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\(\frac{28}{x+4}=\frac{36}{63}=\frac{4}{7}\Leftrightarrow\frac{7.28}{7\left(x+4\right)}=\frac{4\left(x+4\right)}{7\left(x+4\right)}\)
=> 4(x+4) = 7.28
=> 4x + 16 = 196
=> 4x = 180
=> x = 4 5
\(\Rightarrow28\left(x-9\right)=20.35\Rightarrow28x-252=700\Rightarrow28x=952\Rightarrow x=34\)
\(\frac{x-9}{35}=\frac{20}{28}=\frac{5}{7}=\frac{25}{35}\)
=>x-9=25
=>x=25+9
=>x=34
vậy x=34
\(\frac{x}{7}x\frac{4}{9}x5=\frac{3x4x5}{7x9}\)
\(\frac{x}{7}x\frac{4}{9}x5=\frac{20}{21}\)
\(\frac{x}{7}x\frac{4}{9}=\frac{20}{21}:5\)
\(\frac{x}{7}x\frac{4}{9}=\frac{4}{21}\)
\(\frac{x}{7}\) \(=\frac{4}{21}:\frac{4}{9}\)
\(\frac{x}{7}\) \(=\frac{9}{21}\) \(=\frac{3}{7}\)
Vay x la 3
a) \(x\times\frac{9}{13}=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{9}{13}\)
\(x=\frac{65}{54}\)
b) \(\frac{7}{9}+\frac{5}{x}=\frac{73}{36}\)
\(\frac{5}{x}=\frac{73}{36}-\frac{7}{9}\)
\(\frac{5}{x}=\frac{5}{4}\)
\(x=5:\frac{5}{4}\)
\(x=4\)
\(\frac{2}{7}:y=\frac{10}{21}.\frac{9}{14}\)
\(\frac{2}{7}:y=\frac{15}{49}\)
\(y=\frac{2}{7}:\frac{15}{49}\)
\(y=\frac{2}{7}.\frac{49}{15}\)
\(y=\frac{14}{15}\)
\(y-\frac{1}{3}=\frac{10}{21}:\frac{15}{28}\)
\(y-\frac{1}{3}=\frac{10}{21}.\frac{28}{15}\)
\(y-\frac{1}{3}=\frac{8}{9}\)
\(y=\frac{8}{9}+\frac{1}{3}\)
\(y=\frac{8}{9}+\frac{3}{9}\)
\(y=\frac{11}{9}\)
a) Ta có : \(y-\frac{1}{3}=\frac{10}{21}\div\frac{15}{28}\)
\(\Rightarrow\) \(y-\frac{1}{3}=\frac{8}{9}\)
\(\Rightarrow\) \(y\) \(=\frac{8}{9}+\frac{1}{3}\)
\(\Rightarrow\) \(y\) \(=\frac{11}{9}\)
Vậy \(y=\frac{11}{9}\)
b) Ta có : \(\frac{2}{7}\div y=\frac{10}{21}\times\frac{9}{14}\)
\(\Rightarrow\) \(\frac{2}{7}\div y=\frac{15}{49}\)
\(\Rightarrow\) \(y=\frac{2}{7}\div\frac{15}{49}\)
\(\Rightarrow\) \(y=\frac{14}{15}\)
Vậy \(y=\frac{14}{15}\)
Cbht !!!
\(\frac{40-x}{9}=\frac{28}{36}\)
=> \(\frac{40-x}{9}=\frac{7}{9}\)
\(=>40-x=7\)
\(x=40-7\)
\(x=33\). Vậy x=33
mk khẳng định chắc chắn là 33
40-X=28
X = 40 - 28
X = 12