-51-x+23=-6
-32-x+23=-6
-32-x=-6-23
-32-x=-29
x=-32+(-29)
x=-61
-5x-10(-7)=55
-5x+70=55
-5x=55-70
-5x=-15
x=-15:(-5)
x=3
c, -7-2x=-37-(-26)
-7-2x=-37+26
-7-2x=11
-2x=11+7
-2x=18
x=-9
d, /2x-1/=/-5/
2x-1=5
2x=5+1
2x=6
x=6:2
x=3
e, 2-/x+5/=7
2-x+5=7
2-x=7-5
2-x=2
x=2-2
x=0
h, (x+8)2=25
(x+8)2=52
x+8=5
x=5-8
x=-3
f, (x+3)3:3-1=-10
(x+3)3:3=-10+1
(x+3)3:3=-9
(x+3)3:3=33
x+3:3=3
x+3=9
x=9-3
x=6
k mk nhe
a, 2. \(\left|x-20\right|\)=10
\(\Leftrightarrow\)\(\left|x-20\right|\)=5
\(\Leftrightarrow\)\(\left[\begin{matrix}x-20=5\\x-20=-5\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=25\\x=15\end{matrix}\right.\)
Vậy ...
b,2. \(\left|x-5\right|\)=2\(^5\)
\(\Leftrightarrow\)2. \(\left|x-5\right|\)=32
\(\Leftrightarrow\)\(\left|x-5\right|\)=16
\(\Leftrightarrow\)\(\left[\begin{matrix}x-5=16\\x-5=-16\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=21\\x=-11\end{matrix}\right.\)
Vậy...
c,-5x+(7-15)=6x+5
\(\Leftrightarrow\)-5x-8-6x-5=0
\(\Leftrightarrow\)-11x-13=0
\(\Leftrightarrow\)-11x=13
\(\Leftrightarrow\)x=-\(\frac{13}{11}\)
Vậy...
d, 23-3. \(\left|2x+6\right|\)=-7
\(\Leftrightarrow\)3. \(\left|2x+6\right|\)=30
\(\Leftrightarrow\)\(\left|2x+6\right|\)=10
\(\Leftrightarrow\)\(\left[\begin{matrix}2x+6=10\\2x+6=-10\end{matrix}\right.\) \(\Leftrightarrow\)\(\left[\begin{matrix}x=2\\x=-8\end{matrix}\right.\)
Vậy...
\(2\left|x-20\right|=10\Leftrightarrow\left|x-20\right|=5\Leftrightarrow\left[\begin{matrix}x-20=5\\x-20=-5\end{matrix}\right.\Leftrightarrow\left[\begin{matrix}x=25\\x=15\end{matrix}\right.\)
Vậy\(x\in\left\{25;15\right\}\)
\(2.\left|x-5\right|=2^5\Leftrightarrow2.\left|x-5\right|=32\Leftrightarrow\left|x-5\right|=16\Leftrightarrow\left[\begin{matrix}x-5=16\\x-5=-16\end{matrix}\right.\)\(\Leftrightarrow\left[\begin{matrix}x=21\\x=-11\end{matrix}\right.\)Vậy\(x\in\left\{-11;21\right\}\)
\(a,2.\left(x-5\right)-3.\left(x+7\right)=14\)
\(2x-10-3x-21=14\)
\(-x-31=14\)
\(x=-31-14\)
\(x=-45\)
\(b,5.\left(x-6\right)-2\left(x+3\right)=12\)
\(5x-30-2x-6=12\)
\(3x-36=12\)
\(3x=12+36\)
\(3x=48\)
\(x=16\)
\(c,-5.\left(2-x\right)+4.\left(x-3\right)=10.x-15\)
\(-10+5x+4x-12=10x-15\)
\(-6x-22=10x-15\)
\(-6x-10x=-15+22\)
\(-16x=7\)
\(x=-\frac{7}{16}\)
Câu d , e f tương tự nha
a, (x+5)+(x-9)=x+2
\(\Leftrightarrow\)(x+5)+(x-9)-x-2=0
\(\Leftrightarrow\)x+5+x-9-x-2=0
\(\Leftrightarrow\)x-6=0
\(\Leftrightarrow\)x=6
Vậy...
b, \(\left|x+3\right|\)+\(\left|x+2\right|\)=x
\(\Leftrightarrow\)x+3+x+2=x
\(\Leftrightarrow\)x+3+x+2-x=0
\(\Leftrightarrow\)x+5=0
\(\Leftrightarrow\)x=-5
Vậy...
c, 2.\(\left|x-20\right|\)=10
\(\Leftrightarrow\)\(\left|x-20\right|\)=5
\(\Leftrightarrow\)\(\left[\begin{matrix}x-20=5\\x-20=-5\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=25\\x=15\end{matrix}\right.\)
Vậy...
d, 2.\(\left|x-5\right|\)=2\(^5\)
\(\Leftrightarrow\)2.\(\left|x-5\right|\)=32
\(\Leftrightarrow\)\(\left|x-5\right|\)=16
\(\Leftrightarrow\)\(\left[\begin{matrix}x-5=16\\x-5=-16\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=21\\x=-11\end{matrix}\right.\)
Vậy...
e, -5x+(7-15)=-6x+5
\(\Leftrightarrow\)-5x-8=-6x+5
\(\Leftrightarrow\)-5x-8+6x-5=0
\(\Leftrightarrow\)x-13=0
\(\Leftrightarrow\)x=13
Vậy...
f, 23-3.\(\left|2x+6\right|\)=-7
\(\Leftrightarrow\)3.\(\left|2x+6\right|\)=30
\(\Leftrightarrow\)\(\left|2x+6\right|\)=10
\(\Leftrightarrow\)\(\left[\begin{matrix}2x+6=10\\2x+6=-10\end{matrix}\right.\)
\(\Leftrightarrow\)\(\left[\begin{matrix}x=2\\x=-8\end{matrix}\right.\)
Vậy...
Chúc bạn học tốt!!!^^^
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