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a/ \(\left(x+2\right)^2-9=0\)
<=> \(\left(x+2-3\right)\left(x+2+3\right)=0\)
<=> \(\left(x-1\right)\left(x+5\right)=0\)
<=> \(\orbr{\begin{cases}x-1=0\\x+5=0\end{cases}}\)
<=> \(\orbr{\begin{cases}x=1\\x=-5\end{cases}}\)
b/ \(x^2-2x+1=25\)
<=> \(\left(x-1\right)^2=25\)
<=> \(\orbr{\begin{cases}x-1=5\\x-1=-5\end{cases}}\)
<=> \(\orbr{\begin{cases}x=6\\x=-4\end{cases}}\)
a)
<=> 10x - 35 + 16x - 10 = 5
<=> 10x + 16x = 5 + 35 + 10
<=> 26x = 50
<=> x = 50/26 = 25/13
`a) x(x + 5)(x – 5) – (x + 2)(x^2 – 2x + 4) = 3`
`<=>x(x^2-25)-(x^3-8)=3`
`<=>x^3-25x-x^3+8=3`
`<=>-25x=-5`
`<=>x=1/5`
`b) (x – 3)^3 – (x – 3)(x^2 + 3x + 9) + 9(x + 1)^2 = 15`
`<=>x^3-9x^2+27x-27-(x^3-27)+9(x^2+2x+1)=15`
`<=>-9x^2+27x+9x^2+18x+9=15`
`<=>45x+9=15`
`<=>45x=6`
`<=>x=6/45=2/15`
`c) (x+5)(x^2 –5x +25) – (x – 7) = x^3`
`<=>x^3-125-x+7=x^3`
`<=>x^3-x-118=x^3`
`<=>-x-118=0`
`<=>-x=118<=>x=-118`
`d) (x+2)(x^2 – 2x + 4) – x(x^2 + 2) = 4 `
`<=>x^3+8-x^3-2x=4`
`<=>8-2x=4`
`<=>2x=4<=>x=2`
a. x ( x + 4 ) ( 4 - x ) + ( x - 5 ) ( x2 + 5x + 25 ) = 3
- x ( x + 4 ) ( x - 4) + x3 - 53 = 3
-x . (x2 - 42) + x3 -125 = 3
-x3 + 16x + x3 - 125 = 3
16x - 125 = 3
16x = 128
x =8
a, \(\left(x-3\right)\left(x^2+3x+9\right)-x\left(x+4\right)\left(x-4\right)=5\)
\(\Rightarrow x^3+3x^2+9x-3x^2-9x-27-x\left(x^2-16\right)=5\)
\(\Rightarrow x^3-27-x^3-16x=5\)
\(\Rightarrow-16x-27=5\)
\(\Rightarrow-16x=32\Rightarrow x=-2\)
b, \(\left(x-2\right)^3-\left(x+5\right)\left(x^2-5x+25\right)+6x^2=11\)
\(\Rightarrow x^3-6x^2+12x-8-\left(x^3-5x^2+25x+5x^2-25x+125\right)+6x^2=11\)
\(\Rightarrow x^3-6x^2+12x-8-x^3-125+6x^2=11\)
\(\Rightarrow12x-133=11\Rightarrow12x=144\Rightarrow x=12\)
Chúc bạn học tốt!!!
a)
\(\left(x-3\right)\left(x^2+3x+9\right)-x\left(x+4\right)\left(x-4\right)=5\)
\(\Rightarrow x^3-3^3-x.\left(x^2-16\right)=5\)
\(\Rightarrow x^3-27-x^3+16.x=5\)
\(\Rightarrow16x-27=5\)
\(\Rightarrow16x=32\)
\(\Rightarrow x=2\)
Vậy x = 2
b)
\(\left(x-2\right)^3-\left(x+5\right)\left(x^2-5x+25\right)+6x^2=11\)
\(\Rightarrow x^3-6x^2+12x-8-x^3-125+6x^2=11\)
\(\Rightarrow12x-133=11\)
\(\Rightarrow12x=144\)
\(\Rightarrow x=12\)
Vậy x = 12
a) \(\Rightarrow5x^2-15x=5x^2-x-10x+2-5\)
\(\Rightarrow5x^2-15x-5x^2+x+10x=2-5\)
\(\Rightarrow-4x=-3\)
\(\Rightarrow x=\frac{3}{4}\)
Vậy \(x=\frac{3}{4}\)
b) \(\Rightarrow x^2-4x-5x+20-x^2+2x-x+2=7\)
\(\Rightarrow x^2-4x-5x-x^2+2x-x=7-20-2\)
\(\Rightarrow-8x=-15\)
\(\Rightarrow x=\frac{15}{8}\)
Vậy \(x=\frac{15}{8}\)
c) \(\Rightarrow3x^2-6x-4x+8=3x^2-27x-3\)
\(\Rightarrow3x^2-6x-4x-3x^2+27x=-3-8\)
\(\Rightarrow17x=-11\)
\(\Rightarrow x=\frac{-11}{17}\)
Vậy \(x=\frac{-11}{17}\)
Chúc bạn học tốt.
x(x+4)(4-x)+(x-5)(x2+5x+25)=3
(x2+4x)(4-x)+x3+5x2+25x-5x2-25x-125=3
4x2-x3+16x-4x2+x3+5x2+25x-5x2-25x=3+125
(4x2-4x2)-(x3-x3)+(16x+25x-25x)+(5x2-5x2)=128
16x=128
x=128:16
x=8