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Giải:
a) \(\dfrac{3}{-5}=2.\dfrac{x-2}{15}\)
\(\Leftrightarrow\dfrac{-3}{5}=\dfrac{2\left(x-2\right)}{15}\)
\(\Leftrightarrow-3.15=5.2\left(x-2\right)\)
\(\Leftrightarrow-45=10x-20\)
\(\Leftrightarrow-45+20=10x\)
\(\Leftrightarrow-25=10x\)
\(\Leftrightarrow x=-\dfrac{25}{10}=-\dfrac{5}{2}\)
Vậy ...
b) \(\dfrac{2\left(x-2\right)}{5}=\dfrac{3\left(2-3x\right)}{7}\)
\(\Leftrightarrow2.7\left(x-2\right)=5.3\left(2-3x\right)\)
\(\Leftrightarrow14\left(x-2\right)=15\left(2-3x\right)\)
\(\Leftrightarrow14x-28=30-45x\)
\(\Leftrightarrow14x+45x=30+28\)
\(\Leftrightarrow59x=58\)
\(\Leftrightarrow x=\dfrac{58}{59}\)
Vậy ...
Câu 1 :
a, 8.( -5 ).( -4 ).2
= [ 8.2 ].[( -5 ).(-4 ]
= 16.20
= 320
b, \(1\frac{3}{7}+\frac{-1}{3}+2\frac{4}{7}\)
\(=\frac{10}{7}+\frac{-1}{3}+\frac{18}{7}\)
\(=\frac{11}{3}\)
c, \(\frac{8}{5}.\frac{2}{3}+\frac{-5.5}{3.5}\)
\(=\frac{8}{3}+\frac{-5}{3}\)
\(=\frac{3}{3}=1\)
d, \(\frac{6}{7}+\frac{5}{8}:5-\frac{3}{16}.\left(-2\right)^2\)
\(=\frac{6}{7}+\frac{1}{8}-\frac{3}{16}.4\)
\(=\frac{55}{56}-\frac{3}{4}\)
\(=\frac{13}{56}\)
Câu 2 :
a, 2x + 10 = 16
2x = 16 + 10
2x = 26
x = 26 : 2
x = 13
b, \(x-\frac{1}{3}=\frac{5}{4}\)
\(x=\frac{5}{4}+\frac{1}{3}\)
\(x=\frac{19}{12}\)
c, \(2x+3\frac{1}{3}=7\frac{1}{3}\)
\(2x+\frac{10}{3}=\frac{22}{3}\)
\(2x=\frac{22}{3}-\frac{10}{3}\)
\(2x=4\)
\(x=4:2\)
\(x=2\)
d, \(\left(\frac{2}{11}+\frac{1}{3}\right)x=\left(\frac{1}{7}-\frac{1}{8}\right).56\)
\(\frac{17}{33}x=1\)
\(x=1-\frac{17}{33}\)
\(x=\frac{16}{33}\)
a)x\(\in\){8;18} và y\(\in\){7;2}
b)x=6
c)x=-5; y=-3
d)x=7
e)x=4
Dễ vậy!
ok
=>\(\hept{\begin{cases}x=0\\x-5=0\end{cases}}\Rightarrow\hept{\begin{cases}x=0\\x=5\end{cases}}\)
b)
\(\Rightarrow\orbr{\begin{cases}x+2=0\\x-7=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-2\\x=7\end{cases}}\)
\(-5\left(-x+7\right)-3\left(-x-5\right)=-4\left(12-x\right)+48\)
\(5x-35+3+15=-48+4x+48\)
\(5x-4x=-48+48+35-3-15\)
\(x=17\)
-5.(-x+7)-3.(-x-5)=-4.(12-x)+48
5x+(-35)-(-3x)-15=(-48)-(-4x)+48
5x+(-35)+3x-15=(-48)+4x+48
8x+(-50)=4x
8x-4x=50
4x=50
x =50:4
x =12,5\(\notin Z\)
Vậy x\(\in\varnothing\)
Chúc bn học tốt
\(2^5.x-2^3.x+x=\left(7^5:7^5\right).2\)
\(\Rightarrow32.x-8.x+x=1.2\)
\(\Rightarrow\left(32-8+1\right).x=2\)
\(\Rightarrow25.x=2\)
\(\Rightarrow x=2:25\)
\(\Rightarrow x=\frac{2}{25}\)
Vậy \(x=\frac{2}{25}\)