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a.
123-5.(x+4)=38
=>5.(x+4)=123-68
=>5.(x+4)=85
=>x+4=85:5
=>x+4=17
=>x=17-4
=>x=13
b. (3.x-24).73=2.74
=>3.x-16=2.74:73
=>3.x-16=14
=>3.x=14+16
=>3.x=30
=>x=30:3
=>x=10
a) 123 - 5 (x + 4) = 38
5 (x + 4) = 123 - 38
5 (x + 4) = 85
x + 4 = 85 : 5
x + 4 = 17
x = 17 - 4
x = 13
b) (3x - 24) . 73 = 2 . 74
3x - 24 = 2 . 74 : 73
3x - 24 = 2 . 7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
c) (x : 3 - 4) . 5 = 15
x : 3 - 4 = 15 : 5
x : 3 - 4 = 3
x : 3 = 3 + 4
x : 3 = 7
x = 7 . 3
x = 21
a) (x-51)=2.8+20 b) 4.(x-3) = 49-1 c) 2x-49=5.27 d) 9.(x+4)-25=5.4
x-51 =16+20 4.(x-30)=48 2x-49=135 9.(x+4)-25=20
x-51 =36 x-30=48:4 2x =135+49 9.(x+4) =20+25
x = 36+51 x-30= 12 2x =184 9.(x+4) =45
x = 87 x =12+30 x=42 x =184:2 x= 92 x+4 =45:9
x+4 =5
x =5-4 x=1
a: \(\Leftrightarrow\left[\left(3x+14\right):4-3\right]:2=1\)
=>(3x+14):4-3=2
=>(3x+14):4=5
=>3x+14=20
=>3x=6
hay x=2
b: \(\Leftrightarrow\left[\left(x:4+17\right):10+3\cdot16\right]:10=5\)
\(\Leftrightarrow\left(x:4+17\right):10=50-48=2\)
=>x:4+17=20
=>x:4=3
hay x=12
c: \(\Leftrightarrow2\cdot15^2+\left[2\cdot125-\left(2x+4\right)\cdot5\right]:19=453\)
\(\Leftrightarrow250-\left(2x+4\right)\cdot5=\left(453-450\right)\cdot19=57\)
=>5(2x+4)=197
=>2x+4=197/5
=>2x=177/5
hay x=177/10
d: \(\Leftrightarrow\left(19x+50\right):14=5^2-4^2=9\)
=>19x+50=126
=>19x=76
hay x=4
e: \(\Leftrightarrow2\cdot3^x=10\cdot3^{12}+8\cdot3^{12}=18\cdot3^{12}\)
\(\Leftrightarrow3^x=3^2\cdot3^{12}=3^{14}\)
hay x=14
f: \(\Leftrightarrow3\left(x+2\right):7=30\)
=>3(x+2)=210
=>x+2=70
hay x=68
g: \(2480-1570+200-x+5=1010\)
=>1115-x=1010
hay x=105
a, 123 - 5 ( x + 4 ) = 38
=> 5(x+4)=123-38
=> 5(x+4)=85
=> x+4=85:5
=>x+4=17
=>x=17-4
=>x=13
b, ( 3x - 24 ) . 73 = 2 . 74
=> (3x-16).343=4802
=> 3x-16=4802:343
=>3x-16=14
=>3x=14+16
=>3x=30
=>x=30:3
=>x=10
c, 5x+3 - 13 = 112
=> 5x+3=112+13
=>5x+3=125
=> 5x+3=53
=> x+3=3
=>x=3-3
=>x=0
Bài 2:a)<=>5(x+4) =125-38
<=>5(x+4)=87
<=>x+4=17,4
<=>x=17,4-4=13.4
b)<=> ( 3x – 24) . 73 = 2.74
<=> (3x – 16) = 2.74 : 73
<=> (3x – 16) =2.7
<=>3x – 16 = 14
<=> 3x = 30
<=> x = 10
c)=> xϵ ƯC (70, 84) và x > 8
Ta có: 70 = 2. 5. 7 => ƯCLN( 70,84) = 2. 7 = 14
84 = 22. 3. 7
=> ƯC (70, 84) = Ư(14) = { 1 ;2; 7; 14 }
Vì x > 8 => x = 14
d)=>xϵ BCNN (12, 25, 30) và 0 < x < 500
=>BC(12,25,30)=B(300) = { 0; 300; 600; …}
Vì 0 < x < 500
=> x = 300
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