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Bài 1:
a) \(\frac{16}{15}.\frac{\left(-5\right)}{14}.\frac{54}{24}.\frac{56}{21}\)
\(=\frac{4.2.2}{5.3}.\frac{\left(-5\right)}{2.7}.\frac{3.3}{4}.\frac{8}{3}\)
\(=\frac{4.2.2.\left(-5\right).3.3.8}{5.3.2.7.4.3}\)
\(=\frac{-16}{7}\)
b) \(\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{15}{21}.\frac{4}{\left(-5\right)}\)
\(=\frac{7}{3}.\frac{\left(-5\right)}{2}.\frac{5}{7}.\frac{2.2}{\left(-5\right)}\)
\(=\frac{7.\left(-5\right).5.2.2}{3.2.7.\left(-5\right)}\)
\(=\frac{10}{3}\)
Bài 2:
a) \(\frac{21}{24}.\frac{11}{9}.\frac{5}{7}=\frac{7}{8}.\frac{11}{9}.\frac{5}{7}=\frac{11.5}{8.9}=\frac{55}{72}\)
b) \(\frac{5}{23}.\frac{17}{26}+\frac{5}{23}.\frac{9}{26}\)
\(=\frac{5}{23}.\left(\frac{17}{26}+\frac{9}{26}\right)=\frac{5}{23}.1=\frac{5}{23}\)
c) \(\left(\frac{3}{29}-\frac{1}{5}\right).\frac{29}{3}=\frac{3}{29}.\frac{29}{3}-\frac{1}{5}.\frac{29}{3}\)
\(=1-1\frac{14}{15}=\frac{14}{15}\)
Bài 3:
a) x/5 = 2/5
=> x =2
b) -4/x = 20/14 = 10/7
=> -4/x = 10/7
=> x.10 = (-4).7
x.10 = - 28
x= -28 :10
x= -2,8
c) 4/7 = 12/x = 12/ 21
=> 12/x = 12/21
=> x = 21
d) 3/7 = x / 21 = 9/21
=> x/21 = 9/21
=> x= 9
a, 2 . (x - 5) = -24 b, 2 . (x - 5) - 7 = 13
2.x - 2.5 = -24 2 . x - 10 - 7 = 13
2.x - 10 = -24 2 . x - 17 = 13
2.x = -24 + 10 = -14 2.x = 13 + 17 = 30
x = -14 : 2 = -7 x = 30 : 2 = 15
c, 5 . ( 3 - x) + 2 . (x - 7) = -14 d, 12 . (x - 5) + 7 . (3 - x) = 5
15 - 5.x + 2.x - 14 = -14 12.x - 60 + 21 - 7.x = 5
- 3.x + 1 = -14 5.x - 39 = 5
-3 . x = -14 - 1 = -15 5.x = 5 + 39 = 44
x = -15 : ( -3) = 5 x = 44 : 5 = 8,8
e, 30 . ( x + 2) - 6 . ( x - 5 ) - 24 . x = 160
30 . x + 60 - 6x + 30 - 24.x = 160
30. x - 30 .x +90 = 160
0 .x = 160 - 90 = 70
Vậy không có x
a) 2 . (x - 5) = -24
(x - 5) = -24 : 2 = -12
x = -12 + 5
x = -7
b) 2. (x - 5) - 7 = 13
2 . (x - 5) = 13 + 7
2 . (x - 5) = 20
x - 5 = 20 : 2 = 10
x = 10 + 5 = 15
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a) \(\frac{x}{6}=\frac{5}{24}\Rightarrow x=\frac{5}{24}.6=\frac{5}{4}\)
b) \(-\frac{4}{y}=\frac{20}{14}\Rightarrow y=-4:\frac{20}{14}=-\frac{14}{5}\)
c) \(\frac{4}{7}=\frac{12}{x}\Rightarrow x=12:\frac{4}{7}=21\)
d) \(\frac{3}{7}=\frac{y}{21}\Rightarrow y=\frac{3}{7}.21=9\)
Bài 1:
a) |x-2|+(-3)=-1
|x-2| =-1+3
|x-2| =2
=> x-2=2 hoặc x-2=-2
x =2+2 x =-2+2
x =4 x =0
Vậy x=4 hoặc x=0
b)|3-x|-(-14)=25
|3-x|=25+(-14)
|3-x|=11
=>3-x=11 hoặc 3-x=-11
x=3-11 x=3-(-11)
x=-8 x=14
Vậy x=-8 hoặc x=14
Các câu c,d làm tương tự nha, mk ko phải làm hộ cho bạn chép đâu!
Quy luật tìm x với |x|=a suy ra x=a hoặc x=-a (a thuộc N*)
VD: |2-x|=1 => 2-x=1 hoặc -1
Chú ý: |-2|=2 ; |2|=2 . Vì thế công thức trên chỉ áp dụng cho tìm số chưa biết.
Bài 2:
a) |12-x|-|-23|=-19
|12-x|-23 =-19
|12-x| =-19+23
|12-x| =4
=>12-x=4 hoặc 12-x=-4
x=12-4 x=12-(-4)
x=8 x=16
Vậy x=8 hoặc x=16
b) 6-|x+1|=(-4)+|-10|
6-|x+1|=(-4)+10
6-|x+1|=6
|x+1|=6-6
|x+1|=0
=> x+1=0 (ko có TH2 vì làm gì có ''-0'')
x =0-1
x =-1
Câu nào ko đúng thì ... thông cảm, mk làm như để tự ôn thi thôi <3
a) \(x=\frac{7}{25}+\frac{-1}{5}\)
\(\Rightarrow x=\frac{2}{25}\)
Vậy \(x=\frac{2}{25}\)
b) \(x=\frac{5}{11}+\frac{4}{-9}\)
\(\Rightarrow x=\frac{1}{99}\)
Vậy \(x=\frac{1}{99}\)
c) \(\frac{5}{9}+x=\frac{-1}{3}\)
\(\Rightarrow x=\frac{-1}{3}-\frac{5}{9}\)
\(\Rightarrow x=\frac{-8}{9}\)
Vậy \(x=\frac{-8}{9}\)
d) \(\frac{3}{4}-x=-1\)
\(\Rightarrow x=\frac{3}{4}-\left(-1\right)\)
\(\Rightarrow x=\frac{7}{4}\)
Vậy \(x=\frac{7}{4}\)
e) \(x+4=\frac{1}{5}\)
\(\Rightarrow x=\frac{1}{5}-4\)
\(\Rightarrow x=\frac{-19}{5}\)
Vậy \(x=\frac{-19}{5}\)
f) \(x-\frac{1}{5}=2\)
\(\Rightarrow x=2+\frac{1}{5}\)
\(\Rightarrow x=\frac{11}{5}\)
Vậy \(x=\frac{11}{5}\)
g) \(x+\frac{5}{3}=\frac{1}{81}\)
\(\Rightarrow x=\frac{1}{81}-\frac{5}{3}\)
\(\Rightarrow x=\frac{-134}{81}\)
Vậy \(x=\frac{-134}{81}\)
_Chúc bạn học tốt_
a) 10+2x=45:43
10+2x=42
10+2x=16
2x=16-10
2x=6
x=6:2
x=3
vậy x=3
b)130-(100+x)=25
100+x=130-25
100+x=105
x=105-100
x=5
vậy x=5
c)22.(x+32)-5=55
4.(x+9)=55+5
x+9=60:4
x+9=15
x=15-9
x=6
vậy x=9
d)72-7(13-x)=14
49-7(13-x)=14
7(13-x)=49-14
13-x=35:7
13-x=5
x=13-5
x=8
vậy x=8
\(\frac{4}{5}\)+ \(\frac{1}{5}\): \(\frac{-2}{15}\)= \(\frac{4}{5}\)+ \(\frac{1}{5}\)* \(\frac{-15}{2}\)=\(\frac{4}{5}\) + \(\frac{-3}{2}\)= \(\frac{-7}{10}\)
b = \(\frac{-7}{12}\). (\(\frac{3}{11}\)+ \(\frac{-14}{11}\)) + \(\frac{5}{6}\)= \(\frac{-7}{12}\). (-1) + \(\frac{5}{6}\)= \(\frac{7}{12}\)+ \(\frac{10}{12}\)= \(\frac{17}{12}\)
\(a,\frac{x}{6}=\frac{5}{24}\)
\(\Rightarrow\frac{4x}{24}=\frac{5}{24}\)
\(\Rightarrow4x=5\)
\(\Rightarrow x=\frac{5}{4}\)
\(b,\frac{-4}{x}=\frac{20}{14}\)
\(\Rightarrow\left(-4\right).14=20.x\)
\(\Rightarrow-56=20x\)
\(\Rightarrow x=-56\div20\)
\(\Rightarrow x=\frac{-14}{5}\)
\(c,\frac{4}{7}=\frac{12}{x}\)
\(\Rightarrow4.x=12.7\)
\(\Rightarrow4x=84\)
\(\Rightarrow x=84\div4\)
\(\Rightarrow x=21\)
\(d,\frac{3}{7}=\frac{x}{21}\)
\(\Rightarrow3.21=7.x\)
\(\Rightarrow63=7x\)
\(\Rightarrow x=63\div7\)
\(\Rightarrow x=9\)