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\(\left\{{}\begin{matrix}2x+3y=m\\25x-3y=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2x-m=3y\\25x-3y=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=\frac{m-2x}{3}\\25x+3x-m=3\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=\frac{3-2x}{3}\\27x=3+m\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\frac{3+m}{27}\\y=\frac{m-\frac{6+2m}{27}}{3}=\frac{27m-6-2m}{81}\end{matrix}\right.\)
Mà: \(x>0;y< 0\Rightarrow\left\{{}\begin{matrix}\frac{3+m}{27}>0\\\frac{25m-6}{81}< 0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}m>-3\\m< \frac{6}{25}\end{matrix}\right.\)
\(\Rightarrow m\in\left\{-3;\frac{6}{25}\right\}\)
\(\Rightarrow\left\{{}\begin{matrix}27x=m+3\\25x-3y=3\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=\frac{m+3}{27}\\y=\frac{25x-3}{3}=\frac{25m-6}{81}\end{matrix}\right.\)
\(\left\{{}\begin{matrix}x>0\\y< 0\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}\frac{m+3}{27}>0\\\frac{25m-6}{81}< 0\end{matrix}\right.\) \(\Rightarrow-3< m< \frac{6}{25}\)
x=\(\dfrac{m-3y}{2}\)
=> \(25.\dfrac{m-3y}{2}-3y=3\)
=> 25(m-3y)-6y=6
=> 25m-75y-6y-6=0
=>25m-81y-6=0
=>25m-6=81y
=>y=\(\dfrac{25m-6}{81}\)
=>x=\(\dfrac{m-1}{27}\)
voi x>0 thi \(\dfrac{m-1}{27}>0\)
=> m-1>0
=> m>1
voi y<0 thi \(\dfrac{25m-6}{81}< 0\)
=> 25m-6<0
=> m<6/25