Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1a)
Có A=\(33^{44}=3^{44}\cdot11^{44}=\left(3^4\right)^{11}\cdot11^{44}\)
B= \(44^{33}=4^{33}\cdot11^{33}=\left(4^3\right)^{11}\cdot11^{33}\)
Vì \(3^4>4^3\)=> \(\left(3^4\right)^{11}>\left(4^3\right)^{11}\)
mà \(11^{44}>11^{33}\)
=> \(\left(3^4\right)^{11}+11^{44}>\left(4^3\right)^{11}+11^{33}\)
=>\(33^{44}>44^{33}\)
=> A > B
5x+1 = 125 = 53
x + 1 = 3 => x = 2
b) 3x-1 = 81 = 34
x - 1 = 4 => x= 5
c) (x - 6)2 = 9 = 32
x - 6 = 3 => x = 9
(2x - 7)2 = 169 = 132
2x - 7 = 13 => x = 10
d) x3 = 216 = 23.3
x3 = (2.3)3 = 63
Vậy x = 6
a)5x-2 - 32 = 24 - ( 28 * 24- 210 * 22 )
=> 5x-2-32=16
=> 5x-2=25
=> (5x)2=25
=> 5x=5
=> x=1
b) ( 3 * x - 24 ) * 73 = 8 * 74
=> (3.x-16)=8.74:73
=> 3x-16=56
=> 3x=72
=> x=24
c) x15 = x
=> x15:x=1
=> x14=1
=> x=1
d) ( x - 5 )4 =( x - 5 )6
=> (x-5)6:(x-5)4=1
=> (x-5)2=1
=> x-5=1
=> x=6
Bài 1 tự làm!
Bài 2:
a, \(\left(3x-4\right)\left(x-1\right)^3=0\Rightarrow\left[{}\begin{matrix}3x-4=0\\\left(x-1\right)^3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=1\end{matrix}\right.\)
b, \(2^{2x-1}:4=8^3\Rightarrow2^{2x-1}:2^2=2^9\)
\(\Rightarrow2x-1-2=9\Rightarrow2x-3=9\Rightarrow2x-12\Rightarrow x=6\)
c, Đề chưa rõ
d, \(\left(x+2\right)^5=2^{10}\Rightarrow\left(x+2\right)^5=4^5\Rightarrow x+2=4\Rightarrow x=2\)
e, \(\left(3x-2^4\right).7^3=2.7^4\Rightarrow3x-2^4=2.7^4:7^3\Rightarrow3x-16=2.7=14\)
\(\Rightarrow3x=14+16=30\Rightarrow x=\dfrac{30}{3}=10\)
f, \(\left(x+1\right)^2=\left(x+1\right)^0\Rightarrow\left(x+1\right)^2=1\) (vì x0 = 1)
\(\Rightarrow x+1=1\Rightarrow x=0\)
A, 89-(73-x)=20
73-x =89-20
73-x =69
x = 73-69
x = 4
B, 62-(2x-3):3 = 23
(2x-3):3 = 62-23
(2x-3):3 = 39
2x-3 = 39.3
2x-3 = 117
2x = 117+3
2x = 120
x = 120:2
x = 60
C, 4(x-3) = 72 - 110
4(x-3) = 49 - 1
4(x-3) = 48
x-3 = 48:4
x-3 = 12
x = 12+3
x = 15
D, 32 (x+4)-52= 5.22
9(x+4)-25 = 5.4
9(x+4)-25 = 20
9(x+4) = 20+25
9(x+4) = 45
x+4 = 45:9
x+4 = 5
x = 5-4
x = 1
(Làm có hơi dài dòng nhưng đầy đủ lắm)
a, 89-(73-x)=20 b. 62-( 2x -3): 3=23 c, 4(x-3) = 72-11o d, 32 (x+4)-52 = 5.22
(73-x)=89-20 (2x - 3 ):3 = 62-23 4(x-3)=49-1 32(x+4) - 52= 5.4=20
73-x = 69 (2x - 3): 3= 39 4(x-3) =48 32(x+4)-25 =20
x = 73-69 (2x - 3)= 39: 3 x-3 = 48 :8 32(x+4)=20+25=45
x = 4 2x -3 =13 x-3 = 6 9(x+4)=45
2x= 13 + 3 x=6+3 x+4=45:9
2x= 16 x= 9 x+4=5
x=16:2 x=5-4
x= 8 x=1
chỗ nào ko hiểu cứ hỏi mik nhé
a) \(3^{x+1}.15=135\)
\(\Rightarrow3^{x+1}=9\)
\(\Rightarrow3^{x+1}=3^2\)
\(\Rightarrow x+1=2\)
\(\Rightarrow x=1\)
Vậy \(x=1\)
b) \(x+2x+2^2x+....+2^{2016}x=2^{2017}-1\\ \Rightarrow x\left(2+2^2+...+2^{2016}\right)=2^{2017}-1\\ \Rightarrow x\left(2^{2017}-2\right)=2^{2017}-1\)
c) \(x\left(x-1\right)+\left(x-1\right)^2=0\\ \Rightarrow x\left(x-1\right)+\left(x-1\right)\left(x-1\right)=0\\ \Rightarrow\left(x-1\right)\left(x+\left(x-1\right)\right)=0\\ \Rightarrow\left(x-1\right)\left(2x-1\right)=0\\ \Rightarrow\begin{cases}x-1=0\\2x-1=0\end{cases}\)
d) \(2^2.2^5\le2^{x-5}\le2^{10}\\ \Rightarrow2^7\le2^{x-5}\le2^{10}\)
Câu quá dễ mà ko biết trả lời