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a) \(-x+821+534=499+\left(x-84\right)\)
\(-x-x=499-84-821-534\)
\(-2x=-940\)
\(x=470\)
b) \(x-96=\left(448-x\right)-150\)
\(x+x=448-150+96\)
\(2x=394\)
\(x=197\)
c) \(-\left(754+x\right)=\left(x-12-741\right)-23\)
\(-754-x=x-12-741-23\)
\(-x+x=-12-741-23+754\)
\(0x=2\)
\(x\)ko tồn tại
d) \(\left(6+x\right)-\left(17-21\right)=-25\)
\(6+x-17+21=-25\)
\(x=-25-6+17-21\)
\(x=-35\)
e) \(17-\left(x+2\right)=3\)
\(17-x-2=3\)
\(-x=3-17+2\)
\(-x=-12\)
\(x=12\)
h) \(-10-\left(31-x\right)=40\)
\(-10-31+x=40\)
\(x=40+10+31\)
\(x=81\)
k mk nha bạn
a) \(-x+821+534=499+\left(x-84\right)\)
\(\Leftrightarrow-x+821+534=499+x-84\)
\(\Leftrightarrow821+534-499+84=x+x\)
\(\Leftrightarrow940=2x\)
\(\Leftrightarrow x=\dfrac{940}{2}\)
\(\Leftrightarrow x=470\)
Vậy \(x=470\)
b) \(x-96=\left(448-x\right)-150\)
\(\Leftrightarrow x-96=448-x-150\)
\(\Leftrightarrow x+x=96+448-150\)
\(\Leftrightarrow2x=394\)
\(\Leftrightarrow x=\dfrac{394}{2}\)
\(\Leftrightarrow x=197\)
Vậy \(x=197\)
c) \(- (754 + x) = (x - 12 - 741) - 23\)
\(\Leftrightarrow-754-x=x-12-741-23\)
\(\Leftrightarrow-754+12+741+23=x+x\)
\(\Leftrightarrow22=2x\)
\(\Leftrightarrow x=\dfrac{22}{2}\)
\(\Leftrightarrow x=11\)
Vậy \(x=11\)
d) \((6 + x) - (17 - 21) = -25\)
\(\Leftrightarrow6+x-17+21=-25\)
\(\Leftrightarrow x=-25-6+17-21\)
\(\Leftrightarrow x=-35\)
Vậy \(x=-35\)
e) \(17-\left(x+2\right)=3\)
\(\Leftrightarrow17-x-2=3\)
\(\Leftrightarrow17-2-3=x\)
\(\Leftrightarrow x=12\)
Vậy \(x=12\)
h) \(-10 - (31 - x) = 40\)
\(\Leftrightarrow-10-31+x=40\)
\(\Leftrightarrow x=40+10+31\)
\(\Leftrightarrow x=81\)
Vậy \(x=81\)
1
\(\left(x-2\right):2.3=6\)
\(\Leftrightarrow\left(x-2\right):2=2\)
\(\Leftrightarrow\left(x-2\right)=4\)
\(\Leftrightarrow x=4+2=6\)
c) ta có
\(\left[\left(2x+1\right)+1\right]m:2=625\)
\(\Leftrightarrow\left[\left(2x+1\right)+1\right]\left\{\left[\left(2x+1\right)-1\right]:2+1\right\}=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-1:2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2+1=1250\)
\(\Leftrightarrow\left(2x+1\right)^2+1-2=1249\)
\(\Leftrightarrow\left(2x+1\right)^2+1=1251\)
\(\Leftrightarrow\left(2x+1\right)^2=1250\)
...
2
\(\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{7}{4}-\frac{1}{2}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right).\frac{5}{3}=\frac{5}{4}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}:\frac{5}{3}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{5}{4}.\frac{3}{5}\)
\(\Leftrightarrow x-\frac{1}{2}=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}+\frac{1}{2}=\frac{5}{4}\)
a) 2.(x-1/3) - (x-1/2) = 1/2.x
2.x - 2/3 - x + 1/2 = 1/2.x
=> 2.x-x - 1/2.x = 2/3 -1/2
1/2.x = 1/6
x = 1/3
bài b bn làm tương tự nha