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Ta có: \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+...+\frac{2}{18.19}+\frac{2}{19.20}=2.\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{18.19}+\frac{1}{19.20}\right)\)
\(=2.\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}\right)\)
\(=2.\left(1-\frac{1}{20}\right)=\frac{2.19}{20}=\frac{19}{10}\)
\(\frac{2}{1\times2}+\frac{2}{2\times3}+......+\frac{2}{19\times20}\)
\(=2\left(\frac{1}{1\times2}+\frac{1}{2\times3}+.......+\frac{1}{19\times20}\right)\)
\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+........+\frac{1}{19}-\frac{1}{20}\right)\)
\(=2\left(1-\frac{1}{20}\right)=2.\frac{19}{20}=\frac{19}{10}\)
=\(\frac{2001x2004x1001x2006}{2004x2006x2001x2002}\)=\(\frac{1}{2}\)
\(=\frac{2001.2004.1001.2002}{2004.2006.2001.2002}=\frac{1.1.1001.1}{1.2006.1.1}=\frac{1001}{2006}\)
=>3/6+4/6<x<16/4-5/4 K NHA MOI NGUOI
=>7/6<x<11/4
=>28/24<x<66/24
=>x=48/24=2
\(\overline{abc}\times9=\overline{1abc}\Leftrightarrow9\overline{abc}=1000+\overline{abc}\Leftrightarrow8\overline{abc}=1000\Leftrightarrow\overline{abc}=125.\)
abc x 9 = 1abc
abc x 9 = 1000 + abc
abc x 9 - abc = 1000
abc x ( 9-1 ) = 1000
abc x 8 = 1000
abc = 1000 : 8
abc = 125
Ta có:
11/32 > 11/33 = 1/3 = 9/27 > 9/28
=> 11/32 > 9/28
Vậy 9/28 < 11/32
x=4
Nhớ k mình nha
x0x03 + x030x + 30x0x = 111111
x0x00 + 3 + x000x + 300 + x0x + 30000 = 111111
30303 + x . 10100 + x . 10001 + x . 101 = 111111
30303 + x . ( 10100 + 10001 + 101 ) = 111111
30303 + x . 20202 = 111111
x . 20203 = 111111 - 30303
x . 20203 = 80808
x = 80808 : 20202
x = 4
x = 4
( . là dấu nhân)