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Bài 10:
a) (1/3)n = 1/81
=> (1/3)n = (1/3)4
=> n = 4
b) -512/343 = (-8/7)n
=> (-8/7)3 = (-8/7)n
=> 3 = n (hay n = 3)
c) (-3/4)n = 81/256
=> (-3/4)n = (-3/4)4
=> n = 4
d) 64/(-2)n = (-2)3
=> 64/(-2)n = -8
=> (-2)n = -8
=> (-2)n = (-2)3
=> n = 3
Bài 11: (không có y để tìm nhé)
a) (0,4x - 1,3)2 = 5,29
=> (0,4x - 1,3)2 = (2,3)2
=> 0,4x - 1,3 = 2,3
=> 0,4x = 3,6
=> x = 9
b) (3/5 - 2/3x)3 = -64/125
=> (3/5 - 2/3x)3 = (-4/5)3
=> 3/5 - 2/3x = -4/5
=> 2/3x = 7/5
=> x = 21/10
\(a,n^2=\frac{1}{16}\)
\(n^2=\left(\frac{1}{4}\right)^2\)
\(n=\left|\frac{1}{4}\right|\)
=>\(n=\frac{1}{4}\)hoặc \(n=-\frac{1}{4}\)
\(b,n^3.n^2=\frac{32}{243}\)
\(n^5=\frac{32}{243}\)
\(n^5=\left(\frac{2}{3}\right)^5\)
\(n=\frac{2}{3}\)
\(c,\left(x^2\right)^2=\frac{81}{16}\)
\(x^4=\left(\frac{3}{2}\right)^4\)
=>\(x=\left|\frac{3}{2}\right|\)
\(x=\frac{3}{2}\)hoặc \(x=-\frac{3}{2}\)
1, 32 < 2^n < 128
2^5 < 2^n < 2^7
=> 5 < n < 7
Vì n là nguyên dương => n = 6
2, 2.16 > (=) 2^n > 4
2.2^4 > (=) 2^n > 2^2
2^5 > (=) 2^n > 2^2
5 >(=) n > 2 => n = 5 ; 4 ; 3
3, 9.27 < 3^n <= 243
3^2 . 3^3 < 3^n <= 3^5
3^5 < 3^n <=5
5 < n <= 5 ( không có n)
a)
\(\Rightarrow3^{-2}.\left(3^3\right)^n=3^n\)
\(\Rightarrow3^{-2}.3^{3n}=3^n\)
\(\Rightarrow3^{3n-2}=3^n\)
\(\Rightarrow3n-2=n\)
\(\Rightarrow n=1\)
b)
\(\Rightarrow3^{4+n-2}=3^7\)
\(\Rightarrow x^{n+2}=3^7\)
\(\Rightarrow n+2=7\)
\(\Rightarrow n=5\)
c)
\(\Rightarrow2^n\left(\frac{1}{2}+4\right)=9.2^5\)
\(\Rightarrow2^n.4,5=9.2^5\)
\(\Rightarrow2^n=2.2^5\)
\(\Rightarrow2^n=2^6\)
\(\Rightarrow n=6\)
d)
\(\Rightarrow\left(2^5\right)^{-n}.\left(2^4\right)^n=2048\)
\(\Rightarrow2^{n-5n}=2^{11}\)
\(\Rightarrow-4n=11\)
\(\Rightarrow n=-\frac{4}{11}\)
\(\frac{1}{9}.27^n=3^n\)
\(\Rightarrow\frac{3^n}{27^n}=\frac{1}{9}\)
\(\Rightarrow\left(\frac{3}{27}\right)^n=\frac{1}{9}\)
\(\Rightarrow\left(\frac{1}{9}\right)^n=\frac{1}{9}\)
\(\Rightarrow n=1\)
\(32< 2^n< 128\)
\(\Rightarrow2^5< 2^n< 2^7\)
\(\Rightarrow5< n< 7\)
mà n nguyên dương
\(\Rightarrow n=6\)
1 .32 < 2^n < 128
=>2^5< 2^n < 2^7
=>n=6 ( n là số nguyên dương)
3. 9.27≤3 ^n ≤243
=>3^2*3^3≤3^n≤3^5
=>3^5≤3^n≤3^5
Dấu bằng xẩy ra khi n=5 (n là số nguyên dương)
a) \(\left(-\frac{1}{2}\right)^n=\frac{1}{64}\)
\(\left(-\frac{1}{2}\right)^n=\left(\frac{1}{2}\right)^6\)
\(\left(-\frac{1}{2}\right)^n=\left(-\frac{1}{2}\right)^6\)
\(\Rightarrow n=6\)
b) \(\frac{2^n}{32}=2\)
\(2^n=2.32\)
\(2^n=64\)
\(2^n=2^6\)
\(\Rightarrow n=6\)
c) \(\left(-3\right)^3.\left(-3\right)^n=-243\)
\(\left(-3\right)^{3+n}=\left(-3\right)^5\)
\(\Rightarrow3+n=5\)
\(n=5-3\)
\(n=2\)
a, ( - 1/2)n = (1/2)6
n = 6
2n = 2 . 32 = 64
2n = 26
n = 6
(-3)3 . (-3)n = (-3)5
(-3)n = (-3)2
n = 2