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\(7-\left(11+x-13\right)\div2\frac{2}{3}=2\)
\(\left(11+x-13\right)\div2\frac{2}{3}=7-2\)
\(\left(11+x-13\right)\div2\frac{2}{3}=5\)
\(11+x-13=\frac{40}{3}\)
\(11+x=\frac{79}{3}\)
\(x=\frac{46}{3}\)
7 - ( 11 + x - 13) = 2 x 2/2/3 ( 2/2/3 là hỗn số)
7 - ( 11 + x - 13) = 16/3
( 11 + x - 13) = 7 - 16/3
11 + x - 13 = 5/3
11 + x = 5/3 + 13
11 + x = 44/3
x = 44/3 - 11
x = 11/3
(11+x-13):\(2\frac{2}{3}\)=7-2
(11+x-3):\(\frac{8}{3}\)=5
11+x-3 =5 * \(\frac{8}{3}\)
11+x-3=\(\frac{40}{3}\)
x-3=\(\frac{40}{3}\) -11=\(\frac{40}{3}\) -\(\frac{33}{3}\)
x-3=\(\frac{7}{3}\)
x=\(\frac{7}{3}\) +3=\(\frac{7}{3}\)+\(\frac{9}{3}\)
x=\(\frac{16}{3}\)=\(5\frac{1}{3}\)
7 - ( 11 + x - 13 ) = 2 x \(\frac{8}{3}\)
7 - ( 11 + x - 13 ) = \(\frac{16}{3}\)
11 + x - 13 = 7 - \(\frac{16}{3}\)
11 + x - 13 = \(1\frac{2}{3}\)
11 + x = \(1\frac{2}{3}\)+ 13
11 + x = \(14\frac{2}{3}\)
x = \(14\frac{2}{3}-11\)
x = \(3\frac{2}{3}\)
Vậy x = \(\frac{11}{3}nha\)!!!
\(\frac{1}{2}+\frac{1}{2}\times\left(50\%+\frac{1}{4}\right)\)
\(=\frac{1}{2}+\frac{1}{2}\times\left(\frac{1}{2}+\frac{1}{4}\right)\)
\(=1\times\frac{3}{4}\)
\(=\frac{3}{4}\)
1x59y chia hết cho 3 và 5
Vậy y có thể là 0 hoặc 5
Ta có 2 TH:
TH1: y = 0
\(\Rightarrow\)1x590 \(⋮\)3
\(\Rightarrow\)( 1 + x + 5 + 9 + 0 ) \(⋮\)3 = 15 + x \(⋮\)3
Vậy x \(\in\left\{0;3;6;9\right\}\)
TH2: y = 5
\(\Rightarrow\)1x595 \(⋮\)3
\(\Rightarrow\)( 1 + x + 5 + 9 + 5 ) \(⋮\)3 = 20 + x \(⋮\)3
Vậy x \(\in\left\{1;4;7\right\}\)
\(\Rightarrow x\in\left\{0;1;3;4;6;7;9\right\}\); y \(\in\left\{0;5\right\}\)
547 + ( x-2 ) x 1/3 = 1734
39/7 + ( x- 2 ) x 1/3 = 71/4
( x -2 ) x 1/3 = 71/4 - 39/7
( x -2 ) x 1/3 = 341/28
x - 2 = 341/28 : 1/3
x -2 = 341/28 x 3
x -2 = 1023/28
x = 1023/28 + 2
x = 1079/28
Bây giờ thì k cho mình nha
7 - ( 11 + x -13 ) : \(2\frac{2}{3}\) = 2
(11+ x - 13) : \(2\frac{2}{3}\) = 7-2
(11 + x - 13) : \(2\frac{2}{3}\)= 5
11 + x - 13 = 5 . \(2\frac{2}{3}\)
11 + x - 13 = \(\frac{40}{3}\)
11 + x = \(\frac{40}{3}+13\)
11 + x = \(\frac{79}{3}\)
x = \(\frac{79}{3}-11\)
x = \(\frac{46}{3}\)
\(7-\left(11+x-13\right):2\frac{2}{3}=2\)
\(7-\left(11+x-13\right)=2.2\frac{2}{3}\)
\(7-\left(11+x-13\right)=\frac{16}{3}\)
\(11+x-13=7-\frac{16}{3}\)
\(11+x-13=\frac{5}{3}\)
\(11+x=\frac{5}{3}+13\)
\(11+x=\frac{44}{3}\)
\(x=\frac{44}{3}-11\)
\(x=\frac{11}{3}\)