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a, x + 1/3 = 3/4
- > x = 3/4 - 1/3 = 5/12
b, x - 2/5 = 5/4
-> x = 5/4 + 2/5 = 33/20
c, -x - 2/3 = 6/7
-> -x = 6/7 + 2/3 = 32/21
-> x = -32/21
d, 4/7 - x = 1/3
x = 4/7 - 1/3 = 5/21
a) x+1/3= 3/4
x= 3/4 - 1/3
x= 5/12
b) x-2/5 = 5/4
x= 5/4 + 2/5
x = 33 / 20
c) -x - 2/3 = 6/7
-x = 6/7 + 2/3
-x = 32/21 => x = -32/21
d) 4/7 -x = 1/3
x= 4/7 -1/3
x = 5/21
bài 1
Gọi số cần tìm là a
Theo bài ra ta có:
a chia 17 dư 8
a chia 25 dư 16
=> a + 9 chia hết cho 17 và 25
=> a + 9 là BC(17;25)
*17=17
25=5^2
*Thừa số nguyên tố chung và riêng 17;5
BCNN(17;25) = 425
=> BC(17;25) =B(425)= ( 0 ;425 ; 850 ; 1275 ; ...)
=> a +9 thuộc ( 0 ; 425 ; 850 ; 1275 ;.. .)
=> a thuộc ( -9 ; 416 ; 841 ; 1266; ... )
Vì a là số có ba chữ số => a = 416 ; 841
a) \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
\(\Rightarrow\orbr{\begin{cases}\frac{3}{2}x+\frac{1}{2}=4x-1\\\frac{3}{2}x+\frac{1}{2}=-4x+1\end{cases}}\Rightarrow\orbr{\begin{cases}4x-\frac{3}{2}x-1=\frac{1}{2}\\-4x-\frac{3}{2}x+1=\frac{1}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}\frac{5}{2}x=\frac{3}{2}\\-\frac{11}{2}x=-\frac{1}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{3}{5}\\x=\frac{1}{11}\end{cases}}\)
phần b ở đề bài mình ghi sai, là bằng 0 chứ ko phải bằng 10
5) // 3x + 1 / - 5 / = 2
=> / 3x + 1 / -5 = 2 hoặc -2
TH1: / 3x + 1 / - 5 = 2 => / 3x + 1 / = 2 + 5 = 7 => 3x + 1 = 7 hoặc -7
*1: 3x + 1 = -7 => 3x = -7 - 1 = -8 => x = -8/3
*2: 3x + 1 = 7 => 3x = 7 - 1 = 6 => x = 6 : 3 = 2
TH2: / 3x + 1 / - 5 = -2 => / 3x + 1/ = -2 + 5 = 3 => 3x + 1 = 3 hoặc -3
*1: 3x + 1 = 3 => 3x = 3 - 1 = 2 => x = 2/3
*2: 3x + 1 = -3 => 3x = -3 - 1 = -4 => x = -4/3
Vậy x thuộc { -8/3 ; 2 ; 2/3 ; -4/3 }
7) 3/2 + 4/5 /x - 3/4 / = 7/4
=> 4/5 / x - 3/4 / = 7/4 - 4/5
=> 4/5 / x - 3/4 / = 19/20
=> / x - 3/4 / = 19/20 : 4/5
=> / x - 3/4 / = 19/16
=> / x - 3/4 / = 19/16 hoặc -19/16
a)x=\(\frac{5}{12}\)
b)x=\(\frac{39}{35}\)
c)-x=-\(\frac{4}{21}\)
x=\(\frac{4}{21}\)
a) \(\frac{x}{x+1}=\frac{x+5}{x+7}\)
\(=>x\left(x+7\right)=\left(x+1\right).\left(x+5\right)\)
\(=>x^2+7x=x^2+6x+5\)
\(=>x^2+7x-x^2-6x-5=0\)
\(=>x-5=0\)
\(=>x=5\)
vay \(x=5\)
b) \(\frac{x+7}{x+4}=\frac{x-1}{x-2}\)
\(=>\left(x+7\right)\left(x-2\right)=\left(x+4\right)\left(x-1\right)\)
\(=>x^2+5x-14=x^2+3x-4\)
\(=>x^2+5x-14-x^2-3x+4=0\)
\(=>2x-10=0\)
\(=>2\left(x-5\right)=0\)
\(=>x-5=0\)
\(=>x=5\)
vay \(x=5\)
c) \(\frac{x+2}{x-2}=\frac{x-3}{x+3}\)
\(=>\left(x+2\right)\left(x+3\right)=\left(x-2\right)\left(x-3\right)\)
\(=>x^2+5x+6=x^2-7x+6\)
\(=>x^2+5x+6-x^2+7x-6=0\)
\(=>12x=0\)
\(=>x=0\)
vay \(x=0\)
tìm x biết
x-1/2=-2/3
\(x-\frac{1}{2}=-\frac{2}{3}\)
\(x=\frac{-2}{3}-\frac{1}{2}=\frac{-1}{6}\)
2/7-x=-3/4
\(\frac{2}{7}-x=-\frac{3}{4}\)
\(x=\frac{2}{7}-\left(-\frac{3}{4}\right)=\frac{29}{28}\)
a)Ta có: |x-5/4|-|x+2/3|=0
=>|x-5/4|=|x+2/3|
*Xét x>_5/4=>x-5/4>_0=>|x-5/4|=x-5/4
=>x+2/3>0=>|x+2/3|=x+2/3
=>|x-5/4|=|x+2/3|
=>x-5/4=x+2/3
=>x-x=2/3+5/4
=>0=23/12
=>Vô lí
*Xét -2/3<_x<5/4=>x-5/4<0=>|x-5/4|=5/4-x
=>x+2/3>_0=>|x+2/3|=x+2/3
=>|x-5/4|=|x+2/3|
=>5/4-x=x+2/3
=>5/4-2/3=x+x
=>7/12=2x
=>x=7/24
*Xét x<-2/3=>x-5/4<0=>|x-5/4|=5/4-x
=>x+2/3<0=>|x+2/3|=-x-2/3
=>|x-5/4|=|x+2/3|
=>5/4-x=-x-2/3
=>x-x=5/4+2/3
=>0=23/12
=>Vô lí
Vậy x=7/24
\(a,x.\frac{-3}{7}=\frac{4}{21}\)
\(x=\frac{4}{21}:\frac{-3}{7}\)
\(x=\frac{-4}{9}\)
\(b,\frac{-4}{7}:x=\frac{2}{5}\)
\(x=\frac{-4}{7}:\frac{2}{5}\)
\(x=\frac{-10}{7}\)
\(c,x+\frac{1}{12}=\frac{-3}{8}\)
\(x=\frac{-3}{8}-\frac{1}{12}\)
\(x=\frac{-11}{24}\)
\(d,\frac{2}{15}-x=\frac{-3}{10}\)
\(x=\frac{2}{15}+\frac{3}{10}\)
\(x=\frac{13}{30}\)
\(e,-x+\frac{4}{5}=\frac{1}{2}\)
\(-x=\frac{-3}{10}\)
\(x=\frac{3}{10}\)
\(f,\frac{3}{4}.\left(x+1\right)-\frac{1}{2}=\frac{3}{7}\)
\(\frac{3}{4}.\left(x+1\right)=\frac{13}{14}\)
\(x+1=\frac{26}{21}\)
\(x=\frac{5}{21}\)
\(\frac{-3}{2}-2x+\frac{3}{4}=-2\)
\(\frac{-3}{2}-2x=\frac{-11}{4}\)
\(2x=\frac{-3}{2}+\frac{11}{4}\)
\(2x=\frac{-17}{4}\)
\(x=\frac{-17}{8}\)
\(h,-x+\frac{4}{5}=\frac{1}{2}\)
\(-x=\frac{-3}{10}\)
\(x=\frac{3}{10}\)
chúc bạn học tốt !!!
\(\dfrac{x-3}{x-2}\) = \(\dfrac{4}{7}\)
⇒ (x - 3) x 7 = (x - 2) x 4
⇒ 7x - 21 = 4x - 8
⇒ 7x - 4x = 21 - 8
⇒ 3x = 13
⇒ x = \(\dfrac{13}{3}\)
x = 13/3