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b) \(\left(x-\dfrac{2}{9}\right)^3=\left(\dfrac{2}{3}\right)^6\)
\(\Rightarrow\left(x-\dfrac{2}{9}\right)^3=\left[\left(\dfrac{2}{3}\right)^2\right]^3=\left(\dfrac{4}{9}\right)^3\)
\(\Rightarrow x-\dfrac{2}{9}=\dfrac{4}{9}\)
\(\Rightarrow x=\dfrac{2}{3}\)
Tìm x biết:
\(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
\(\left(8x-1\right)^{2n+1}=5^{2n+1}\)
(x-7)x+1-(x-7)x+11=0
=>x-7=0
=>x=7
(8x-1)2n+1=52n+1
=>8x-1=5
=>8x=6
=>x=3/4
Tick Đúng Nha
1.
a) \(x\in\left\{4;5;6;7;8;9;10;11;12;13\right\}\)
b) x=0
d) \(x=\frac{-1}{35}\) hoặc \(x=\frac{-13}{35}\)
e) \(x=\frac{2}{3}\)
a) \(\left(5x+1\right)^2=\dfrac{36}{49}\)
\(\left(5x+1\right)^2=\left(\pm\dfrac{6}{9}\right)\)\(^2\)
\(5x+1=\pm\dfrac{6}{9}\)
+) \(5x+1=\dfrac{6}{9}\)
\(5x=\dfrac{6}{9}-1=\dfrac{6}{9}-\dfrac{9}{9}\)
\(5x=\dfrac{-5}{9}\)
\(x=\dfrac{-5}{9}:5=\dfrac{-1}{45}\)
+) \(5x+1=\dfrac{-6}{9}\)
\(5x=\dfrac{-6}{9}-1=\dfrac{-6}{9}-\dfrac{9}{9}\)
\(5x=\dfrac{-5}{3}\)
\(x=\dfrac{-5}{3}:5=\dfrac{-5}{15}\)
vậy \(x\in\left\{\dfrac{-5}{15};\dfrac{-1}{45}\right\}\)
a: =>5x+1=6/7 hoặc 5x+1=-6/7
=>5x=-1/7 hoặc 5x=-13/7
=>x=-1/35 hoặc x=-13/35
b: =>x-2/9=4/9
=>x=6/9=2/3
c: =>8x+1=5
=>8x=4
hay x=1/2
\(\left(x+3\right)^{2n+1}=\left(2x-3\right)^{2n+1}\)
\(\Rightarrow\left(x+3\right)=\left(2x-3\right)\)
\(\Rightarrow x+3=2x-3\)
\(\Rightarrow x+3-2x+3=0\)
\(\Rightarrow-x+6=0\)
\(\Rightarrow x=6\)
Vậy x=6
\(\left(x+3\right)^{2n+1}=\left(2x-3\right)^{2n+1}\)
\(\Rightarrow x+3=2x-3\)
\(x+3-2x+3=0\)
\(\left(x-2x\right)+\left(3+3\right)=0\)
\(-x+6=0\)
\(-x=0-6\)
\(-x=-6\)
\(\Rightarrow x=6\)
Vậy \(x=6\).