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Bài 1 :
A + B = 4x2 - 5xy + 3y2 + 3x2 + 2xy - y2
= ( 4x2 + 3x2 ) - ( 5xy - 2xy ) + ( 3y2 - y2 )
= 7x2 - 3xy + 2y2
A - B = 4x2 - 5xy + 3y2 - ( 3x2 + 2xy - y2 )
= 4x2 - 5xy + 3y2 - 3x2 - 2xy + y2
= ( 4x2 - 3x2 ) - ( 5xy + 2xy ) + ( 3y2 + y2 )
= x2 - 7xy + 4y2
Bài 2 :
a) M + (5x2 - 2xy) = 6x2 + 9xy - y2
M = 6x2 + 9xy - y2 - (5x2 - 2xy)
M = 6x2 + 9xy - y2 - 5x2 + 2xy
M = ( 6x2 - 5x2 ) + ( 9xy + 2xy ) - y2
M = x2 + 11xy - y2
Vậy M = x2 + 11xy - y2
b) (3xy - 4y2) - N = x2 - 7xy + 8y2
N = 3xy - 4y2 - x2 - 7xy + 8y2
N = ( 3xy - 7xy ) - ( 4y2 - 8y2 ) - x2
N = -4xy + 4y2 - x2
Vậy N = -4xy + 4y2 - x2
3, Cho đa thức
A(x)+B(x) = (3x4-\(\dfrac{3}{4}\)x3+2x2-3)+(8x4+\(\dfrac{1}{5}\)x3-9x+\(\dfrac{2}{5}\))
= 3x4-\(\dfrac{3}{4}\)x3+2x2-3+8x4+\(\dfrac{1}{5}\)x3-9x+\(\dfrac{2}{5}\)
= (3x4+8x4)+(-3/4x3+1/5x3)+(-3+2/5)+2x2-9x
= 11x4 -0.55x3-2.6+2x2-9x
A(x)-B(x)=(3x4-\(\dfrac{3}{4}\)x3+2x2-3)-(8x4+\(\dfrac{1}{5}\)x3-9x+\(\dfrac{2}{5}\))
= 3x4-\(\dfrac{3}{4}\)x3+2x2-3-8x4-\(\dfrac{1}{5}\)x3+9x-\(\dfrac{2}{5}\)
= (3x4-8x4)+(-3/4x3-1/5x3)+(-3-2/5)+2x2+9x
= -5x4-0.95x3-3.4+2x2+9x
B(x)-A(x)=(8x4+\(\dfrac{1}{5}\)x3-9x+\(\dfrac{2}{5}\))-(3x4-\(\dfrac{3}{4}\)x3+2x2-3)
=8x4+\(\dfrac{1}{5}\)x3-9x+\(\dfrac{2}{5}\)-3x4+\(\dfrac{3}{4}\)x3-2x2+3
=(8x4-3x4)+(1/5x3+3/4x3)+(2/5+3)-9x-2x2
= 5x4+0.95x3+2.6-9x-2x2
1) (3x+2)-(x-1) = 4(x+1)
3x+2-x-1 =4x+4
(3x-x)+2-1 =4x+4
2x+1 =4x+4
2x-4x =1-4
- 2x =-3
x=\(\dfrac{-3}{-2}=\dfrac{3}{2}\)
Bài 26:
\(A+B+C=4x^2-5xy+3y^2+3x^2+2xy+y^2-x^2+3xy+2y^2\)
\(=\left(4x^2+3x^2-x^2\right)+\left(-5xy+2xy+3xy\right)+\left(3y^2+y^2+2y^2\right)\)
\(=6x^2+6y^2\)
\(B-C-A=\left(3x^2+2xy+y^2\right)-\left(-x^2+3xy+2y^2\right)-\left(4x^2-5xy+3y^2\right)\)
\(=3x^2+2xy+y^2+x^2-3xy-2y^2-4x^2+5xy-3y^2\)
\(=\left(3x^2-4x^2+x^2\right)+\left(2xy-3xy+5xy\right)+\left(y^2-2y^2-3y^2\right)\)
\(=-4xy-2y^2\)
\(C-A-B=\left(-x^2+3xy+2y^2\right)-\left(4x^2-5xy+3y^2\right)-\left(3x^2+2xy+y^2\right)\)
\(=-x^2+3xy+2y^2-4x^2+5xy-3y^2-3x^2-2xy-y^2\)
\(=\left(-x^2-4x^2-3x^2\right)+\left(3xy+5xy-2xy\right)+\left(2y^2-3y^2-y^2\right)\)
\(=-8x^2+6xy-2y^2\)
cái câu B-C-A ý thì kết quả phải là 4xy-4y^2 chứ
vì: 2xy-3xy+5xy =4 xy
y^2 - 2y^2-3y^2 = -4y^2
=> = 4xy-4y^2
a, A=\(\left(2x^2y-4xy^3\right)-\left(3x^2y-2xy^3\right)\)
= \(2x^2y-2xy^3-3x^2y+2xy^3\)
= \(2x^2y-3x^2y-2xy^3+2xy^3\)
=\(-1x^2y-0\)
=\(-1x^2y\)
Bn tự làm tiếp nhé
1, \(3xy^2+Q=-7xy^2\)
\(\Rightarrow Q=-7xy^2-3xy^2\)
\(\Rightarrow Q=-10xy^2\)
2. \(P=3+5x^2-3xy+5y-5x^2-11+2xy+x^3\)
\(\Rightarrow P=\left(5x^2-5x^2\right)+\left(-3xy+2xy\right)+5y+x^3+\left(3-11\right)\)
\(\Rightarrow P=-xy+5y+x^3-8\)
A+(9x^3+7xy-5y)=12x^3-3y
A=12x^3-3y-(9x^3+7xy-5y)
A=12x^3-3y-9x^3-7xy+5y
A=(12x^3-9x^3)+7xy-(3y-5y)
A=3x^3+7xy+2y
!!! Hok tốt!!!
thank bạn conan