Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,\left(1+3x\right)^4=256\)
\(\left(1+3x\right)^4=4^4\)
\(\Rightarrow\orbr{\begin{cases}1+3x=4\\1+3x=-4\end{cases}}\Rightarrow\orbr{\begin{cases}3x=3\\3x=-5\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\x=\frac{-5}{3}\end{cases}}\)
\(b,720:\left(x-140\right)=3^3-2^3.4\)
\(720:\left(x-140\right)=-5\)
\(x-140=720:\left(-5\right)\)
\(x-140=-144\)
\(x=-4\)
\(c,16^x.4^3=512\)
\(\left(2^4\right)^x=8\)
\(2^{4x}=2^3\)
\(\Rightarrow4x=3\)
\(\Rightarrow x=\frac{3}{4}\)
\(d,\left(2x-1\right)^4=81\)
\(\left(2x-1\right)^4=3^4\)
\(\Rightarrow\orbr{\begin{cases}2x-1=3\\2x-1=-3\end{cases}}\Rightarrow\orbr{\begin{cases}2x=4\\2x=-2\end{cases}}\Rightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)
Bài làm :
\(1\text{)}...\Leftrightarrow\orbr{\begin{cases}\left(1+3x\right)^4=4^4\Leftrightarrow1+3x=4\Leftrightarrow3x=3\Leftrightarrow x=1\\\left(1+3x\right)^4=\left(-4\right)^4\Leftrightarrow1+3x=-4\Leftrightarrow3x=-5\Leftrightarrow x=-\frac{5}{3}\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=1\\x=-\frac{5}{3}\end{cases}}\)
\(2\text{)}...\Leftrightarrow720\div\left(x-140\right)=-5\Leftrightarrow x-140=-144\Leftrightarrow x=-4\)
\(3\text{)}...\Leftrightarrow\left(2^4\right)^x.\left(2^2\right)^3=2^9\Leftrightarrow2^{4x}.2^6=2^9\Leftrightarrow2^{4x}=2^3\Leftrightarrow4x=3\Leftrightarrow x=\frac{3}{4}\)
\(4\text{)}...\Leftrightarrow\orbr{\begin{cases}\left(2x-1\right)^4=3^4\Leftrightarrow2x-1=3\Leftrightarrow2x=4\Leftrightarrow x=2\\\left(2x-1\right)^4=\left(-3\right)^4\Leftrightarrow2x-1=-3\Leftrightarrow2x=-2\Leftrightarrow x=-1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-1\end{cases}}\)
6x . 6 = 2016
6x = 2016 : 6
6x = 336
=> x \(\in\varnothing\)
42x+3 : 4 = 256
42x+3 = 256 x 4
42x+3 = 1024
42x+3 = 45
2x + 3 = 5
2x = 5 - 3
2x = 2
x = 2 : 2
x = 1
[ x - 2 ]2 = 16
[ x - 2 ]2 = 42
x - 2 = 4
x = 4 + 2
x = 6
[ 2x - 1 ]3 = 27
[ 2x - 1 ]3 = 33
2x - 1 = 3
2x = 3 + 1
2x = 4
x = 4 : 2
x = 2
[ 2x - 1 ]100 = [ 2x - 1 ]100
=> x \(\in N\)
a: \(\Leftrightarrow2x+7=-4\)
=>2x=-11
hay x=-11/2
b: \(\Leftrightarrow\dfrac{7^x\cdot49+7^x\cdot7+7^x}{57}=\dfrac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
\(\Leftrightarrow7^x=5^{2x}\)
=>x=0
a) (2x-1)5 = 2x-1
=> (2x-1)5 - (2x-1) = 0
(2x-1).[(2x-1)4 -1]=0
=> 2x-1 =0 => 2x = 1=> x = 1/2
(2x-1)4 - 1= 0 => (2x-1)4 = 1 = 14 = (-1)4
=> 2x-1= 1 => 2x = 2 => x = 1
2x -1 = -1 => 2x = 0 => x = 0
KL:...
b) 25x.43 = 169
25x = (42)9:43
25x = 418:43
25x = 415 = (22)15 = 230
=> 5x = 30 => x = 6
c) 3x+1+4.3x = 7.36
3x.3+4.3x = 5013
3x.(3+4) = 5013
3x.7 = 5013
3x = 729 = 36
=> x = 6